For problem 1 you can also do 1.107/13=8.2~8 which is our number of carbons 2. 107-13(8)=3 3+8=11 which is the number of Hydrogens so we Have C8H11. 4. From the nitrogen rule we know there has to be a nitrogen since we have an odd m/z 5. 1 CH2 = N..so then we have C8H11 - CH2 = C7H9N as our answer
@isobelspio64735 ай бұрын
Hi what of the second one
@isobelspio64735 ай бұрын
Hi what of the second one
@SM-gc2tx7 ай бұрын
in my class, we call the peak with a relative intensity of 100% the "base peak," which indicates the molecular weight of the most stable carbocation. the" m peak" is the peak furthest to the right, indicating the molecular weight of the parent compound
@keziahbrutus2 жыл бұрын
Thank you soo much señorita this was a great help 💐💐💐💐
@catcatdogdog012 жыл бұрын
it helps a lot, thank you for the detailed explanation
@tamernicola25592 ай бұрын
this was very helpful thank you🐱
@clementkandota1695 ай бұрын
thank you very much, that was very helpful.
@fakhrulnawawi96812 жыл бұрын
Where 1.1% came from?
@Neha8s3 ай бұрын
Natural abundance of C-13 NMR is 1.1% and C-13 is NMR active
@tayyba14913 ай бұрын
Thank alott ❤❤❤
@AbuBakar-wx5kk2 жыл бұрын
good good good
@bawag37242 жыл бұрын
Chup oy
@AbuBakar-wx5kk2 жыл бұрын
what happened sister?
@bawag37242 жыл бұрын
@@AbuBakar-wx5kk baaz aa ja tu
@sudhikutta Жыл бұрын
Good explanation.
@user-px8nv3bu9d2 жыл бұрын
Very helpful, thanks
@user-rh7bd9wr4i4 ай бұрын
For problem 1 apply rule of 13 within 1 step u got ans😅
@pathumsanjeewa77782 жыл бұрын
Thank you 😊
@sumitradas242 жыл бұрын
Thanks
@vav58383 жыл бұрын
super helpful, thank you!
@krish_krish3543 жыл бұрын
How to see and calculate the relative abundance more than 100 scale.
@Ahmed7Mamoon3 жыл бұрын
Thanks 😊
@isobelspio64735 ай бұрын
Please where did you get the 1.1% from
@Neha8s3 ай бұрын
Because natural abundance of C-13 carbon atom is 1.1% that C-13 is NMR active