Razavi Electronics2 Lec12: Large-Signal Analysis of MOS Differential Pair

Рет қаралды 90,033

6 жыл бұрын

Пікірлер: 35

@anaseshmawi568 5 жыл бұрын

You are the best professor I have ever learned from. I really hope that all professors do the same and be humble as you. They think all students are as experienced as they. they need to put themselves in our shoes

@coolwinder 3 жыл бұрын

01:25 - Intro and Review 04:19 - General Properties of the MOS Differential Pair 15:00 - Note: CMRR is affected by the tail current output resistance 15:12 - Rough Differential Behavior of the MOS Differential Pair 20:12 - Saturation Region of the MOS Transistor 21:43 - Example: The Minimum Value of the Input Differential Signal when one Transistor Turns Off 29:00 - Large-Signal Analysis of the MOS Differential Pair 44:00 - Note: Overdrive voltage is important as it defines largest differential input voltage amplitude

@jing-chingchen2333 4 жыл бұрын

thanks for the series of lecture upload in KZfaq!!!!! It could be life saving for an individual trying self-studying electronics alone!!

@gevorggeghamyan1718 6 жыл бұрын

Brilliant job!

@hemantj675 Жыл бұрын

Thanks for these videos. Life savers.

@felixqi6659 3 жыл бұрын

Thank you so much, Sir!!!! Really love your lecture!

@mnada72 3 жыл бұрын

Waiting eagerly for circuit theory I & II and the rest of the series.

@prashantsharma5618 6 жыл бұрын

Excellent Lecture......My humble request to cameraman to please pay attention to the noise comming in between.

@zinhaboussi 7 ай бұрын

i think he is filming alone in his house

@samtiny6332 5 жыл бұрын

thank you sir ,,, u give lots of time

@camilotello3296 2 жыл бұрын

I love your lectures.

@velmalagangadhar1532 5 жыл бұрын

brilliant explanation sir

@danysharrouf8207 5 жыл бұрын

Excellent lecture

@swarnikashruti5308 4 жыл бұрын

brilliant lecture

@Krishnasharma-wc4wo 5 жыл бұрын

brilliant

@12345breakdown 2 жыл бұрын

GOAT

@hosseintjk4324 5 жыл бұрын

سلامت باشه این استاد

@zinhaboussi 7 ай бұрын

ازيك يا باشه هههه

@zeustheboerboel3794 4 жыл бұрын

what it must feel like to be a genius like yourself

@coolwinder 3 жыл бұрын

Maybe lonely, but absolutely fulfilling!

@AmrBinAas 5 ай бұрын

Nice Prof ❤️

@prat4142 Жыл бұрын

Bro really wants us to solve the equations at 39:50 💀💀💀💀

@e1490807aa Жыл бұрын

The ID1 that I get by calculation is ID1=1/2Iss ± 1/2 Kn(Vin1-Vin2)^2 (don't know if it's correct or not yet.)

@DuyNguyen-kh5tk Жыл бұрын

checked!

@engine28111 4 жыл бұрын

how to get final result of (Id1- Id2)?

@alexnoggle1874 Жыл бұрын

First you have to square both sides where he left off at 39:00 to solve for Id1. Then you must move everything to the same side and multiply everything out. After that, you have to use the quadratic formula where a = -16, b = 16*Iss, and c = 4*(Vid^2)*Iss*kn-4*(Iss^2)-(kn^2)*(Vid^4). Once you have plugged everything into the quadratic formula, simply it as much as possible. Now, repreat all of that to find Id2. Next subtract Id2 from Id1. Both Id1 and Id2 should have a section of their equations where there is a +/-. For Id1, make the +/- a +, and for Id2, make the +/- a -. Once you do this, you can simplify it into the final equation that he provided. It's a bunch of algebra, but once you get going it won't seem so bad.

@velukrishna808 3 жыл бұрын

8:20

@ayshaabdulgani442 5 жыл бұрын

When Vgs = 2Vth, what will be the region of operation?

@sauravarjun6224 5 жыл бұрын

Depends on what is Vds, if Vds >Vgs - Vth, it is in saturation region else triode region.

@mrpossible5696 5 жыл бұрын

16:34

@not_nerd_iitian1764 2 жыл бұрын

brilliant way of explanation but please don't write books anymore.

@Abhishek_78 Жыл бұрын

Bit rude, but I know what you mean, There is decent hand-holding in his videos, but the flow of concepts in the book is not articulated well enough. Newbie reader feels like he is being swung from one circuit topology to another, with no support whatsoever.