Non-Uniform Circular Motion Problems, Centripetal Acceleration & Tangential Acceleration, Physics

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Күн бұрын

This physics video tutorial explains how to solve non-uniform circular motion problems which cover topics like centripetal acceleration, tangential acceleration and net acceleration. Non-uniform circular motion occurs when an object moves in a circle with a change in speed. The centripetal acceleration arises due to a change a direction but the tangential acceleration is present due to a change in speed.
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Пікірлер: 71

@TheOrganicChemistryTutor Жыл бұрын

Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Next Video: kzfaq.info/get/bejne/e9ZhnayZrcrKYnU.html

@christopherortolano5434 3 жыл бұрын

Whenever i search up a concept im struggling in, I always hope your name pops up to teach me

@user-bv5sq9dy7w 3 жыл бұрын

Same

@rozanmohsen8868 2 жыл бұрын

Same

@godchisa2893 Жыл бұрын

same

@nexuslatir Жыл бұрын

Same

@ronnaraneta1812 5 ай бұрын

aren't we all😅

@dave5194 6 жыл бұрын

Thank you. Not a lot of videos about non uniform that actually goes into the math much

@prince_m_h_d2513 5 жыл бұрын

You are the best I got A+ in Physics because of you .

@gabe7996 4 жыл бұрын

Professor did not explain it like this! super helpful

@bman9469 6 жыл бұрын

another great video. thanks for all the help

@jacobvandijk6525 4 жыл бұрын

Would be nice if you had a video on the Corliolis-acceleration too ;-)

@lenael4747 4 жыл бұрын

You r so helpful ❤️

@chinkuchawdhary8017 6 жыл бұрын

Nice explanation

@faresabowandi6476 3 жыл бұрын

What if the object didn't start from rest which speed do i use to calculate the centripetal acceleration?

@user-yx9hb2bq9t 2 жыл бұрын

great great great great vedio and helps a lot on my test!

@N_NY_M 4 жыл бұрын

fing thank u man!

@abdulaziz10071 4 жыл бұрын

You are the best

@amoslangat3616 3 жыл бұрын

how do I taugle this... 1. A pendulum bob of mass 1.0 kg is attached to a string 1.0m long and made to revolve in a horizontal cycle of radius 0.6m. Find the period of the motion and the tension of -2 the string (assume g = 10 ms ).

@halidsufiyan3663 3 жыл бұрын

This diserve more subscribers 🏆🏆🏆

@Good-xc7qh 3 жыл бұрын

Thanks

@sthembilesibiya3589 2 жыл бұрын

The best lecture ever✨

@misterblank7795 2 жыл бұрын

Indeed

@peronkop 5 жыл бұрын

What if I don't have a time and the only thing I got is the start speed, end speed, the chord and the radius? Can I know the tangential acceleration then?

@rubentuting525 4 жыл бұрын

yes. 2as = vf² - vi² a = what u wanna know s = chord = angular displacement

@hassanakhtar4264 4 жыл бұрын

What’s the difference between tangential speed and acceleration and what’s the formulae or how do u find tangential speed if there is a difference?

@sarthakchavhan 4 жыл бұрын

Tangential speed (omega) = V(perpendicular)/radius Tangential acc (alpha)= a(tangential)/radius The difference between tangential acc and tangential speed is that the tangential acc is same acceleration that you study in kinematics and the tangential velocity is not dependent on tangential acc although tangential acceleration can change tangential speed . The relationship is same as studied in kinematics that the object can have constant velocity even in absence of acceleration. Only fact that should be noted both in kinematics and circular motion that velocity is constant( only magnitude in case of circular motion) when tangential acceleration is not present. Hope you got what you wanted . If not reply asap 🙏😊🙏

@Ej-sg5px Жыл бұрын

Sir ac=acostheta please explain what the value of theta will be?

@ChrisTuckerCarlzyn 19 күн бұрын

What does the angle theta represent?, the angle with respect to what?

@sudarshanregmi3070 Жыл бұрын

11:27 why is angle in degrees and not in radians?

@mathematicsforphysics6882 3 жыл бұрын

What is the direction of net force in non uniform accerlation? Can we calculate the angle in this case?

@johnzuba8803 8 ай бұрын

Net force matches the direction of the centripetal acceleration. No way to calculate angle because there is no tangential acceleration because the particular moves at constant speed. The net force component is simply the acceleration component times the mass I think

@gokhandurmaz6099 6 жыл бұрын

Thank you for telling this matter.

@amoslangat3616 3 жыл бұрын

1. A pendulum bob of mass 1.0 kg is attached to a string 1.0m long and made to revolve in a horizontal cycle of radius 0.6m. Find the period of the motion and the tension of -2 the string (assume g = 10 ms ).

@praketakshantala2179 3 жыл бұрын

Period is equal to 1 divided by the frequency (rotations/min). Hope this helps

@erfanahmadafghan689 6 жыл бұрын

Thank you as your service.

@Suhana_30.12 Жыл бұрын

The object is moving with a constant rate of change in velocity but the rate of change in speed is variable. Is this type of motion possible ??

@sreenadhek2842 5 жыл бұрын

When there is a tangential acceleration, the velocity is changing. Then how can the centrepetal acceleration become constant (v2/r)..?

@naweedbabakarkhail5210 5 жыл бұрын

Sreenadh E K that's a good question 🤔

@alieser7770 4 жыл бұрын

I guess the v there is the velocity at a certain point in time

@sarthakchavhan 4 жыл бұрын

Bro . When the tangential acceleration is present speed and velocity(i mean direction and magnitude both) are not constant . That is the reason why centripetal acceleration is also not constant . And also the net acceleration is= root (a tangential ^2 + a centripetal. ^2 ) So this means that the object will still have a circular motion . BASICALLY YOU DON'T NEED TO WORRY ABOUT THAT . THE ABOVE EQUATION OF NET ACCELERATION WILL ADJUST ON ITS OWN

@pyrojayxx1366 2 жыл бұрын

whats net acceleration for? it's not in my school material...

@AdenipekunAbdurrahman-uz5gf 2 ай бұрын

V good ❤❤❤

@sergiorome48 2 жыл бұрын

the angle seems wrong, well I guess it also depends on point of refernece? am I wrong?

@rubentuting525 4 жыл бұрын

can I replace v²/r by At = Ac×r ?

@mikaelasalvador8841 3 жыл бұрын

YAAAANNNN STEM PAAAAAA

@yurkkon6010 Жыл бұрын

Done

@tomatrix7525 4 жыл бұрын

I think it’s important to add, that with the first example, the net acceleration calculated is in respect to 5 seconds with the speed of 40m/s. Though tangental Acceleration would be constant, the Fc increases with time, so if he calculated the Fc at a speed different to 40, let’s say 20m/s, we would get a lower Fc, so the net acceleration would be the sq rt. of 8^2 [our constant Tangental Ac] . 20^2/800[ Our Contripetal Ac at the speed 20m/s.

@nemdenemam9753 Жыл бұрын

Can somebody please explain why the centripetal acceleration formula from uniform motion also applies to non uniform motion? The derivation I see everywhere comes from the assumption that |v1| = |v2|. Derivation in uniform motion: IF 1) |v1| = |v2| = |v| and v2-v1 = delta_v in common base 2) where delta_s = the vector between the bases of v1 and v2 THEN delta_s / R = delta_v / v rearranging: delta_v = v * delta_s / R dividing by time: a = delta_v / delta_t = v * (delta_s / delta_t) / R = v^2 / R How is it proven that the same geometrical constraint is true in regard to centripetal acceleration if it's not true that |v1| = |v2|?

@user-mr5cm7yh6h Жыл бұрын

I have this problem. Now of you know about that please explain it to me.

@leagueof1vs178 6 жыл бұрын

Organic Master

@RSKEDITS 6 жыл бұрын

very interesting and eazy to understand ; i think the like is less because the time your'e taking to draw those things, try to use any other softwares which looks better than this.

@lenael4747 4 жыл бұрын

That's not true. This is better 😐

@novierjohnabdallahyousefebrahe Жыл бұрын

gamed ya basha

@trinoncarter3946 2 жыл бұрын

fire my professor and hire this guy

@wengeance8962 6 жыл бұрын

ok but what if the problem is in radians?

@rubentuting525 4 жыл бұрын

where does v²/r came from?

@sofiaque490 4 жыл бұрын

It's a law. Memorize it!

@thenewwws 3 жыл бұрын

So on a uniform circular path, you can actually write the position of a particular with a vector r having the coordinates r as the length of the radius and and theta as the positive angle with the X axis. At time t=1 and t=2 the object will be at two different locations and the difference is the vector dr. The same is also true for their velocity vectors just as the position vector. Since the speed, i.e. the length, the magnitude of the velocities v1 and V2 is same and the difference between the two vectors is dv. The angle is also theta. As the angles are the same theta and both triangles have two sides of equal length, (The first triangle has the side length r, and the second triangle v), the triangles are similar and one can write v/dv=r/dr so dv=v/r*dr. And recall the acceleration can also be written as dv/dt as the change in velocity divided by the change in time. If you put v/r*dr in the place of dv in the second equation you get (v/r)*(dr/dt). Recall how we defined r as a position vector. So dr/dt is the change in position divided by change in time which is nothing other than velocity. So the equation becomes a=v/r*v = v^2/r

@mohammadanis1679 3 жыл бұрын

I wish you could replace my prof.

@zenobrawlstars3622 9 ай бұрын

My goat

@dhrubadutta856 3 жыл бұрын

u didnt point out that the radial acceleration is the opposite of centripeteral acceleration

@Maintenancevlog 4 жыл бұрын

Good luck sa mga nag exam dira 😂👌🔥🇵🇭

@helpme7489 4 жыл бұрын

hahahahahaha

@rubentuting525 4 жыл бұрын

daghan salamat unta tanan

@sergiorome48 2 жыл бұрын

so much better than the stupid textbook

@quibbyTM 2 жыл бұрын

Dropping out…

@kanekisleftkidney6474 Жыл бұрын

Hey Organic Chemistry Tutor. I wanna marry you. I love you so much on god. I been trying to use a textbook to help me with this concept for an hour and I just watched 7 minutes of this video and understand way more than I did with the book. basically all i am saying is I wanna have ur kids *muah*