physics Top 30 MCQ || physics MCQS with answers || Multiple choice Questions

No video

physics Top 30 MCQ || physics MCQS with answers || Multiple choice Questions

Рет қаралды 10,294

Күн бұрын

#physics #physicsmcqsolution #studymotivation
Hi viewer! Today I have covered complete physics mcqs with answers. these Mcqs are very important for all upcoming Exams, especially for class part I & part II,
#physicswallah
#physicsmcqs
physics,
physics girl,
physics wallah,
physics 2 final exam review,
physics class 12 chapter 1,
physics chapter 11,
physics suggestion for ssc 2024,
physics freshman course chapter 2,
physics grade 11 unit 3 new curriculum,
physics freshman course chapter 1,
physics 2nd paper chapter 1,
physics asmr,
physics animation,
physics answer key 2024,
physics angular momentum,
physics acceleration,
physics angels,
physics a level,
physics audiobook,
physics admission class,
physics are mind blowing,
a physics professor bet me,
a physics major is cooking breakfast when he notices,
a physics student on planet exidor,
a physics playlist,
a physics professor leaves her house,
a physics book slides off,
a physics toolkit,
a physics project,
a physics professor did daredevil stunts,
a physics lecture,
physics brawl stars,
physics basics,
physics bowl big bang theoryphysics,
physics girl,
physics wallah,
physics 2 final exam review,
physics class 12 chapter 1,
physics chapter 11,
physics suggestion for ssc 2024,
physics freshman course chapter 2,
physics grade 11 unit 3 new curriculum,
physics freshman course chapter 1,
physics 2nd paper chapter 1,
physics asmr,
physics animation,
physics answer key 2024,
physics angular momentum,
physics acceleration,
physics angels,
physics a level,
physics audiobook,
physics admission class,
physics are mind blowing,
a physics professor bet me,
a physics major is cooking breakfast when he notices,
a physics student on planet exidor,
a physics playlist,
a physics professor leaves her house,
a physics book slides off,
a physics toolkit,
a physics project,
a physics professor did daredevil stunts,
a physics lecture,
physics brawl stars,
physics basics,
physics bowl big bang theory

Пікірлер: 39

@sonu_birthlia. 2 ай бұрын

Ans.of 12th qus. Wrong 2m/ss is correct

@studyRoom31 2 ай бұрын

Yeah sure! To determine the acceleration of an object when a force is applied, you can use Newton's second law of motion, which is given by the formula: F=ma F=ma where: F F is the force applied, m m is the mass of the object, a a is the acceleration of the object. Given: Force F=10 N F=10N Mass m = 5 kg m=5kg We need to find the acceleration a a. Rearranging the formula to solve for a α: a=Fm α = m F Substituting the given values: a=10 N5 kg α = 5kg 10N a=2 m/s2 a=2m/s 2 So, the acceleration of the object is 2 m/s2 2m/s 2

@IlyasKhan-bd7gv Ай бұрын

F=10 Nm=5 kg2 lines; Line 1: cap F equals 10 space N; Line 2: m equals 5 space kg end-lines; 𝐹=10 N𝑚=5 kg Plug-in values 10 N=5 kg⋅a10 space N equals 5 space kg center dot a 10 N=5 kg⋅𝑎 Divide both sides by the same factor 10 N5 kg=5 kg⋅a5 kgthe fraction with numerator 10 space N and denominator 5 space kg end-fraction equals the fraction with numerator 5 space kg center dot a and denominator 5 space kg end-fraction 10 N𝟓 kg=5 kg⋅𝑎𝟓 kg Simplify a=2 N/kga equals 2 space N / kg 𝑎=2 N/kg Convert units a=2 m/s2a equals 2 space m / s squared 𝑎=2 m/s2

@studyRoom31 Ай бұрын

❤️❤️❤️

@GfhfhgKhan 2 ай бұрын

Nice Mcqs sir/m

@studyRoom31 2 ай бұрын

🌻

@AmeenKhan-xm2cw 2 ай бұрын

Sir All is well so always be happy

@studyRoom31 2 ай бұрын

🌻

@vishakhapathania2864 28 күн бұрын

Nice pyq 👍👍

@studyRoom31 28 күн бұрын

♥️♥️♥️

@ghulamfareedrajperghulamfa1292 2 ай бұрын

12 me a Hoga

@studyRoom31 2 ай бұрын

Yeah sure!To determine the acceleration of an object when a force is applied, you can use Newton's second law of motion, which is given by the formula: 𝐹=𝑚𝑎 F=ma where: 𝐹 F is the force applied, 𝑚 m is the mass of the object, 𝑎 a is the acceleration of the object. Given: Force 𝐹=10 N F=10N Mass 𝑚=5 kg m=5kg We need to find the acceleration 𝑎 a. Rearranging the formula to solve for 𝑎 a: 𝑎=𝐹𝑚 a= m F Substituting the given values: 𝑎=10 N5 kg a= 5kg 10N 𝑎=2 m/s2 a=2m/s 2 So, the acceleration of the object is 2 m/s2 2m/s 2 .

@Sneha_roy123 2 ай бұрын

Thankuuu sir 🙏 its nice ....nd very gud for basics 👌 😊

@studyRoom31 2 ай бұрын

🌻

@shakeelahmedjunejo7522 Ай бұрын

12 A

@studyRoom31 Ай бұрын

♥️

@shoaibshakirkohistani4063 Ай бұрын

12 Quistion Ans is wronG its Ans is 2m/s

@studyRoom31 Ай бұрын

♥️

@AhmadUmerL55 2 ай бұрын

All is well sir ❤❤❤batameez student kabhi kamiab ni hotay

@studyRoom31 2 ай бұрын

Much love 💓

@maheshb1509 26 күн бұрын

Sir 12 quastio 10 worng correct anwsar 2m,/ss

@studyRoom31 26 күн бұрын

♥️

@asiaKhan-us9ls 2 ай бұрын

Es trah ky channel monitize hoty hn????

@studyRoom31 2 ай бұрын

I don't know

@RasmitaMania-o5u Ай бұрын

12 no answer 2m/s²

@studyRoom31 Ай бұрын

🌻

@syedsaliman2195 Ай бұрын

Question 9 you discuss speed and acceleration not centripetal acceleration

@studyRoom31 Ай бұрын

I am so sorry Brother, I don't understand what you are talking about, explain to me a little so that I can answer you.

@syedsaliman2195 Ай бұрын

@@studyRoom31 sir g my question is that in your question is confusion b/c you talking about the speed and acceleration not centrepetal acceleration plz don`t mind and check your answer

@studyRoom31 Ай бұрын

@@syedsaliman2195 Acceleration is defined as the rate of change of velocity with respect to time. Velocity includes both speed and direction. If an object is moving at a constant speed, its speed does not change. However, for the object to have zero acceleration, its direction must also remain constant. Thus, when an object moves at a constant speed in a straight line (constant velocity), there is no change in its velocity, and hence its acceleration is zero. In summary: Constant speed implies no change in the magnitude of velocity. For acceleration to be zero, the direction must also be constant. Therefore, constant speed in a straight line results in zero acceleration.

@user-og1sl5qf1c 2 ай бұрын

answer are wrong

@studyRoom31 2 ай бұрын

Which answer is wrong tell me to see the book quickly?

@sonu_birthlia. 2 ай бұрын

Ans.of 12th qus. Wrong 2m/ss is correct

@syedsaliman2195 Ай бұрын

Q12 is also wrong

@studyRoom31 Ай бұрын

Yeah sure.It is the correct answer option A

@vidhimishra-dy4rg Ай бұрын

20 k a hoga

@studyRoom31 Ай бұрын

Determine the net displacement direction and distance: Moving 10 meters north is a positive displacement in the north direction. Moving 5 meters south is a negative displacement in the north direction. Calculate the net displacement: Net displacement = 10 meters north − 5 meters south = 5 meters north Net displacement=10meters north−5meters south=5meters north Magnitude of the displacement: The magnitude of the displacement is the absolute value of the net displacement. Magnitude of displacement = ∣ 5 meters ∣ = 5 meters Magnitude of displacement=∣5meters∣=5meters Thus, the magnitude of the displacement is 5 meters.

@studyRoom31 Ай бұрын

Correct answer option A