The puzzle is not clear at all. I can measure 40 liters with a 1 liter jar, picking up the milk 40 times.

There's a missing constraint to the problem: You can only dip each jar once in the container

I think the minimum amount of jars is one, we need a 1 litre jar and we can calculate any amount of milk😂😂

I like your videos, but in this case u didnt mention that I can not use same jar twice, so in that case only one, one liter jar is enough.

Some ordered 765ml milk Shop owner- Sorry, KZfaq did not teach me tat

Why cant we use a jar twice.....there is no such restriction mentioned in the video

I can do 1-40ltrs with only 2 cups. One 40 ltr jar and one 1 ltr jar. 1. Fill the 40 ltr jar and pour 1ltr from the 40 ltr jar into the 1 ltr jar (this will give u 39 ltrs) 2. Repeat step 1 (fill the 40 ltr jar, pour 1ltr from the 40 ltr jar into the 1ltr jar and pour the 1ltr into the bucket this will give u 38 ltrs) You can get every liter using this technique.

Only one litre jar is sufficient

There should be a rules one jar should be used once to pour from the big container to pour milk. Otherwise people will say I will use 1 litre 40 times.

Question is wrong. Right question is a piece of iron weighs 40 kg should divide in 4 parts so that you can measure 1to 40 kg.

You solved it like hit and trail method, and you haven't mentioned that we can only use one jar once, okay give me 2.45 lit

I have heard the same puzzle but the only difference was that it was about finding only 4 weighing blocks to be made out of 40 kg iron block that could measure all 1-40 kg weights ( natural nos.) in one step only. It would give no confusion.

I only needed two jars, I took a 40L and a 1L and filled the 40L 1L at a time marking each spot....man that was easy.

Easier option would be 1 ltr, 2 ltr, 5 ltr & 10 ltr jar. You can take out any quantity from 1 ltr to 40 ltr just by filling any of these jars 1 to max 4 times. No need of pouring back (subtracting) the extra quantity from bigger to smaller jar and then again from smaller jar to main tub. Lots of time and efforts saved.

I think there is a deeper reason for the powers of 3. We can take inspiration from how binary numbers work. In that case, for any integer N, a 2^0 + b 2^1 + c 2^2 + ... = N where {a,b,c,...} can only be 0 or 1. In our case, for any integer N, a r^0 + b r^1 + c r^2 + ... = N where {a,b,c,...} can be 0, 1 or -1. "0" : A jug is not used. "1" : A jug is used to fill milk from container. "-1": A jug is used to remove milk from some other jug. Simple linear algebra gives us r=3.

After watching video, I think that I've become logical but when you'll post another puzzle, then no logic works.

Not enough constraints on this puzzle. We could use only 2 jars by having -1 jar with 1 litre -1 jar with 39 litres and just keep filling up the small jar and using it to fill up the large jar. If the constraint was to minimize the size of the largest jar, we could have 11, 10, 10, 9 -For a number from 0-8, fill up 11-litre jar, pour from that jar into a 10-litre jar till its filled up, dump contents of that 10-litre jar into the tub. Move the 1 litre of milk in the 11-litre jar into the 9-litre jar. Rinse and repeat till your 9-litre jar has the desired amount. -For a number from 9-11, you can just fill up one of the jars. -For a number X from 12-18, fill up 9-litre with X - 9 litres using first technique, move into 11-litre jar. Fill up 9-litre jar. -For 19 fill up 10 & 9, for 20 fill up 10 & 10, for 21 fill up 11 & 10 -For a number X from 22-28, fill up 9 litre with X - 19 litres using first technique, move into 11-litre jar. Fill up 9 & 10 litre jars. -For 29, fill up 10,10,9, for 30 fill up 11,10,9, for 31 fill 11,10,10 -For a number X from 32-38, fill up 9 litre with X-29 litres using first technique, move into 11-litre jar. Fill up 9,10,10 litre jars. -For 39, fill up 10 litre-jar, pour into 11 litre jar, fill up 9,10,10 litre jars. -For 40, fill up all the jars Some other possible constraints to make variants of this puzzle: -Can only fill up 1 jar at the start -No dumping milk back into the tub. -Can only pour from a larger jar to a smaller jar -Can only pour into an empty jar(in other words, no mixing of milk in jars) -Jars of size N cost F(N), minimize cost of jars -There must be a unique solution for every possible quantity -Minimize number of moves -The sum of all jars must be the target quantity, (no cherry-picking) Perhaps the constraint that would make the solution presented be the only one could be, only allowing pouring from a larger jar to a smaller jar(with the tub of milk being the largest jar) Still a nice puzzle and solution though.

amazing yaar.....really too good......waiting for more puzzles.

1,2,5,10 (and 40 which is the main jar) is enough. That is why money system is built like that.

thanks man to make such logical videos for us

Why other than one litre jar is required?

Just a 1L and a 40L jar should suffice...

we can also keep 4 jars capacities in this manner, 1l, 3l, 5l and 11l u can measure all from 1L to 40L milk iam 100% sure for this answer is also correct just u can try for all 1L to 40L if u are not getting any x no. of litre then comment me, i will sure give solution u just need to try for all 1L -40L😀😀

Yes there is a issue in the constraint in tuhsi one , but u doing a good job keep going

Would be more fun if you asked what is the maximum integer number of liters that you can measure using 4 jars. By the way, I got it with 7, 9, 10 and 14.

1:13 how about if it is 5.5 ltr

40l and 1l, no need for the others but you can have others to give you means to get to your desired amount more quickly.

How should i increase my logic thinking sir...i do programming where logical thinking is crucial...please guide me on how should i improve my logical thinking??

You can do the same with just three jars, 1, 2 and 5 liters: the fourth jar could be anything betweeen 0.x and 40 liters, but it really doesn’t matter since you can make all numbers from 1 to 10 with the other three.

U didn't say that u cannot use a jar twice. So what will u do when u want to get 7 literes.

Best xplanation Bt u mentioned in the video that all are the powers of 3 Nd how can it be a logic fr the question

Isn't it also possible to measure any amount 1-40 with a 1 liter jar and a 40 liter jar, by repeatedly pouring the 1 liter jar of milk into the 40 liter jar, as many times to get to how much you need?

it's 1 3 5 10 ltr for me because people would carry their own jar to buy milk (well du'h who would buy liquid without having some kind of container either from the seller or the buyer) and also 1 3 5 can cover from 1 to 9 easily therefore most of the world currency is 1 2 5 and 10 (i choose 3 ltr because it's better for this kind of problem)

Need more info. There is no restriction from using the same jar more than once. A 1 liter could be used 40 times to get 40 liters.

But the jars like 2,3,5 and 10 will also work for the question.Is that right?

It lack constraints. My answer would be one 20 liters of jar because that'd be much easier than 1 liter to any amount because I can assume that my 20 litter jar has measurements. Why four when you can use one? Aren't riddles supposed to be thought out of the box?

U should have explained the question better

We can also use containers having volumes 1ltr, 5ltrs, 10ltrs and 20ltrs.

I think an 1L and a 38L jar is enough.. if anyone asks for 40L give the one the whole container of milk, apart from that if someone asks for 39, fill both the jars and give else if someone asks for 2L pour 1L jar twice in the container and put the milk in 38L jar

What if someone needs 1L + 250ml? The question is very vague so we can't know for sure. Also, 5 can be given as 3 + (3-1) 6 as 3+3 7 as 3+3+1 8 as 3+3+(3-1) 9 as 3+3+3 10 as 9+1 11 as 9+(3-1)... Maybe it is efficiency related...

If i were there all of jars i use 10 litres This is so complicated explanation for those people who can not understand it even watching for more times also so pls ask some easy riddles and also very tough riddles Bcoz of tough riddles, few people think that they dont have so much iq to solve them They lose themselves Although this is easy to me.....

If you had a 1 liter jug and a 40 liter jug, then you could pour any integer amount of milk into the fourty liter jug using the 1 liter jug like a measuring cup

Great video

Solution is cumbersome. For purely additive measures, use 1 2 4 8. This business of adding and then deducting is not optimal

What if a customer asks 1.5 liter milk?

Can we use the combination of 1, 2, 5, and 10 liters jar?

awesome

But to give any amount of milk in integer multiple of 1 ltr, we only need a one ltr. Moreover 1,2,2,5 is also a standard measure. That's also possible...

Another solution using BINARY : Have Jars of 1,2,4,8 This is much more elegant

1, 2, 5 and 10 are enough to measure any litres.

Actually one thing Is missing in the question that is each jar is allowed to use once for each required quantity demanded

How much would largest container weigh? Could anyone lift it when it is full?

1 dislike for incomplete information and then, pr denting yourself as superior.

Oh man, where do I start, firstly I really like the channel so well done. Secondly, I’m not trying to hit on your solution but I think this one has more solutions than one... and dare I say it more optimal solutions, or alternatively this puzzle could have actually been more difficult than 40 ltrs. If you start with a simple example of 2,3,11,28 you can still make all the numbers but you can also make up to 44 ltrs. Some numbers are harder, for example to make 7 you need to pour 11 into 2, then pour 2 back into 3, then pour from 11 into 2 again to remove 4 in total from 11 but you do end up with a single container with 7 left, fair? To make some numbers between you need to sometimes pour milk back into the main container, or use a container twice, but it isn’t detailed in the puzzle or against the rules? Like to make 4 you would have to pour 11 into 2 and also 3 which leaves 6, pour 2 back into main container, pour 6 into 2, 4 remains. Or you could pour 11 into 3 and the 3 back into the main for 8 and then pour into 2 and back into the main for 6 and repeat again for 4. Since this is a logic puzzle and you wouldn’t waste any milk there are now more possibilities with a more advanced strategy. To the creator, let me know what you think of this answer? Some of your puzzles are a lot harder, I love logic puzzles so I thought I’d push this one a bit further!

Hey Ammar, funny problem, especially you did not perfectly clear all the requirements, cause that gives one the possibility to think out of the box. So I gave it a try in a different way: 1) I am a shop owner that sells milk 2) my customers buy milk in the range of 1 to 40 l in integer amounts, and they don‘t bring their own container 3) as the shop owner, I have to buy containers and give them to the customers to take home. For simplicity, I have a contract with my container supplier, so the cost is equal for every container, no matter what capacity. So I‘m interested in selling my milk with a minimum amount of containers, range 1-4 4) I think your solution gives the best possibility for me as the shop owner to save money, because if you handout up to 40 containers, that will ruin my business 😅 Finally, you can make two modified riddles out of this: I have 40 customers,each wanting to buy a different integer amount between 1 and 40 l, so a total of 41*20=820 l (thanks to C.F. Gauss 🙂) A) What are the minimum costs I have to pay to my container supplier, assuming it‘s 100 rupees each, no matter what the size of the container is? B) What are the minimum costs, assuming that a container costs 10 rupees per liter of capacity I didn‘t do the math yet completely, maybe you and your viewers like to give it a try, cheers from Hamburg, Juergen

It is better to have 1,2,3,5 litres of jar

i think 2 liter, 3 liter, 4 liter, and 31 liter will also work please check if it is right?

Super g

🙌

By measure it is meant, one needs to store it somewhere as well. Not just measure 1 litre and throw.

Just get a 1 ltr and a 6783246109235 ltr If a guy wants n ltr of milk, fill up the 1 ltr jar and pour it into the other jar, then repeat for n times.

Congrats on 100k subscribers

If the buyer comes with his own container there are plenty of 4 jars combinations. One set of 4, without pen on paper, would be 10 - 4 - 3 - 2, but, as I said, can be plenty of others

This puzzle is NOT well specified for two reasons. 1. the range of 1 to 40 includes fractions. the puzzle should have specified no fractions. 2. the puzzle wants the desired amount of milk to end up in its containers. That was not specified at the start. Like bottled water in the USA, maybe the customers all bring their own milk containers. then you only need a single 1 liter measure to give them from 1 to any number of liters. maybe the customer will drink the milk there. then you only need a single 1 liter measure. the puzzle only asks you to measure N liters. It does not say what happens after you measure. you could pour the milk on the ground but still you still would have measured N liters.

There's a much easier way to solve this. You have a 1 liter jar and a 40 liter jar. The other two jars don't matter. And you just use the 1 liter jar to measure into the 40 liter jar until you get the exact number of liters you need. Or if we can pour directly into the jar of the person purchasing our milk, we only need the 1 liter jar.

You didn't mention whether we can use a jar twice or not.

There's a parameter missing. 1 1lr jug would be adequate for what we were asked.

hii if customer want 20 liters milk how will you give???

What if we measure 39.45 litres

Hey you didn't explained why was it powers of three only and where else this concept can be applied

Excellent explanation. I like your videos. To measure 7 litres of milk , It's correct to take 9 litres milk out of the tank and then take out 3 litres milk from 9 litres jar. At last we have to take out 1 litre milk out from 3 litre jar and then put 1 litre milk inside the 9 litre jar from 1 litre jar. Is it correct??

Just have a single jar of 1L. Why do you need 4 jars when you can do the same job for with a 1L jar?

What is the reason behind 3^n please?

Ruko me 50 ltr ki tanki lekar aata hu, aaj sabme doodh batega.

Even the jars with the capacity of 1, 2 , 4, 8 litres will serve the purpose. Mr. Mohammad Ammar, let me know if it is correct.

thts a pretty good one but.... u did it on basis of substraction what about addition having 1 3 5 10 ltrs of jar 1+1=2 a 3 ltr jar gives 3+1=4 5 would give 5 5+1=6. 5+1+1+=7 5+3=8. 5+3+1=9 and a 10 and so on ......u just show us things in a difficult way ......still i m ur supporter though

This is also possible I guess :- 7l 9l 11l and 13l

Its very easy... Let Jars is named as A B C D We assumed as Jar A is 10 liter.. Jar B is 5 liter.... Jar C is 2 liter.... Jar D is 1 liter.... According to the question, If customer wants 1 liter of milk. We use jar D=1 liter... If customer wants 2 liter of milk we use jar C=2 liter... If customer wants 3 liter of milk we use Jar C+D= 2+1= 3 liter.... If customer wants 4 liter of milk we use Jar C+C= 2+2=4 liter.... If customer wants 5 liter of milk we use Jar B= 5 liter..... If customer wants 6 liter of milk we use Jar B+D=5+1=6 liter.... And so on........! I if u understand......!

1,2,5,10 are sufficient. Currency is also printed like this.it's the same

I think this is not full question. Because certain conditions should be mentioned with it Such as 1) A jar should used only once to take out milk from bucket. 2) We have to take jars quantity which totals to Amount i.e 40 (as we can't use same jar twice) And of course quantity should be natural number!!!

This puzzle has been asked very very poorly. Without specifying the constraints, you could just have a Jar of 1 liter

For 1.5 ltr ...or 1.2 ltr..or something else value.???

1ml jar and I don't need other three jars , because one can even demand 1.29 litres

Well it doesn't matter if your smart and can just reuse the 1 bottle. I swear you never clarified that.

Can't we just use 1L jar n number of times to take n L of milk...

what to do for 7L by this process?

Nice video

try 1, 2 ,2 ,5 you can hold any number from 1 to 10 with this if your buyer doesn't have a pot to put milk I used to carry coins in this config so i can give change in any numbers

All u need is a 1 liter jar. 40x 1 liter = 40 liters.

Thought I could use one jar more than once

I heard about this answer but don't know the logic. Thank you for this logical explanation.

Its binary like patterns 8 4 21 for 15 ltr 27 9 3 1 for 40 ltr So on.... Restriction: can't use same jug twice while single measurement. You can use multiple jug at a time for filling and emptying.

There is a better way to ask this question: there is a balance and 4 difference scale weights, and you can use these weights to find 1 g to 40 g of weight. What are the weight's weight?

11.5 , 10.5 , 9.5 , 8.5 would also work 😄...god bless you

Wjat if a person wishes to buy 9.5litres?

1, 2 , 4, 8 is the best jar capacity

very nice problem

1, 2 ,5 , 10 also works.

Can't you use one jug of 1 liter x times? The requirements don't specify how many times you can use one specific jug, or if you need to optimize the number of steps to draw the milk. The question should be formulated in such a way as to allow only one (reasonable) solution.

nice puzzle