He is a professor and probably majored in chemistry, which requires a lot of math, chem, and bio knowledge

You get prepared for the subject, work hard on it, practice and if you have some talent on the subjects BAM! You've got an informative video.

@@tsugumilana7581 also he might have notes which most college professors have and probably keeps updating it. That’s what I do as a tutor. It takes practice

I'm a chemistry major. In addition to 50+ hours of chem, math thru calc III is required, and calc based physics

it's all based on each other, it just works

😺

i’m not an expert but my professor always says that if it’s charged, it’s a strong nucleophile. since it’s an iodide ion, it has a negative charge. the aprotic solvent will actually help it, because a protic solvent would surround the nucleophile and hinder it. that’s why SN2/E2 reactions favor aprotic solvents

Despite it being the weakest nucleophile of the halogens in an aprotic solvent it still is a relatively strong nucleophile

hmm good catch

I was thinking the same thing since on 14:33 he said I- was not the strongest nucleophile (for aprotic solvents)🤔

I think it is because OCH3 on its own is a strong base so it will be more likely to take a hydrogen from the substrate and do an Elimination than act as a nucleophile and do a Substitution

There is a join option next to subscribe.

That's more than likely a mistake there, if he had used some other polar protic solvent like water then it would've been correct, because water is so small to solvate tert-butoxide anion and so it would've still been an E2 reaction, even though the solvent is polar protic always look at the size of the anion of the base also to decide whether it's an e1 or e2 reaction, so yes u r correct it should've been an E1 reaction because tert-butanol is used as solvent which has the capacity to solvate big anions

Compounds that are tertiary will undergo a SN1 reaction more readily. In this case, we were looking for what solvent would allow for that reaction to undergo which relies on polarity of the solvent which water is the most polar in this case. Basically tertiary compound is the one going through the SN1 reaction while water is the one causing it.

I believe that in any Polar solvent that once the Bromine leaves the Iodine can attach easily because it is able to bully it’s way around the positive end of the acetone trying to inhibit Iodine’s movement because of it being a larger molecule. Fluorine is the strongest but smallest in size so it would have the most difficult time trying to go around acetone molecules. However, in Non polar solvents, then electro negativity wins out and then Iodine couldn’t replace Bromine. However I don’t understand the Bromine being pushed out by an iodine in an SN2 reaction either so I agree with you on that. It seems Bromine would be the one replacing Iodine.