you're the reason Im going to get a 528 on the mcat
@sarahchong9616 Жыл бұрын
update I got a 498 and now I am retaking it lmao
@alifaraj312 Жыл бұрын
@@sarahchong9616you got this
@aslaans.5654 Жыл бұрын
@@sarahchong9616 LMFAO I FEEL U
@sophias42805 ай бұрын
@@sarahchong9616How did the second round go?
@zazzawi00992 ай бұрын
My smile never disappeared so quickly 😆 I really hope you did great second time 🥰
@DFOlover13 жыл бұрын
Are you serious? It's really been this easy???
@TheFutureGuyGaming3 жыл бұрын
thanksssssssssss really helpful!!!!
@amberwolff41112 жыл бұрын
How would you know if both reactants =2? For example, 1N2 + 3H2 --> 2NH3, for both reactants mol/c = 2
@sciencesimplified38902 жыл бұрын
If the number of mols/C for both reactants = 2…. Then neither would be a limiting reagent, both reactants would run out at the same time
@BUNNIELOBES2 жыл бұрын
Ahhh!!! Thank you for this!!!!
@shawalbhalli9076Ай бұрын
When we calculate theoretical yield using the moles of the limiting reactant, do we use the moles before dividing with the coefficient?
@sciencesimplified3890Ай бұрын
As opposed to what? But yeah I believe so I’m a bit confused exactly what you’re asking
@e.m.ye.m.y1779 Жыл бұрын
Thank you so much !! Do you have an email for inquiries ?? Thank you again
@prinox168610 ай бұрын
bruhh !!! ❤
@sukhdevchaudhary241 Жыл бұрын
We can't understand your voice in English we can in English but your voice is soo diff please manage for us🙏
@Tert-Butyl Жыл бұрын
I'm sorry but could you not just assume the one with the biggest coefficient is the limiting reagent? I feel like this is taking it a step further than it needs to go.
@sciencesimplified3890 Жыл бұрын
Trust me, do not soley use to coefficient to determine the limiting reagent… there will be many examples of this on exams where that will not be true