Please sir check question 2 well .the the thirty-third point is 9 not 0
@FKacademy16 күн бұрын
If that is the case then, a+6d=12...eqn1 a+32d=9...eqn2 Subtract eqn1 from eqn2 to get: 26d=-3 Divide both sides by 26 d=-3/26 Put d=-3/26 into eqn1 to get: a+6(-3/26)=12 a=12+6/13 a=165/13 The sum of the first 69 terms will be: S69=69/2[2×165/13+(69-1)×-3/26] =7866/13 =605.08 to 2 d.p