McKinsey interviewer led consulting case interview: free public Wi-Fi (w/ ex-BCG Consultants)

Рет қаралды 8,394

Күн бұрын

Here's a consulting case interview featuring an ex-BCG Consultant & ex-BCG Project leader focusing on an open-ended question that covers brainstorming and qualitative reasoning activities with some quant.
🎥 Your Client is the government of a large city. (Think Chicago, New York or Los Angeles). They plan to provide all residents free wireless connection by building Wi-Fi hotspots covering the entire city. They hired McKinsey to help them determine whether or not they should do it.
Watch Christopher Macrae Ham (ex-BCG Project Leader) run Matthew Calvert (Ex-BCG Consultant) through this mock consulting case interview.
🎬 Video Sections:
00:00 About the case
00:51 Introductions
03:37 Case question
04:03 Clarifying questions
05:22 Structuring
08:10 Brainstorming Part 1
11:12 Brainstorming Part 2
15:17 Quantitative
20:58 Synthesis
21:38 Conclusion
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💡 Looking to become familiar with the consulting industry, the career opportunities, and the recruiting process? Our free consulting guide covers it all: www.rocketblocks.me/guide/con...
➡️ Book a 1-on-1 coaching session with Christopher here: www.rocketblocks.me/contribut...
➡️ Book a 1-on-1 coaching session with Matthew here: www.rocketblocks.me/contribut...
#consultinginterviews #caseinterviewprep #BCG #consulting #mckinsey

Пікірлер: 16

@nralpha63 Жыл бұрын

I'm Nikhil Raigonde, from India doing an MBA currently. I want to thank you for making these case interview videos. I have learned a lot.

@rocketblocks Жыл бұрын

Glad you enjoyed it! Subscribe for more mock interviews

@hasmo42 Жыл бұрын

Great video! I don't think the math makes sense though - should calculate area covered by each hotspot (pi * radius^2) and divide total area (40*25) by area per hotspot to get number of hotspots (approx 13) and multiple by cost to get $13M

@thegoonist Жыл бұрын

you cant do that. its a circle. i got 27 hotspots to cover the area.

@varadajitkshirsagar6880 11 ай бұрын

With all due respect, how did you come to 27 hotspots ? Isn’t dividing area of the rectangle by the area of one circle going to cover all the area? I understand it being a circle means having a few open spots but covering those would be an additional 7 hotspots, bringing us to a total of 20 hotspots (13 + 7).

@1Piece_Luffy 11 ай бұрын

I also got 27 hotspots. The secret is to draw out. Think of 8 golf balls, 5 cm radius each, tightly positioned from the top in the 40 cm x 25 cm gift box. You are basically covering up so that you cannot see any crevice from the sky. You will find 5 x 3 holes between the balls themselves and the balls and corners. You also need to add 4 more on the bottom, below each ball because there are 5 cm gaps. Therefore, you need 8 + 15 + 4 balls so that there is no black space from the helicopter view.

@nope2467 10 ай бұрын

Actually 24 hotspots is enough, find a square in the circle which is approximately 7 x 7, you need 6 of it to cover the 40 unit wide (total to 42), and 4 to cover 25 unit height (total to 28). So 24 is sufficient How calculate the units of square in the circle, draw two radius 90 degree to each other, connects them and you will get the length of one side of the circle. Which is the square roots of 50, around 7 units. Hope this helps

@fouadljn7033 3 ай бұрын

@@varadajitkshirsagar6880 I think the best way to approach the math is to consider the biggest square that can fit into a circle. This square will have a diagonal of 10 units. that means that the square has a side of root square 50 or the square has an area of 50. Finally, we can divide the total area (40x25)/50=20

@kloppsliverpudlians88 2 ай бұрын

I would have done this differently. Square area = 40x25=1000 sq ft. Circular area per hotspot = pi x r^2 = (3)(5)(5) = 75. Therefore you need at least 1000/75 = at least ~15 hotspots + some buffer for inevitable overlap

@saroco 2 ай бұрын

The best solution is to look for the biggest square circumscribed in a circle of radius 5. Then divide 40 into the length of that area, same with 25. Finally, multiply both results. From Pitagoras theorem, one can get 2*a=2*sqrt(c^2 /2) Where “c” is the radius of the circle, and “2*a” is the length of the square side. Replacing c=5 results in 10*sqrt(0.5) ≈ 7 Then 40/7=5.71≈6 25/7= 3.57≈4 But values must be rounded up. Then the final answer is 6*4=24

@francescobruzzone9099 Жыл бұрын

Didn't really get the process of solving the math question. Has anybody got that?

@yingying-tz5zk 2 ай бұрын

Hi there, Thanks for making such a awesome video for us. Just a quick question, how long we can think of the clarifying questions? Is there any way we could speed up?

@nimbus2758 9 ай бұрын

I don’t think he followed any structure, he was just giving launder list

@henriettaifyede1737 10 ай бұрын

Hi...can you (anyone) please explain the maths process (calculations)?

@pankajmehta655 7 ай бұрын

I think the way he went about is: 1. For a circle to compensate for the overlaps, consider them as square with the diameter as the diagonal of it. 2. With that (although I am not sure he did it that way) you can estimate the side of the square. i.e 10/sqrt (2). 3. Then you just calculate the number of squares that will be needed to fill the area of 40*25 units. Round off the sqrt (2) to 1.5 to make calc easier. Ballpark it's going to be around 28. Hope this helps.