Sir, you explained very beautifully. that show how great person you are. I really appreciate you taking time off from your busy life and teaching us these complex ideas and explaining them so easily. that even a dumb guy like me can understand. Bundle of Thanks.
@yoprofmatt6 жыл бұрын
You're very welcome. Thanks for commenting, and keep up with the physics (or maybe the boxing as your username suggests?). Cheers, Dr. A
@TheKraetos8 жыл бұрын
You are a wonderful human being that the world is lucky to have. I wish you were my professor. *sigh*
@yoprofmatt8 жыл бұрын
+Kraetos John Now this comment makes me feel very loved. Thanks very much. Cheers, Dr. A
@adnanhaider46237 жыл бұрын
I just can't believe, how talented teachers are there in this world. You made me your fan.
@n95834 жыл бұрын
I’m a young guy and Im a big fan of astrophysics I loveeee videos about rockets and space thank you so much for this video🙂
@yoprofmatt4 жыл бұрын
Nayef Alhajraf, You're very welcome. Glad you're enjoying the videos. You might also like my new site: www.universityphysics.education Cheers, Dr. A
@RoboticsDevelopment3 жыл бұрын
Rocket Scientist you say? *scoffs* That's just conservation of momentum!
@manuboker13 жыл бұрын
BEST PHYSICS LECTURES EVER !!!
@simetric65516 жыл бұрын
Excellent explanation. We need more teachers and professors like this gentleman.
@yoprofmatt6 жыл бұрын
Thanks for the comment. Hope you're enjoying the physics. Cheers, Dr. A
@HARSHVARDHAN-im2hb6 жыл бұрын
God level of teaching !
@allenndlovu5174 жыл бұрын
Prof i like how you teach physics, you actually teach physics whilst solving real world problems and i think that makes your lectures very cool.
@samuelcarvalho36913 жыл бұрын
This video is amazing. IT WAS EXACTLY WHAT I WAS LOOKING FOR to understand this concept. You really opened my mind about this concept. I love the way you teach, your interaction with students. Everything makes it so interesting. After this video i actually like physics more hehe.I wish you were my Professor.
@laurenilano73686 жыл бұрын
THIS WAS SO GOOD
@ironphoenix86958 жыл бұрын
I like the explanation this is particularly good for revising something you have already learnt about
@yoprofmatt8 жыл бұрын
+Iron Phoenix Thanks much Iron Phoenix (best name ever). Cheers, Dr. A
@GauravKumar-wj2ht7 жыл бұрын
u r grt and i think very talented also.....thnx a lottt
@shoaibshahriar38826 жыл бұрын
Wow,u make physics so fun and practical.Teachers like u are what students need to fall in love with learning and physics.Grrreat video,pls keep up the good work :D :D
@yoprofmatt6 жыл бұрын
Great to hear. I'm always trying to improve the delivery. Stay tuned. Cheers, Dr. A
@pavanbs64074 жыл бұрын
Your are a real genius nothing can compare u
@yoprofmatt4 жыл бұрын
pavan, Very flattering, and very untrue. But thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@DEV-ey8jb3 жыл бұрын
Professor, Thanks a lot for this lucid explanation. My query is that, will this conservation of momentum hold true for a launch vehicle with in the earth’s atmosphere? Will it be correct to say that the stage separation of the rockets occur in order to reduce its mass as per the equation?
@vrindaverma79277 жыл бұрын
You are an amazing teacher Thanks a lot for these video's they are very helpful
@yoprofmatt7 жыл бұрын
Good to hear. Glad they're useful. Keep up with the physics. Cheers, Dr. a
@JIMMYPANTELLERIA2 жыл бұрын
what if the person throwing the wrench throws it using a battery powered wrench thrower and has a rope tied to the wrench, then after throwing, stops the wrench and slowly pulls it back to himself. When he has the wrench in his hands will the whole system have moved in an opposite direction of the throw?
@TheScienceCube6 жыл бұрын
Very nicely explained!
@yoprofmatt6 жыл бұрын
Thanks for watching! Cheers, Dr. A
@beatrax80066 жыл бұрын
Thank you very much for this explanation
@yoprofmatt6 жыл бұрын
You bet. Thanks for the shout out. Cheers, Dr. A
@aedenkramer46214 жыл бұрын
If you do reply my questioon is if something has a M=5kg which means 49N needed for thrust does how many times the needed N=there M/s like so does 147N mean it would go 2-3M/s 3if you account the needed intial force.
@onurgucukoglu53788 жыл бұрын
Does he write backwards?
@yoprofmatt8 жыл бұрын
+Onur Gücükoğlu Onur, no I just do a horizontal "flip" of the image. Cheers, Dr. A
@boxer86579926 жыл бұрын
no wonder why your wedding ring is in your right hand. lol
@EndureTemptation5 жыл бұрын
What about students in attendance? Do they watch what's written backwards?
@ahmedosman96996 жыл бұрын
What a great explanation thanx 😊
@yoprofmatt6 жыл бұрын
You are very welcome. Thanks for tuning in. Cheers, Dr. A
@samilnaml72993 жыл бұрын
Thank you sir for your clear explanation
@syedzubair69248 ай бұрын
Sir ever amazing lecture regarding the same topic I got it very well
@202get9 жыл бұрын
thanks, great explanation.
@yoprofmatt8 жыл бұрын
+Durin's Bane Cheers! Dr. A
@hazal5416 жыл бұрын
Its great .simply cleared .
@yoprofmatt6 жыл бұрын
Clear is good. Cheers, Dr. A
@souravkumarnath3 жыл бұрын
Is the final momentum was additive in nature by considering the direction ? 1)P = mv +MV or 2)P = mv- MV Because some books consider 1st one for solving rocket equation.
@yoprofmatt3 жыл бұрын
Sourav Kumar Nath, Depends on your frame of reference (earth or rocket) and also which way you regard the velocity of the exhaust. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@notsomuchhere13877 жыл бұрын
Thank you so much Sir,I have an entrance exam for an amazing university coming up and I need ace it !!
@yoprofmatt7 жыл бұрын
Best of luck to you. Be amazing. Cheers, Dr. A
@axalate45725 жыл бұрын
Dr. A i have a question Does the gasses move with a velocity relative to the rocket???? if so Why?????
@yoprofmatt5 жыл бұрын
The gasses are essentially "exploding" inside the rocket, and the only exhaust path is out the back. Thus they shoot out with very high velocity. Cheers, Dr. A
@eliyahomar4 жыл бұрын
Thank you
@yoprofmatt4 жыл бұрын
Omar Elmoré, You're very welcome. Glad you're enjoying the videos. You might also like my new site: www.universityphysics.education Cheers, Dr. A
@juice122224 жыл бұрын
Great explanation. Can we think of the empty rocket as the person and the wrench as the fuel?
@yoprofmatt4 жыл бұрын
Clorox Bleach #1, Exactly. And love the username. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@anamikakolay79813 жыл бұрын
Where do they write on?
@John-yahya8 жыл бұрын
Great explanation . Well done sir . But why is the Pf =MwVw-MpVp Isn't supposed to be + in between ?
@yoprofmatt8 жыл бұрын
Thanks Yahya, The minus sign indicates movement to the left (if we're calling movement to the right positive). If Vp is speed (a scalar, hence a positive number), you put the minus sign out in front to indicate a negative velocity. (Alternately, if you kept all the velocities as vectors, you would use the plus sign, but the Vp velocity vector would be a negative number, and you'd get the same result). Cheers, Dr. A
@nes22147 жыл бұрын
I get the concept, but I struggle with grasping the practicality of this situation. If space is a vacuum, or there is no air and no pressure in space, what produces the opposite reaction to force your momentum in the opposite direction? Wouldn't the conservation of momentum in space force both you and the wrench to continue in the wrong direction? Or would the reaction between you and the wrench be enough?
@nes22147 жыл бұрын
Or if space is expanding at a velocity faster than I can throw the wrench, wouldn't that cause a problem too? Or am I overthinking it?
@redus27 жыл бұрын
"What produces the opposite reaction to force your momentum in the opposite direction?" -- Think of Newton's second law. "The alteration of motion is ever proportional to the motive force impressed; and is made in the direction of the right line in which that force is impressed." Here the motive force is the wrench you're throwing. When you throw it, think of that as a push, which is a force. Now Newton's third law. "To every action there is always opposed an equal reaction; or the mutual actions of two bodies upon each other are always equal, and directed to contrary parts." Therefore when you push the wrench it pushes back on you. I'm not sure what you mean by the second and third questions. To continue the simplicity of the problem, as long as you throw the wrench in the opposite direction of the ISS then you will get back to the station.
@redus27 жыл бұрын
You're over thinking it. It depends which part of space you're talking about, how fast its expanding, it depends on your speed on your way back to the ISS and not the wrenches. Something would have to be effecting that small amount of space between you and the station. If the space effects you AND the station the same (like a gravity wave passing through) then it wouldn't matter and you wouldn't notice any change in distance.
@ryangarrison70887 жыл бұрын
You are making the common mistake of assuming the wrench (or rocket exhaust) is "pushing" on the air around us. And that without that air up in space, there is nothing to push on at all. But it doesn't work like that. It's a very common misconception. Like Christopher Smith said, for every action there is an equal and opposite reaction. You throw the wrench one way, you go the other way. It has nothing to do with the air, or lack of air.
@robertreynolds91205 жыл бұрын
Great explanation for the concepts presented but as a beginning physics student it leaves me wondering... At time 0, the astronaut and the ISS are orbiting the earth. When her tether breaks, the astronaut immediately throws the wrench. Assuming she throws it in a straight line from the release point, doesn't this propel her in a straight line back toward the ISS -- which will have moved on by the time she reaches its former position?
@yoprofmatt5 жыл бұрын
You are correct that things get a bit more complicated when in orbit, and particularly if they are separated by a good distance. I guess here we're assuming no effects due to being in orbit. Cheers, Dr. A
@arshisid479 жыл бұрын
this is such a great video!! wonderfully explained. well done Alex.half of the time i was wondering what it was that you were writing on. :p
@yoprofmatt8 жыл бұрын
+Arshmah Siddiqui Check out the board here: learningglasssolutions.com Cheers, Dr. A
@krishnakhandelwal94666 жыл бұрын
Ok. This means Law of conservation of momentum is same as Third law of motion. Right?
@Kalernor6 жыл бұрын
Precisely. When newton originally proposed his 3rd law of motion he proposed it in the form of conservation of momentum.
@albertzheng1823 жыл бұрын
thanks
@rajibkudas1235 жыл бұрын
Beautiful example...
@yoprofmatt5 жыл бұрын
Thank you. Oldie but goodie. Cheers, Dr. A
@gabrieldecker72094 жыл бұрын
Great video, the class is really engaging, makes the student enjoy it. However, I have one question, Dr. Anderson. I apologize in advance for the lengthy message, but I think it’s necessary. I totally understand the conservation of momentum in situations like a person pushing another one on an ice ring; or an astronaut throwing a wrench in an attempt to get back to the ISS (by the way, if we had molecules of gases on space, we should be able to move just by kicking the air, because we would be exerting a force on the molecules, and the molecules on us, right? That's just a hypothetical situation). The thing is, I don't really understand the conservation of momentum when the system involves gases(explosions, propulsion of a rocket,etc). For example, if a have a big stone, stationary, then I put an explosive in a hole inside the stone. And let's assume that the stone breaks into 2 chunks, that gains momentum in a straight line only (the X-axis). Conservation of momentum says that the momentum applied by the gases at the chunk that moves to the right and at the one that moves to the left has the same magnitude but opposite direction. But how does that work? I mean, when I push someone on an ice ring, I apply a force on that person, and he/she on me, as a reaction. But how does that applies to gases of the explosive? Part of the gases apply a force to the chunk moving to the right, during a dt, which results in a quantity of momentum to the right(and the reaction force is the one that the chunk applies to the gases), and another part of the gases apply a force to the chunk that moves to the left, during a dt, which results in a momentum that has the exactly same magnitude of that momentum applied to the chunk that moves rightward, how crazy is that? I mean, am I thinking too much about it? I do not see my peers thinking this way(like, they do not talk about the gases of the explosive and etc) and it really frustrates me at times, because I am spending way more time than my peers studying this subject. Again, great class! Cheers from Brazil!
@stuartgray58774 жыл бұрын
Gabriel - If I had a catapult in space that fired blocks of water ICE, would the catapult feel a recoil force when it fires the block? YES Now what about a tank full of LIQUID water of the same mass as the ice block? Now how about a FIREHOSE in space? Would a person hold a firehose feel the recoil when the water shoots out into space? YES. Now what if the water was a GAS (super heated steam) but of the SAME MASS? Will the firehose feel recoil if the water is superheated as it comes out? Hint: WATER VAPOR (gaseous water) STILL HAS MASS.
@gabrieldecker72094 жыл бұрын
@@stuartgray5877 Thank you, Stuart! It's becoming clearer. But still, thinking about the water in hose. Think that we have a reservoir up in the air, and a hose connected to it. So we do not use any pump, we just let gravity do its job. So, water is being shot out by the GRAVITY FORCE, and the reaction force to this force g force that is acting upon the water is the FORCE that WATER EXERTS ON THE EARTH'S CENTER. So, we have the action-reaction pair. So, Mr Stuart, If we look at it, we do not see any FORCE ACTING UPON THE HOSE itself, so how does the hose goes backwards??? I mean, when I throw something, this something applies a force on me, that explains why I go backwards. But, in the HOSE case, why does it go backwards if nothing is applying a force on it?
@stuartgray58774 жыл бұрын
@@gabrieldecker7209 WHY are you confusing the problem with a gravity fed water canon? Lets just talk about a water canon that expels the water at 3000 PSI. Would a person holding this water canon IN SPACE, feel a recoil when the water shoots out at 3000 PSI? have you EVER seen a video of firemen trying to hold on to a firehose alone? Maybe you should look that up?
@gabrieldecker72094 жыл бұрын
Stuart Gray I must lack knowledge, it seems simple to you, but I’m kinda struggling, idk why... Mr Stuart, see if I’m thinking correctly about the spacecraft. When it is blowing gases backwards, it goes forward. But the thing is, like I said before, if I throw a wrench, the wrench “throws” me, and that’s why I move, bc sth is acting upon me. So, when the spacecraft blows gas backwards, it moves forward because the gases are exerting forces IN SOME PART(i don’t know which part) of this spacecraft, is that right sir? Besides, this part of the spacecraft where the gases are exerting force upon must be one of the strongest parts. Is that right, Mr Stuart?
@stuartgray58774 жыл бұрын
@@gabrieldecker7209 The thing that gets the force applied to it is the Rocket Nozzle. Large Rocket engines have a giant nozzle that can expel massive quantities of gases at supersonic speed. The gases MUST have a force applied to them to be accelerated. The force is from the nozzle and the components in the engine that accelerate the fluids into the combustion chamber. On smaller spacecraft (like deep space probes) the engines are much smaller and mix Bi-propellants or mono-propellants to create thrust. Some thrusters I have had experience with were so small we called them "mouse farts" and were used to change the pointing of a spacecraft.
@mihirpant84746 жыл бұрын
Conservation of momentum is valid when there is collision but.. What about rocket 🚀. One there is no collision between the particles exhausted out?
@yoprofmatt6 жыл бұрын
Conservation of momentum always works (as long as you identify the entire system of particles). It works in collisions but also in explosions. A rocket exhaust is sort of like a controlled explosion. The gas that expanded rapidly not only pushed itself out of the rocket, but also pushed the rocket forward. Cheers, Dr. A
@papalegba67593 жыл бұрын
@@yoprofmatt so COM is defined as m1*v1=m1*v1? news to me. also pretty sure a CD nozzle doesn't 'push' a gas, but meh...
@JonLG4907 жыл бұрын
haha lets get it ! i love physics
@yoprofmatt7 жыл бұрын
Music to my ears. Cheers, Dr. A
@ozzyfromspace4 жыл бұрын
“Decrease your mass to move faster”. Me: *shits myself during panic attack* that works 😅👍🏽 In practice, the ISS is experiencing circular motion, so unless you plan the maneuver proper, you could miss the station and start floating out into space. That said, this was a very instructive example!
@yoprofmatt4 жыл бұрын
Float Circuit, Hilarious, love it. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@apoorvatandon82308 жыл бұрын
What's that board on which u write called
@yoprofmatt8 жыл бұрын
+Asd Fgh It's called Learning Glass. You can see more here: learningglasssolutions.com Cheers, Dr. A
@nivedkarun38346 жыл бұрын
Thanks
@yoprofmatt6 жыл бұрын
You are welcome. Keep up with the physics. Cheers, Dr. A
@TheHazCan7 жыл бұрын
I love science, but seriously struggle with algebra... Yet every thing you just said made perfect sense straight away, I wish you could have been my science teacher👌
@yoprofmatt7 жыл бұрын
Thanks Harry, Math (and physics) takes time to master. Keep working on both, put in the time, and you'll get it. Cheers, Dr. A
@husnainhyder67134 жыл бұрын
you're cool
@ramgy6127 Жыл бұрын
I am not a degree holder but I can understand.
@ZelForShort6 жыл бұрын
What are the odds! My names Alex!
@yoprofmatt6 жыл бұрын
Odds are probably pretty good. This video has 12k views, so there was bound to be an Alex eventually. Cheers, Dr. A
@ZelForShort6 жыл бұрын
Matt Anderson Fair point :) Great video as well. Very clear even to a 16 year old
@beingfor18257 жыл бұрын
You know Dr. Anderson. I love physics so much yet I do not understand even a single concept in it. I feel like my mind is blocked.
@yoprofmatt7 жыл бұрын
Sorry to hear that. Hopefully my channel will help a bit. I would suggest getting a study group together. See my video here: kzfaq.info/get/bejne/atWHZteIpt_QoKs.html Cheers, Dr. A
@frankdimeglio82162 жыл бұрын
CLEARLY, gravity AND ELECTROMAGNETISM/energy are linked AND BALANCED opposites (ON BALANCE); as the stars AND PLANETS are POINTS in the night sky. Consider TIME (AND time dilation) ON BALANCE. By Frank DiMeglio
@johnsumner14744 жыл бұрын
Is this also an example of Newton's third Law ?
@yoprofmatt4 жыл бұрын
John Sumner, Yep. Thanks for the comment, and keep up with the physics! You might also like my new website: www.universityphysics.education Cheers, Dr. A
@papalegba67593 жыл бұрын
@@yoprofmatt in that case why not draw a free body diagram illustrating the force pairs the rocket needs to create in order to produce motion? that's what a real teacher would do imo.
@stuartgray58772 жыл бұрын
@@papalegba6759 - "in that case why not draw a free body diagram" Coming from someone that REFUSES to provide this free body diagram even though I have been ASKING FOR YEARS - LITERALLY! So shut the fuck up!
@MuhammadAli-kw2ou7 жыл бұрын
where is rocket acceleration?????
@yoprofmatt7 жыл бұрын
Excellent question. Here we are talking about one impulse: we throw one object, and then we recoil. With a rocket, however, there is a continuous stream of particles being thrown out the back (the exhaust). Momentum changes continuously over time. Remember that F = ma = dP/dt, so herein lies your acceleration. Also note that the "exact" calculation for rocket propulsion gets a bit tricky. I'll try to make another video soon laying out the full details. Cheers, Dr. A
@ptyptypty35 жыл бұрын
but.. you could engage in some FLATULENCE and use that to Propel yourself toward the Space station!!.. lol, okay, that was Sophomoric but SOMEBODY had to say that!!.. (nevermind that I'm 65 years old and saying it... )
@papalegba67593 жыл бұрын
pretty sure a rocket is a heat engine of the internal combustion type, and thus dependent upon doing PV work. so i have no idea why you're blabbing about conservation of momentum and people throwing spanners in space.
@kitcanyon6583 жыл бұрын
@stuartgray58772 жыл бұрын
pretty sure you are a high school dropout that has never taken a single physics class in your life. STOP trying to lecture actual engineers about basic physics. All you do is make a fool of yourself
@papalegba6796 Жыл бұрын
@@stuartgray5877 pretty sure any "engineer" that doesn't know a rocket is a heat engine is useless lol.
@husnainhyder67136 жыл бұрын
Yes
@yoprofmatt6 жыл бұрын
Cool beans. Dr. A
@BasStuurwold6 жыл бұрын
Benedict Cumberbatch anyone?
@yoprofmatt6 жыл бұрын
Quite a few of my students agree with you. Now if only I could act! Cheers, Dr. A
@eugenegrudzien5040 Жыл бұрын
All of the explanations of rocket propulsion I've seen on KZfaq invoke Newton's third law of motion or use conservation of momentum. The third law of motion states that if two bodies INTERACT then the force exerted by body A will be equal and opposite to the force body B exerts back on body A. It is incorrect to say that the gas exiting the rocket in the backward direction causes the rocket to move in the forward direction, by Newton's third law, because there is no INTERACTION between the exiting gas and the rocket. The law of conservation of momentum is not a law like Newton's second law of motion which states that if there is a net, non-zero force on a body then the body will accelerate in the direction of the net force and is always true. The law of conservation of momentum is derived from Newton's second law and is true only in certain restricted cases. If you have a system of interacting bodies, they must obey Newton's third law in pairs so that all the internal forces between the bodies add to zero. Second, the sum of the external forces acting on the bodies must also add to zero. If these two conditions are met, then the total momentum of the system of bodies will be conserved. A rocket leaving the surface of the Earth doesn't obey the conservation of momentum because gravity is an external force acting on the rocket. Only if the rocket is in outer space, far from any gravitating bodies, can the conservation of momentum be applied. So, how can you provide a simple explanation for rocket motion? I believe that all you need to say is that the hot gases entering the exhaust chamber of the rocket expand in all directions and that the part of the gas having a forward component of velocity pushes the rocket forward. It can be said that calculating the change in a rocket's velocity is difficult in a gravity field and conservation of momentum can be used in the simple case of no external forces.
@brucemccandless71485 ай бұрын
Why not just use your SAFER device to propel yourself back to the ISS?