Reacting Masses - Worked Example

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Reacting Masses - Worked Example

Рет қаралды 70,924

Күн бұрын

Step by step video showing you how to do the reacting masses calculations. In these questions, you are given the mass of the limiting reactant and asked to calculate the mass of a product, using the balanced chemical equation.
If you are practising, here are some questions for you to try. Show your full working out and see if you arrive at the correct answer:
1. 56 grams of water (H2O) react with sodium (Na) to produce sodium hydroxide (NaOH) and hydrogen gas (H2). Calculate the mass of hydrogen produced. The balanced chemical equation for the reaction is: 2Na + 2H2O  2NaOH + H2
Answer: 3.12 grams
2. Calculate the mass of potassium oxide (K2O) produced from 126 grams of potassium (K) reacting with oxygen (O2) in excess. The balanced chemical equation for the reaction is: 4K + O2  2K2O
Answer: 152 g
3. 34 grams of magnesium (Mg) react with chlorine (Cl2), which is in excess. Calculate the mass of magnesium chloride (MgCl2) produced. The balanced chemical equation for the reaction is:
Mg + Cl2  MgCl2
Answer: 140 grams
4. Excess sulfuric acid (H2SO4) reacts with 23 grams of copper oxide (CuO). Calculate the mass of copper sulfate (CuSO4) that would form. The balanced chemical equation for the reaction is:
CuO (s) + H2SO4 (aq) → CuSO4 (aq) + H2O (l)
Answer: 46.1 grams

Пікірлер: 55

@wallacehu223 4 жыл бұрын

very clear explanation. Easy to follow and understand

@emilia5289 3 жыл бұрын

THANK YOUU SOO MUCH - Until now I couldn't fully comprehend the method of working out reacting masses but now thanks to your very concise and clear explanation I DO ! :)

@TakaiwanaMazarura 2 ай бұрын

you have made chemistry pretty easy for me

@zebamaryam 3 жыл бұрын

Thank you for explaining so clearly!!!

@insync6684 3 жыл бұрын

Your techniques is very good but instead of using moles we can calculate like this, this is a easy method. first - find the relative atomic mass of 4Fe so, 4 x 56 = 224g secondly find the atomic mass of iron oxide iron = (56 x 2) = 112 112 x 2 (because there are 2 moles in iron)* =224g Oxygen = (16 x 3) =48 48 x 2 ( because there are 2 mole in oxygen) = 96g Now we add the masses 224 + 96 = 320g We know that 4fe 2fe(2)O(3) 224g - 320g 45g - ? 224 g produce 320g grams of iron oxide, how much does 45g produce? 45 x 320 -------------- = 64.28g = 64.23g ( 3 sgf) 224 If you guys found this easy try this one or try another one. your choice.

@otaku1615 2 жыл бұрын

Thx alott I just got a question to determine the molar mass of 3O2 for example do we multiply the molar mass by 2×3 or just by 2 or just by 3?

@insync6684 2 жыл бұрын

@@otaku1615 First. What is the molecular mass of oxygen ? 16. The question is 3O2, so your first times by 2. So 16 x 2 = 36. THEN times by 3 (the mole) . 36 x 2 = 72. The total mass of 3O2 is 72.

@otaku1615 2 жыл бұрын

@@insync6684 oh okay so for another example if we got 7O2 we first times the molar mass of O which is 16 by 2 then by 7

@insync6684 2 жыл бұрын

@@otaku1615 yes

@otaku1615 2 жыл бұрын

@@insync6684 thxxx alotttt

@sujatadasroy4269 4 жыл бұрын

very nice video , well explained and clear!

@henrycarr7983 2 жыл бұрын

Just saved me cause I have a chemistry mock tomorrow and fully get this now, thanks.

@mohamedalihassan7015 3 ай бұрын

2yrs ago, I hope now you're in another field.

@henrycarr7983 3 ай бұрын

@@mohamedalihassan7015 got an 8 in chem separate higher 🔥🔥🔥🥱 don’t do it a level though

@josephgrant9615 3 жыл бұрын

such as great explanation thank u, such a different feeling than someone who is terrible at explaining stuff

@alphaskeli3524 2 жыл бұрын

i love how simple this man makes it thx

@utkarsh8744 4 жыл бұрын

Really helpful. Thank you

@gregtheegg 11 ай бұрын

I never comment on videos, but I appreciate you so much, I now feel confident on my end of year test. EVERYONE LIKE

@jaehyahyuk5746 3 жыл бұрын

Thank you!!! Nice short video with great explanation.

@CrispPlate 11 ай бұрын

Thank you... You helped me sooo much! 🙏🙏

@sobansohail1320 3 жыл бұрын

you helped me alot

@tinodaisheganyani6188 3 жыл бұрын

Good 👍 comment

@Faridbuza Жыл бұрын

Thank you so much for this clear explanation. You should do more videos. You're a really great teacher. Thank you ❤

@diskittydoegd4169 2 жыл бұрын

Thanks this helped a lot!

@julialazzarotti644 2 жыл бұрын

Thank you!!

@xarqs8646 5 ай бұрын

absolute legend

@muntasirahmed8715 Жыл бұрын

Thx man..it helped a lot!

@emilymonk58 3 жыл бұрын

Lol am I the only one who still doesn’t get it

@cricup3835 Жыл бұрын

I'm I the only one who Dying on mole chapter

@elestrello6564 2 жыл бұрын

Thank you so much that really helped !!!!!!!!!

@idealsnake3849 Жыл бұрын

Thank You so much

@jocelynmegio4369 3 жыл бұрын

Thank you!

@andrewmudenda6916 2 жыл бұрын

Very clear and accurate 👌

@OOHMED 11 ай бұрын

thanks man!

@chair6385 Жыл бұрын

Thank you

@lilz707 3 жыл бұрын

wow thank you so much

@tinodaisheganyani6188 3 жыл бұрын

Completely exllent

@doodlegirl-art Жыл бұрын

Thank you very helpful!

@harlem8015 3 жыл бұрын

Life saving

@RhondaGomaveh-pf8bo 10 ай бұрын

Appricated

@raheema 2 жыл бұрын

thank you so much man

@watashiwaaziz7252 10 ай бұрын

Since you have the mol ratio, and the no. Of mol for iron, you could just cross multiply, ( quicker method k

@ksumar 5 ай бұрын

I think the solution can be simplified much easily without the mole concept: From the equation we know that: 4Fe + 3O2 ---> 2Fe2O3 (56x4=224) of Iron produces 320g of Fe2O3 (twice as much as mole of Fe=160g) Therefore, if 224g Fe------> 320g Fe2O3 45g------> give would produce: 45 x 320/224 = 64.3g of Iron III Oxide!