Thanks, I appreciate your step-by-step derivation. I wish you would provide a link in the description to the complete course. I cannot find where lecture 17 is for this series.
@sandeep-ol8yq4 жыл бұрын
kzfaq.info/get/bejne/e895d7aUz5eWZIU.html this is the link of the complete course
@AKSHAYKUMAR-hl2br4 жыл бұрын
Sir.. Will u plzz..provide some more topics of optical engineering..that will be really helpful
@alexbraun88756 ай бұрын
am just curious... Are these scalar differential equations? ie are the complex amplitudes E1 and E2 also vectors? Also, is it implied that there are complex conjugates to be included in the differential equations? Thanks for the great lecture. Will it be possible to take formally in the near future?Alex
@kanchansaikia88355 жыл бұрын
Nice
@dsjgfhidupgjret Жыл бұрын
Around 18:05 , I don't get how the limit of sinc^2(dkz/2) becomes z^2, neither the equation, nor the verbal explanation.
@jacobvandijk652511 ай бұрын
This (17:44) is not a sinc-function because there is no z in the denominator! The prof is mistaken. It is a sine-function squared. Around 0 this function looks like a parabola: y = z^2
@midhunbenny89755 жыл бұрын
how (dw/n1)the square comes in the expression for p2??? actually it is (dw/n2) square na????beacause no where in the derivation n1 comes!!!!