In this video, low pass filter is implemented using stub by following Richard's transformation and Kuroda's identities.
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@gokersener28263 жыл бұрын
Thanks. Very helpfull. The previous video too.
@johnatkinson32182 жыл бұрын
I have discovered your channel and really enjoy your tutorials! Thank you very much. I however am having trouble separating the transmission lines properly for a n=5 and greater low pass filter.. Your examples all seem to be n=3, do you have any videos showing this? Thank you!
@tmeireles753 жыл бұрын
thank you very much for the video. I have the same question thank other viewer. Consider the Kuroda conversion from the series stub on the right side at 9:30. Z1 is 1, Z2 is 1 as well, which means n^2 is 2. This means the transmission line is n^2*Z1 which is 2, but the open circuit should be 1/(n^2*Z2) which is 1/2...
@meditationtales58662 жыл бұрын
i was also thinking same
@mindtherapy19892 жыл бұрын
Same
@tejaskamble9962 жыл бұрын
After converting the capacitance value is 1/ (n^2 * Z2), so you can say C = 1/ (n^2 * Z2) but for capacitor the characteristic impedance Zo = 1/ C. Therefore you have to take inverse of 1/ (n^2 * Z2).
@noahlape81873 жыл бұрын
Hello again. I am a little confused on how you are getting L = 1 and C = 2, I can not seem to manipulate the equations in anyway to get those values. I also could not seem to calculate your g values either. I am currently trying to design a filter generator in matlab, that is why I'm asking so many questions.
@kavithasenthilkumar4533 Жыл бұрын
How can a shunt inductor which in case of bandpass filter be change to shunt stub from series
@soumyajitchakraborty97043 жыл бұрын
For maximally flat filters in general , if we are given N=3 in the question directly then we need to go for the next higher integer in the table or we take n=3 itself as provided in the question?
@RFDesignbasics3 жыл бұрын
You should take only n=3.
@melissaquero-gopar94044 жыл бұрын
Why do the inductors turn open circuited? Is it because you used the table? Is it because in the table it says the inductors turn into a box connected in parallel with the resistor. How did you solve the formula for n?
@RFDesignbasics4 жыл бұрын
You can watch this video kzfaq.info/get/bejne/nc5ohZdqqqqVhoE.html. By calculating the input impedance of one of the case you can prove the same.
@sravani4614 жыл бұрын
And don't we need to perform frequency transformation in final values since we started with normalised values with wc = 1
@sravani4614 жыл бұрын
How to calculate wavelengths for each element analytically without using any simulator
@Yoyo-ck9pm3 жыл бұрын
Sir can we use to design filter for order n=4. Does Richard KURODAS can be used for odd order elements only??
@RFDesignbasics3 жыл бұрын
Can be used for even number as well
@Yoyo-ck9pm3 жыл бұрын
@@RFDesignbasics sir can you upload an example how to do
@zhenluo50754 жыл бұрын
Sorry, but I don't quite understand why the wavelength is different on 100 Ohm and 25 Ohm stub? Coud you please explain this?
@RFDesignbasics4 жыл бұрын
Different characteristics impedance leads to different width of stub, eventually leads to different effective dielectric constant. Because effective dielectric constant depends upon width. Wavelength is inversely proportional to square root of effective dielectric constant.
@zhenluo50754 жыл бұрын
@@RFDesignbasics Yes, I recall some of knowledge. when frequency goes high, more fields confined into substrate, which will lead to a higher effective dielectric constanct. Thank you for the explanations, Sir.
@kartikmittal9842 Жыл бұрын
how to find different wavelength for different Zo
@barrathyvagananthan41673 жыл бұрын
Hello can u do for high pass filter
@derekjoel82714 жыл бұрын
In the Kuroda's Identities for series inductor , shouldnt the value of Z for the capacitor shunt be 1 / ( n squared * Zo). ie. Instead of 2 , shouldn't it be 1/2.
@sravani4614 жыл бұрын
But 1/2 is the value of the capacitor in lumped form. When we apply Richards transformation on it, the Zo value of capacitor becomes 1/C i.e. Zo = 2
@egeulucay74912 жыл бұрын
@@sravani461 this answer is gold. ty
@noahlape81873 жыл бұрын
Hello, I am having trouble understanding how to calculate the wavelength as well
@RFDesignbasics3 жыл бұрын
Ask questions clearly
@noahlape81873 жыл бұрын
@@RFDesignbasics okay, so in the video you mention how the lambda (wave length) is dependent on the Z, however, you do not go into detail on how they are related. or how to solve for lambda. I know you mention it is dependent on dielectric constants of the material based on varying widths, but this is vague and for hand computations, confusing. My question is, how would you calculate the wavelength by hand (and therefore the geometry) without the use of simulation soft ware?
@RFDesignbasics3 жыл бұрын
Ok. So the answer is going to be long. The wavelength is ratio of Phase velocity and frequency inside any microstrip line. To calculate phase velocity you need to know the dielectric constant or relative permittivity of the material. In case of microstrip line the relative permittivity combine with air or free space and makes relative effective permittivity or effective dielectric constant which is dependent on h of the substrate and width of the line as well (refer the formula from DM Pozar Microwave Engineering section 3.8). Since Z0 is width dependent of the line, relative dielectric constant also width dependent and hence wavelength too is width dependent. For calculation of all these manually you can refer the same section of Pozar.
@noahlape81873 жыл бұрын
@@RFDesignbasics Going off of this I also found a source that validates this response in "Fundamentals of applied electromagnetics" - Paerson, chapter 2 section 5. Thank you for you speedy and detailed response, I really appreciate your videos!