True. Some design flaws. The grill too low and will smoke 💨 a lot

If you do not balance the chemical equation for burning wood with a design that allows 30 times air to fuel you will see poor combustion of which smoke is unburnt fuel from lack of air (oxygen).

With wood combustion we observe solid wood disappearing and it is converted into gas products, leaving some ashes. Air by volume: 78% Nitrogen, 20% Oxygen, 1% Argon and a fraction percent Carbon Dioxide. Air also contains a fraction percent of water vapor about 1% at sea level and less at altitude. Wood (fuel) is composed mainly of cellulose, that is an organic polymer made up by repetition of glucose (sugar) residues. Cellulose has a formula as C6 H10 O5. (6 Carbon, 10 Hydrogen and 5 Oxygen atoms) Wood composition varies by species but is thought of as 50% Carbon, 42% Oxygen, 6% Hydrogen, 1% Nitrogen and 1% other elements such as Calcium, Potassium, Sodium, Magnesium, Iron and Manganese. Fire is a rapid chemical reaction also called combustion or when slow is called smoldering. Combustion is a chemical process where some molecules are destroyed and new molecules are created. The balanced chemical equation for combustion requires 6 O2 molecules. (NOTE: One wood to six O2 molecules as a mixture is expressed as a 1:6 ratio) C6H12O6 + 6 O2 = 6 CO2 + 6 H2O 1 pound of seasoned wood requires at a minimum 6 pounds of O2 for good combustion. Since air is only 20% O2, it actually takes 30+ pounds of air to provide the required O2 (oxygen). One cubic foot of air at standard temperature and pressure (STP) weighs 0.0807 pounds. Hence, 30 lbs. / 0.0807 lbs/ft3 = 372 ft3 As combustion temperatures and stove warms the air weighs less per cubic unit so the volume of required air increases and the need to pre-heat air becomes important in optimizing a good combustion (stove) design. 9 times out of 10, poor combustion relates to lack of sufficient air (oxygen). ASK THE QUESTION "WHERE SHOULD THE AIR FLOW TO BENEFIT PRIMARY AND SECONDARY COMBUSTION?" Remember this is in a perfect stove... I doubt it exists, so always provide more air first... to improve combustion. If you see soot and smoke you need more air and higher temperatures. When organics (wood/biomass) burn, C-H bonds can be broken. Both C and H atoms form new bonds with Oxygen, yielding Carbon Dioxide CO2 and Water H2O. Oxygen is found in air as O2 molecules: CH4 (methane) + O2 = CO2 + H2O It is apparent, however, that one Oxygen molecule is not sufficient to burn (oxidize) one Methane molecule. Methane contains 5 atoms (1 C and 4 H). (Think about a balanced equation where the left = right) The C atom needs 2 O atoms to form one CO2 molecule. A couple of H atoms needs one O atom to form one H2O molecule, and there are two such couples. Summing up, the methane molecule requires 4 O atoms, that are found in 2 oxygen O2 molecules. From one methane molecule one carbon dioxide molecule is formed, containing the C atom, and two water molecules, containing the 4 hydrogen atoms. Two oxygen molecules are consumed to provide the 4 oxygen atoms. The full balanced (left=right) chemical equation is: CH4 + 2 O2 = CO2 + 2 H2O This is a balanced reaction. The numbers in front of the chemical formulas are the reaction coefficients. They indicate the ratios between numbers of molecules: for one methane molecule, two oxygen molecules must react, producing one molecule of carbon dioxide and two water molecules. With the proper coefficients, the reaction equation shows that the same number of atoms in the reagents is found in the products. (Left=Right) Complete Combustion is expressed as (for wood/biomass organics): CH2O + O2 > CO2 + H2O + Heat

You will have to try it some time. Thanks for watching!