Physical Pendulum Problems - Moment of Inertia

Physical Pendulum Problems - Moment of Inertia - Physics

Рет қаралды 153,753

6 жыл бұрын

This physics video tutorial provides a basic introduction into the physical pendulum. It explains how to calculate the period of a physical pendulum which depends on the moment of inertia of the rod and the inertia of any mass attached to it. This video contains 2 example problems.
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Пікірлер: 57

@TheOrganicChemistryTutor 8 ай бұрын

Full Video - The Simple Pendulum: www.patreon.com/MathScienceTutor Direct Link to The Full Video: bit.ly/3GEctFc More Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Physics Final Exam Review: bit.ly/3YZgrQl

@gp7493 5 жыл бұрын

When I get into the work field as an engineer, I'm paying your patreon hella

@jagoayomikun2304 6 жыл бұрын

Hell sire, I really appreciate your efforts.. Ur videos helped me to an A in my last semester physics course. I was the best in my class. This semester I have oscillations in my outline which includes simple harmonic motion, physical pendulum, simple pendulum, I've seen those video's and picked up important points. But I wud appreciate if you could make videos on forced oscillations and damped harmonic motion,which I can't seem to find. I would also like you to recommend a good textbook for me.. Tanks in advance sire..

@ibsangonzalez7351 3 жыл бұрын

@The Organic Chemistry Tutor whats the inertia when the axis of rotation is not at the end of the rod?

@tamimrahman9749 5 жыл бұрын

Thank you very much.Thanks a lot ♥♥♥

@abdulrakeebalsarori8171 4 жыл бұрын

Brilliant! Thanks a million

@cialatr 3 жыл бұрын

Excellent video! Thank you! :)

@shokhrukhmirzozokirov104 4 жыл бұрын

Very nice explonation, thank u so much

@prashanthseethapettai5347 5 жыл бұрын

Thank you!

@emmanulluakila4302 2 жыл бұрын

I do not know how many times this dude saved my life. thanks

@canadianhaitian 6 жыл бұрын

This is great I wish my professor would tell us where to get these formulas?! Now that I know I= 1/3 ml it’s easier to plug in

@Bluebabykitten 6 жыл бұрын

Watch his 2 hour video of simple harmonic motion

@Yourlocaljp 6 жыл бұрын

Search 'Inertia Moment of Common Bodies' in image search. Sadly in my class I have to memorize them for NO justifiable reason...

@Bluebabykitten 6 жыл бұрын

+Yourlocaljp same engineering physics

@kriztylkatemacalisang3526 3 жыл бұрын

Thank you so muuuuuch!!!

@siphelelenene3359 5 жыл бұрын

what if we are given compound pendulum say, 10 oscilltions in time of 95secs and we are ask to find moment of inertia

@quahntasy 6 жыл бұрын

This video really helped. But I was wondering why the channel name is Chemistry Tutor when this is physics.

@Pedritox0953 2 жыл бұрын

Very complete problem

@nic741 5 жыл бұрын

1/3ML^2 is the moment of inertia of a rod of length 2l hence isnt L=1.5/2?

@engr.rimarc.liguan1795 Жыл бұрын

d is the location of the center of the rod

@mikaelafrias7786 2 жыл бұрын

Hello, is it mgd or mgl for the equation at 2:17? Like are they both correct for me to use?

@engr.rimarc.liguan1795 Жыл бұрын

mgd

@celestialrainstorm 2 жыл бұрын

If d is the distance from the center of mass then if i drill a hole in between the pivot shown in the first problem and the center of mass then the distance would be 1/4 L and if i start pivoting from there then the period should be greater since d is smaller right?

@user-tc5eb5zu9q 11 ай бұрын

May I want to help you

@duncanram 6 жыл бұрын

A conical pendulum consists of a uniform straight bar (L) long and of mass (M), with a bob of mass (m) at its lower end. it rotates at (N rev/min) about a vertical axis through the upper end of the bar. How would you find the radius of rotation of mass (m)

@planeloverpilot4802 Жыл бұрын

radius will be length × cos theta with the horizontal.. its basically the horizontal component of length

@akashtandon3527 3 жыл бұрын

what happens if the axis of rotation passes through the centre of mass?

@akxyn5010 3 жыл бұрын

T is ∞ It means, it's never gng to oscillate

@akxyn5010 3 жыл бұрын

Because of 2 reasons 1) denominator becomes 0 2) There is no torque to cause rotation as distance between the perpendicular force and point of rotation is 0 Hence rxF = 0

@mashanatanzon557 Жыл бұрын

Hi! If I have a physical pendulum where I vary the height at which I apply the mass on the rod does the same formula work? Thank you.

@Troeltsch7873 8 ай бұрын

But a practical moment of inertia is a sum that could hardly get finished and also this youtube formula appears to fit a rod of negligible radius. You can tell from a Serway schoolbook that a FAT rod is going to deserve another formula and if you are also going to attach a big disk to it somewhere then the formula for that is going to be a sum that has both your rod and also your disk in it. Maybe the formulas for making a grandfather clock are up here on the internet somewhere?

@gregschraiber4224 2 жыл бұрын

Does anything in the formulas change if I'm dealing in imperial units (Lbs, inches) ?

@alphajim9405 2 жыл бұрын

Yes…. Just convert those units to metric

@Troeltsch7873 8 ай бұрын

Yes imperial units seem to work just as well in the particular case. Your unit of mass is not going to make any difference but if standard gravity is going to be feet per second per second then your pendulum length must be made out of feet and not inches.

@masseyway5261 2 жыл бұрын

Can someone confirm that 'd' = L/2. It's making me feel weird

@michaelcharif5818 2 жыл бұрын

I think the moment of inertia of a rod is (1/12)mL^2 not 1/3. Could you please double check this because it's kind of confuesing... other wise nice explanation , tnx

@tabularasa6581 2 жыл бұрын

It's 1/12 when the axis is in the middle of the rod, and it's 1/3 when the axis is at one end

@ibsangonzalez7351 3 жыл бұрын

Whats the inertia when the axis of rotation isnt at the end of the rod?

@tonibalogun4897 3 жыл бұрын

You can use parallel axis theorem to get that

@sulafamohammad5526 4 жыл бұрын

Does anyone know what is the relationship between the length an period in physical pendulum???!

@Troeltsch7873 8 ай бұрын

If you leave out the physical part of it then some pendulum lengths are listed in a book of Physical and Mathematical tables from Yarwood and Castle. Over there you see, that, for example, apparent gravity at Rome is about 9.80347 meters per second square and over there the length of a one second pendulum is about .99329 meters. That is an impractical pendulum, since, so far, the massive part of it has a negligible size and the longer part of it has a negligible mass. Also such a one second pendulum has a period of two seconds and it takes one second to go from one extreme to the other.

@feeargodpz65 9 ай бұрын

In my school it's I/mgh haha i was a little confused until i realized it, yay slow learner me 😔👍

@fanadeynbataoil8362 3 жыл бұрын

How did you get the 1/3

@diegoarpino2080 3 жыл бұрын

If youre talking about the part at 0:39, that is the formula for the moment of inertia of a rod rotating at its end. Hope this makes sense. Best of luck

@julianaloisetudlong9095 2 жыл бұрын

What if there is no given mass in the problem??

@Troeltsch7873 8 ай бұрын

Since you are dividing the moment of inertia by the mass of the pendulum it doesn't make any difference however massive it is and you may as well leave the mass of it entirely out of it. Apart from any consideration for air resistance the one and a half meter long rod should have the same period (at small angular displacements) regardless whether it weights a gram or a ton or anywhere in between.