Pipe Resonance

Рет қаралды 45,681

Digital Sound and Music

10 жыл бұрын

A column of water and a tuning fork are used to illustrate the raised amplitude that results from pipe resonance

Пікірлер: 34

@martianman8948 2 жыл бұрын

Thankyou so much prof. I'm 10th grade, and I wasn't able to understand the experiment which was in our book... Now I'm very clear about it

@k1ra141 Жыл бұрын

Icse op

@userunknown4801 2 жыл бұрын

BEST VIDEO ON THE WHOLE INTERNET

@MohamedAli-qj8fl 2 жыл бұрын

Thank you so much

@sube789 8 ай бұрын

Thanks. Good demonstration...

@PennFosterHighSchool 6 жыл бұрын

Thanks for the clear demonstration of this concept!

@sadashiva2832 6 жыл бұрын

got cleared with the demonstration.....................thank u :-)

@santoshgoyal1303 3 жыл бұрын

amazing!

@erwinconxepts 2 жыл бұрын

wow thank you for this very informative lecture. i am finding a way to change sound using resonance for my bike exhaust

@sanjamdas3558 2 жыл бұрын

tq for the demonstration

@harshil_1.618 3 жыл бұрын

Nice demo

@llamafrhd Жыл бұрын

wow that must be a cold room

@nandinichaudhari628 2 жыл бұрын

Help's a lot👍

@theAlpha.06 5 жыл бұрын

Helped a lot sir👍

@steffliot3788 4 жыл бұрын

Helpful

@turbo3089 3 жыл бұрын

@ashmalshahzad 3 жыл бұрын

Thankyou😻

@shilohpatten3761 4 жыл бұрын

Why was the tube's air volume 2 Hz off from the tuning fork? Measuring the water from the top of the meniscus wouldn't have even made such a wide intonation wave. I'm just curious, maybe 343m (standard) is a constant with electronic sine waves while temperature only then directly effects amplitude dissipation instead of temperature determining the size of the metal fork because metal expands at lower temperatures. What do you think?

@sharanya181 2 жыл бұрын

tysm

@ShikharEdusoft 3 жыл бұрын

Prof. thanks for the demonstration. Can you please tell me which oscilloscope software are you using to visualise waveform on your screen? I need to show the same for my students.

@slvds 3 жыл бұрын

I'm using Spectre. It recently traded hands over to a new company and I'm not sure if they're selling new licenses yet. But here's the link: www.zynaptiq.com/macaudioapps/

@SwirlingDragonMist 3 жыл бұрын

What specific software and equipment was used in this demonstration?

@turbo3089 3 жыл бұрын

If you put the same tuning fork down inside the pipe and remove the water will a echo and resonate at the same time

@abhijitk3980 3 жыл бұрын

Sir, What is the effect of inner diameter and thickness of pipe on resonance?? Any formula ??

@ThomasHaberkorn 4 жыл бұрын

Dear Prof., I have a mix up in my terminology, I think you can clear things up. I did the following experiment: I have air flowing through a straight pipe. Pressure ratio between outlet and inlet is lower than the critical pressure ratio, which suggests flow velocity at the outlet is close to the speed of sound. I have recorded the sound of this process and analyzed the frequency spectrum. Suprisingly for me (but maybe not for you), the dominant frequencies are in a integer ratio to one another. So this would imply a standing wave behaviour.. but can it be called that? The air is moving at a great speed through the pipe after all. I search on the web for explanation, of little avail. Literature containing a mathematical approach would be greaty appreciated. Take care, love your videos.

@slvds 4 жыл бұрын

The term "standing wave" is typically used to describe a resonance that is happening in a room. So yes, what you are observing in your experiment is a resonance, and yes, multiple frequencies resonate simultaneously. For a pipe that is open at both ends, the fundamental resonant frequency will have a wavelength that is twice the length of the pipe. And then yes, integer multiples of that frequency will also resonate. Here's some more information from our book: digitalsoundandmusic.com/2-1-4-resonance/

@letslaugh8287 2 жыл бұрын

Thanx sir ☺️☺️☺️☺️☺️☺️

@anirudhagavhane1036 3 жыл бұрын

Sir where are you from

@luqman4826 5 жыл бұрын

At 1:42 why is it 1/4 of the wavelength

@theAlpha.06 5 жыл бұрын

Because at that point node is formed ie the displacement of wave is zero there.....

@chandrabhan7212 5 жыл бұрын

At water surface and open surface we apply boundary conditions i.e., a node is formed at the water surface (since its displacement must be zero at all times) and an antinode is formed at the open surface. Distance between a node and an antinode is lambda/4, where lambda = wavelength of the applied frequency.