Hello Sir I am a GREAT fan of you and your teaching styles.Your videos are truly a blessing for.

thanks soo much i have finally come to grips with momentum

Thank you Dr P.You videos really helped me how to calculate momentum.

Your videos are really a blessing!

Thank you very much your effort! Keep up the good work!! :)

It is the most helpful vedio that I have watched so far ,thank you.

Thank you sir. I really appreciate your help. Thanks for all the videos that you make as it helps alot of people out. Once again thanks alot 😃 📚 📚

This was extremely helpful, thank you so much!

got nearly full marks in all my physics exams looking forward to a levels great teaching

It was really helpfull...especially when ur scl tcher speaks whale in class thank u so much

I LOVE your videos :')

You are great 👍 and you can explain very well .

Awesome video

You've made my life easier!!! ;-)

Amazing, very helpful cheers

thanks u hv helped me but sir how is the principle f conservation of linear momentum linked to newton third law of motion?

cheers... really helped mate :)

with regard to the momentum of a photon the energy of a photon is not defined by its mass or velocity but rather by its frequency shows by E=hf where h is plancks constant. for particles with momentum the equations E^2=(pc)^2 + (mc^2)^2 therefore for a massless particle like a photon momentum is E=pc where pc=(E^2-m^2c^4)^0.5 there's also a lot of information on this online so research is a good idea to get a full understanding of this.

What about relative velocity of approach and separation ?

Thank you! I only thought you did high level stuff but i just decided to check this out, now i can watch some of your videos to relieve myself of pressure for next year, i'm confident about most of my subjects but now i can watch some of your videos, revise them, and hopefully feel much better about going into my physics course next year 😁👍

cool vid

I've seen +ve and -ve used in chemistry when referring to electrolysis.

I thought that p=mv divided by (1-v^2 over c^2)^.5 where c is the speed of light. is this true or for gcse is the denominator omitted?

At the example in 15:45 you are assuming that the trolley is decelerating but what if it was accelerating then what would we do to the formula to decrease the force

Does this mean that if we had two objects of masses 1 and 2 kilograms respectively and the object with 1 kilogram was travelling at 2 m/s whereas the object of mass 2 kilograms was travelling at 1 m/s, they would produce the same effect if they hit my hand ? In other words will I feel the same ?

If you could make a video on GCSE transformer it would be really good

At the example in 22:06 there is a mistake as the force applied is in N but the answer is in KG so you need to change N to KG before you answer so the answer you got is not 16 kg m/s it is 16 N m/s so you need to divide by 10 so the answer is 1.6 kg m/s right? If I am wrong please enlighten me THANK YOU

How is it that a photon can have momentum since photons are massless and according to p=mv, momentum can only exist with mass.

😍😍😍😍

is momentum a part of IGCSE too?

Hi Dr.Mosher

14:00 nice car bro.............

f = (mass x velocity)/time

Is this GCSE or A'Level Physics?

nevertheless the equation is not fully stated even at a level you rarely consider relativistic situations and even then you use the incomplete equation. both the gcse and a level are poor preparation for any potential degree students

Science is good