That's what I'm here for. Glad you like...

That’s fantastic to hear AJ. I have actually been keeping them this duration on purpose thinking that I must get to the point and have a message without it turning into a lecture. I want to avoid technical overload, especially if the intention is to help younger engineers. But it’s awesome to hear longer videos aren’t unwelcome! Thanks for the feedback.

Wow, thanks a lot! Hope it’s useful to you!

You have no idea how nice that is to hear. Thanks for the support.

You bet!

Appreciate it Hugh!

That’s really kind, thanks a lot man! Am not worried about the numbers… If the stuff is good enough it will come! I always say that as long as I answer a question that only a handful of people have then that’s why I started and I’m happy! Once again, thank you.

Yes, Pat should have more FLOW based on his content. BUT wait... Seems like the flow has increased dramatically recently . Does this mean he has no HEAD? 😂

@@delinquenseyeah man I want more videos from him ...seems like he hasn't posted any recently

I have no idea what you’re talking about 🤫

Glad you thought so! Yes, although more accurately it makes it easier for what drives the pump (normally a motor).

@@ProcesswithPat got it! Makes sense now, thank you

Hey there! There’s quite a bit in your not-really-question, but it’s pretty interesting! First and foremost - you have defined some heights (you didn’t mention how high your hill was) but no flow rate requirements or line sizes. You would need line dimensions/geometry as well as the flow rate to be able to say anything about the pressure. So the 50 psi guess you gave - it totally possible - you could design the pipe so that at the design flow rate the discharge pressure is 50 psi (as long as this is enough to get uphill). So we can’t be too specific with values because the problem isn’t defined enough. Secondly, you have 250 ft in the reservoir which means you can flow to the tank without a pump as long as your hill is less than 220 ft (250 reservoir minus 30 tank). The RATE would depend on your line size. Need more flow? You need a bigger pipe. The main reason you’d have a pump is if the flow rate required would need really large pipes for low pressure drop, and so it becomes more economical to install a smaller pipeline and overcome the pressure drop (due to higher velocities is a smaller pipe) with a pump. Thirdly - your question - what is the pressure as the fluid reaches the pump? You are describing a transient state and so the pressure will increase the more the discharge line fills, and yes, it will increase even quicker when the fluid starts flowing uphill. But the pressure will start increasing even before the liquid reaches the uphill. Imagine you have a water/air interface. Air flowing through a pipe also has pressure drop. So your pump pushing that air-water interface along the pipe is not only causing water flow, but also air flow. Both of these have their own pressure drop in the pipe. It’s just that air flowing at the same velocity as water in the same pipe causes less pressure drop because of the very low air density. So even before you’ve reached the uphill the proportion of pipe exposed to water versus pipe exposed to air is increasing, and the water experiences higher pressure drop, resulting in an increase in discharge pressure from the pump. If your pump was running at constant speed that would mean the flow would be dropping over time. Once again - the significance of all these effects is totally academic because we have no idea what the line sizes and velocities are. Finally - practically speaking - you need to ask yourself when you would start the pump. Realistically you’d open a valve on the reservoir and one on the tank and flood the line/pump. It’s not likely that you time the pump to start as it sees liquid. It is interesting to consider how the pump discharge pressure changes theoretically though. However, you would have valves on the discharge of that pump and you would never start the pump with that discharge valve open. That is because a motor draws an extremely high current when it starts because it takes force (and electrical current) to accelerate it to speed. If your valve is open then that entire flooded line is placing load on your pump/motor which will push the starting current up even further. You would have over-current protection (basically a circuit breaker like at your house) on your pump motor to protect it from burning out due to high electrical current. Does that help?

@@ProcesswithPat Thanks Pat, I guess what I'm wondering is this: Do pump effluent pressure gauge readings equal just the amount of pressure/resistance on the effluent side of the pump, or do they equal that plus the pressure on the inlet side of the pump? If my inlet pressure was 50 psi and I had no resistance to flow on the outlet, would the outlet pressure be 0 psi or 50 psi?

If the ONLY thing you do is increase suction pressure to a centrifugal pump, then the discharge pressure and flow will both increase, but the DIFFERENTIAL pressure will drop. So if you start with suction at 0 psi and discharge at 50 psi, and then you increase the suction to 50 psi, then the discharge will got to some thing like 90 psi. However it is also totally possible to increase the suction pressure from 0 to 50 and maintain the same differential to gave 100 psi discharge. The best way to understand is by looking at pump/system curves. I’d be more than happy to do a video on it, if it’d be useful?

As promised: kzfaq.info/get/bejne/rbOUgrthzZfdpIU.html

Hey Manoj? You looking for something specific? I like to put in a bit of work into it, but I need a good understanding to explain it clearly, and although I understand compressor surge, anti surge not something I use daily… so I don’t want to pretend to know thing I don’t!

@@ProcesswithPat if possible can you do a video about centrifugal compressor surge and the anti surge devices used on the centrifugal compressor to avoid the surge phenomenon

He explained only in laymen language