Lionel Messi's post below is correct. Triatomic molecules (linear) have 7 degrees of freedom.
@camilleren_d17142 жыл бұрын
For rotational dof, why does it have to rotate only about C atom and why not around O atoms? Wouldn't the moment of inertia be higher?
@ZnNlove7 жыл бұрын
So if total DOF is given by the equation (3 * # of atoms), then how come gaseous Oxygen, O_2 has 5 DOF and not 6 if ur equation is to be used? I am confused
@lionelmessi14797 жыл бұрын
Actually the formula is (3 * #of atoms)-(# of bonds) This is what i found to be it in a few other videos as well and it works all the time but bear in mind there are exceptions in some cases. I don't understand why here they have used a different formula.
@hable71736 жыл бұрын
The degrees of freedom are not just limited to translational degrees of freedom, there are vibrational and rotational degrees of freedom too. However we tend to disregard the vibrational degrees of freedom in a gas as its insignificant
@devvratashtaputre63785 жыл бұрын
Vibrational DOF in diatomic molecule is absent,, hence just 5 DOF, same thing happens in case of all diatomic molecules
@MrKA19613 жыл бұрын
vibrational degrees of freedom at room temperature do not count because vibrational energy levels can be modified only at higher temperatures where collisions are sufficiently violent for vibrations to start. (see quantum mechanics) At low temperatures even rotational DOF can be neglected (bc. of slower motions do not result collisions violent enough to make molecules rotate) At room temperatures mainly translational and rotational DOF contribute to Cv.
@fractalnomics2 жыл бұрын
Does this mean if the CO2 molecule has 3 modes or emission spectra lines, these modes share the energy - equally?