Low pass filter implementation using stub||Richard's transformation and Kuroda's identities||

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RF Design Basics

RF Design Basics

4 жыл бұрын

In this video, low pass filter is implemented using stub by following Richard's transformation and Kuroda's identities.

Пікірлер: 34
@gokersener2826
@gokersener2826 3 жыл бұрын
Thanks. Very helpfull. The previous video too.
@johnatkinson3218
@johnatkinson3218 2 жыл бұрын
I have discovered your channel and really enjoy your tutorials! Thank you very much. I however am having trouble separating the transmission lines properly for a n=5 and greater low pass filter.. Your examples all seem to be n=3, do you have any videos showing this? Thank you!
@tmeireles75
@tmeireles75 3 жыл бұрын
thank you very much for the video. I have the same question thank other viewer. Consider the Kuroda conversion from the series stub on the right side at 9:30. Z1 is 1, Z2 is 1 as well, which means n^2 is 2. This means the transmission line is n^2*Z1 which is 2, but the open circuit should be 1/(n^2*Z2) which is 1/2...
@meditationtales5866
@meditationtales5866 2 жыл бұрын
i was also thinking same
@mindtherapy1989
@mindtherapy1989 2 жыл бұрын
Same
@tejaskamble996
@tejaskamble996 2 жыл бұрын
After converting the capacitance value is 1/ (n^2 * Z2), so you can say C = 1/ (n^2 * Z2) but for capacitor the characteristic impedance Zo = 1/ C. Therefore you have to take inverse of 1/ (n^2 * Z2).
@noahlape8187
@noahlape8187 3 жыл бұрын
Hello again. I am a little confused on how you are getting L = 1 and C = 2, I can not seem to manipulate the equations in anyway to get those values. I also could not seem to calculate your g values either. I am currently trying to design a filter generator in matlab, that is why I'm asking so many questions.
@kavithasenthilkumar4533
@kavithasenthilkumar4533 Жыл бұрын
How can a shunt inductor which in case of bandpass filter be change to shunt stub from series
@soumyajitchakraborty9704
@soumyajitchakraborty9704 3 жыл бұрын
For maximally flat filters in general , if we are given N=3 in the question directly then we need to go for the next higher integer in the table or we take n=3 itself as provided in the question?
@RFDesignbasics
@RFDesignbasics 3 жыл бұрын
You should take only n=3.
@melissaquero-gopar9404
@melissaquero-gopar9404 4 жыл бұрын
Why do the inductors turn open circuited? Is it because you used the table? Is it because in the table it says the inductors turn into a box connected in parallel with the resistor. How did you solve the formula for n?
@RFDesignbasics
@RFDesignbasics 4 жыл бұрын
You can watch this video kzfaq.info/get/bejne/nc5ohZdqqqqVhoE.html. By calculating the input impedance of one of the case you can prove the same.
@sravani461
@sravani461 4 жыл бұрын
And don't we need to perform frequency transformation in final values since we started with normalised values with wc = 1
@sravani461
@sravani461 4 жыл бұрын
How to calculate wavelengths for each element analytically without using any simulator
@Yoyo-ck9pm
@Yoyo-ck9pm 3 жыл бұрын
Sir can we use to design filter for order n=4. Does Richard KURODAS can be used for odd order elements only??
@RFDesignbasics
@RFDesignbasics 3 жыл бұрын
Can be used for even number as well
@Yoyo-ck9pm
@Yoyo-ck9pm 3 жыл бұрын
@@RFDesignbasics sir can you upload an example how to do
@zhenluo5075
@zhenluo5075 4 жыл бұрын
Sorry, but I don't quite understand why the wavelength is different on 100 Ohm and 25 Ohm stub? Coud you please explain this?
@RFDesignbasics
@RFDesignbasics 4 жыл бұрын
Different characteristics impedance leads to different width of stub, eventually leads to different effective dielectric constant. Because effective dielectric constant depends upon width. Wavelength is inversely proportional to square root of effective dielectric constant.
@zhenluo5075
@zhenluo5075 4 жыл бұрын
@@RFDesignbasics Yes, I recall some of knowledge. when frequency goes high, more fields confined into substrate, which will lead to a higher effective dielectric constanct. Thank you for the explanations, Sir.
@kartikmittal9842
@kartikmittal9842 Жыл бұрын
how to find different wavelength for different Zo
@barrathyvagananthan4167
@barrathyvagananthan4167 3 жыл бұрын
Hello can u do for high pass filter
@derekjoel8271
@derekjoel8271 4 жыл бұрын
In the Kuroda's Identities for series inductor , shouldnt the value of Z for the capacitor shunt be 1 / ( n squared * Zo). ie. Instead of 2 , shouldn't it be 1/2.
@sravani461
@sravani461 4 жыл бұрын
But 1/2 is the value of the capacitor in lumped form. When we apply Richards transformation on it, the Zo value of capacitor becomes 1/C i.e. Zo = 2
@egeulucay7491
@egeulucay7491 2 жыл бұрын
@@sravani461 this answer is gold. ty
@noahlape8187
@noahlape8187 3 жыл бұрын
Hello, I am having trouble understanding how to calculate the wavelength as well
@RFDesignbasics
@RFDesignbasics 3 жыл бұрын
Ask questions clearly
@noahlape8187
@noahlape8187 3 жыл бұрын
@@RFDesignbasics okay, so in the video you mention how the lambda (wave length) is dependent on the Z, however, you do not go into detail on how they are related. or how to solve for lambda. I know you mention it is dependent on dielectric constants of the material based on varying widths, but this is vague and for hand computations, confusing. My question is, how would you calculate the wavelength by hand (and therefore the geometry) without the use of simulation soft ware?
@RFDesignbasics
@RFDesignbasics 3 жыл бұрын
Ok. So the answer is going to be long. The wavelength is ratio of Phase velocity and frequency inside any microstrip line. To calculate phase velocity you need to know the dielectric constant or relative permittivity of the material. In case of microstrip line the relative permittivity combine with air or free space and makes relative effective permittivity or effective dielectric constant which is dependent on h of the substrate and width of the line as well (refer the formula from DM Pozar Microwave Engineering section 3.8). Since Z0 is width dependent of the line, relative dielectric constant also width dependent and hence wavelength too is width dependent. For calculation of all these manually you can refer the same section of Pozar.
@noahlape8187
@noahlape8187 3 жыл бұрын
@@RFDesignbasics Going off of this I also found a source that validates this response in "Fundamentals of applied electromagnetics" - Paerson, chapter 2 section 5. Thank you for you speedy and detailed response, I really appreciate your videos!
@RFDesignbasics
@RFDesignbasics 3 жыл бұрын
Thank you. You are welcome 🙂
@mustaphaalkhafaaf5512
@mustaphaalkhafaaf5512 3 жыл бұрын
sorry why lambda/8 ??? why 8 ??
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