Y−Parameters (Solved Problem 1)

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Neso Academy

Neso Academy

Күн бұрын

Network Theory: Y−Parameters (Solved Problem 1)
Topics discussed:
1) Step by step procedure to calculate the Y-parameters of the given two-port network.
2) Conversion of Z-parameters to Y-parameters.
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Music:
Axol x Alex Skrindo - You [NCS Release]
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Пікірлер: 62
@user-nw2of1xh9s
@user-nw2of1xh9s 3 ай бұрын
Underrated Channel, Amazing and clear explanation. Go ahead Sir.
@100courses7
@100courses7 2 жыл бұрын
Sir, U make the problem-solving look so easy. Amazing job sir. Honestly, your channel is underrated.
@soar_hub
@soar_hub 3 жыл бұрын
Thanks so much for your lessons!
@ravisumanthmuppana8383
@ravisumanthmuppana8383 3 жыл бұрын
The video is really informative .. Change the playback speed to 1.25x and thank me later
@Priyajit_Ghosh
@Priyajit_Ghosh Жыл бұрын
bruh, I am in 2x speed
@kapilumrania
@kapilumrania 3 жыл бұрын
You're god sent sir!!
@divyarao6280
@divyarao6280 5 жыл бұрын
After redrawing the circuit. We can use a short cut sir as it was a T network.... name the resistors as Ź a, zb and Zc...now Z parameters will be Za+zb Zb Zb Zb+Zc
@meerashende9470
@meerashende9470 5 жыл бұрын
Whats about -ve sign
@meerashende9470
@meerashende9470 5 жыл бұрын
How he gave -z12 n 21 we don't take like this whil calculating adj.
@VAISHNADEVIGECEUG-
@VAISHNADEVIGECEUG- 2 жыл бұрын
NICE AND DETAILED EXPLANATION SIR THANK YOU SIR
@sirjantudu7553
@sirjantudu7553 Жыл бұрын
thank you so much for clearing doubts
@venkatramansampath
@venkatramansampath 5 жыл бұрын
Thank you Sir for the video
@avethakur9198
@avethakur9198 3 жыл бұрын
We can also solve this problem by applying KVL in delta loop in circuit to obtain value of i' in form of i1 and can put it in our z parameters equations
@basarrimon3301
@basarrimon3301 10 ай бұрын
Yess
@vijayavardhantuntu5449
@vijayavardhantuntu5449 Жыл бұрын
Super Teaching sir ......Amazing ✨
@knoxxcruise6939
@knoxxcruise6939 5 жыл бұрын
Can we use I1=Y11V1+Y12V2 and I2=Y21V1+Y22V2 I
@srisaiteja9375
@srisaiteja9375 3 жыл бұрын
Love u sir 💜 from vizag
@rupayansahaakapglucifer598
@rupayansahaakapglucifer598 Жыл бұрын
The method shown is good but very lengthy. If you can convert this star network to delta or pi network and then directly using the short circuit admittance therom it will very easy and short
@avijitdeyelectrical1551
@avijitdeyelectrical1551 5 жыл бұрын
please sir upload more numerical problem on z , y parameter, h hybrids
@user-st9rw2vi3s
@user-st9rw2vi3s 3 жыл бұрын
I am getting Y11 = -Y21 = 31/260 and Y21 = - Y22 = 33/260
@nitishkumarprajapati6096
@nitishkumarprajapati6096 2 жыл бұрын
Thanks Sir 😃😃
@SarveshGupta-bu5ho
@SarveshGupta-bu5ho 5 жыл бұрын
Sir how to solve problem for capacitor and inductor
@securitynandhmoni1553
@securitynandhmoni1553 4 жыл бұрын
Which reference do you used🤔 please ,give a name
@ganeshrajjoshi7559
@ganeshrajjoshi7559 3 жыл бұрын
how can i solve if there is capacitor instead of 10ohm and 5ohm resistor
@nani2543
@nani2543 2 жыл бұрын
Directly we can solve through nodal analysis right ?
@venkattelugumusic472
@venkattelugumusic472 2 жыл бұрын
Thank you so much sir for your explanation mind blowing my doubt was cleared in jntua question paper the Z paramaeters are given but find y- Parameters like addmittence my mind is not working to see the question,after seen this video it's easly iam solved.thank you bro for these video 👌🙏🎇🎆😍😍
@UBUBYUTSE_REVIVAL_TV
@UBUBYUTSE_REVIVAL_TV 10 ай бұрын
Real answer are: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12
@syedameenali7361
@syedameenali7361 4 жыл бұрын
Can we convert the inner star to delta and apply kvl?
@starkendeavours7072
@starkendeavours7072 2 жыл бұрын
yes you can, both are convenient though.
@syedameenali7361
@syedameenali7361 2 жыл бұрын
@@starkendeavours7072 thanks 👍
@rachitmittal448
@rachitmittal448 Жыл бұрын
Sir can we solve the problem using KCL Equation? If we assume lower terminal as ground. Then V1 and V2 will be voltages as upper terminals. 20 ohm resistor between v1 and v2. T Network of other three in v1mand v2. We can assume A as intersection. Write KCL at 1,2,A.
@theaerogirl
@theaerogirl 5 ай бұрын
I got the same idea. Can`t we do that?
@abhinavkarn5090
@abhinavkarn5090 4 жыл бұрын
After changing from Delta to star......what happened to those 10ohm and 5 ohm resistors
@AcchuRocky
@AcchuRocky 4 жыл бұрын
All 3 resistors in delta is converted into 3 resistors in star form.. hence 20, 10, 5 ohms are disappeared to those 3 resistors..
@karthikvenkata6484
@karthikvenkata6484 2 жыл бұрын
I am getting different answers as Y11=0.025,Y12=-0.015,Y21=-0.025,Y22 =0.035
@UBUBYUTSE_REVIVAL_TV
@UBUBYUTSE_REVIVAL_TV 10 ай бұрын
Real answer are: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12
@sazidabintaislam2676
@sazidabintaislam2676 5 жыл бұрын
In Z12 and Z21, how did get - sign?
@levinraj2404
@levinraj2404 5 жыл бұрын
its matrics rule
@-MEET--mv1eb
@-MEET--mv1eb 5 жыл бұрын
Sir why whole current i2 will flow through 5 ohm only I think i2 will be divided into two branches initially through 5 ohm and 20 ohm
@rishabhprasad8333
@rishabhprasad8333 3 жыл бұрын
Same doubt
@avinashingle5491
@avinashingle5491 5 жыл бұрын
Sir pls provide transient topic of network which is most imp
@tanyashankar9966
@tanyashankar9966 2 жыл бұрын
can anyone please explain why can't we calculate simply y parameters simply from the circuit and not through the inverse process?
@happysingh6586
@happysingh6586 Жыл бұрын
i think we can do that also by using kirchoffs current law and write current equations
@UBUBYUTSE_REVIVAL_TV
@UBUBYUTSE_REVIVAL_TV 10 ай бұрын
Me I calculated by using circuit for addmittance without using impedance and I get the same answer. as follows: Y11=0.12,Y12=-0.11,Y21=-0.11,Y22 =0.12
@sumitsinghietlucknow7104
@sumitsinghietlucknow7104 5 жыл бұрын
Sir please make video on MATLAB
@rickjljr11
@rickjljr11 8 ай бұрын
>> z1=10 z1 = 10 >> z2=20 z2 = 20 >> z3=5 z3 = 5 >> Ya=1/z1 Ya = 0.10000 >> Yb=1/z2 Yb = 0.050000 >> Yc=1/z3 Yc = 0.20000 >> Y=[Ya+Yb, -Yb; -Yb, Yb+Yc] Y = 0.150000 -0.050000 -0.050000 0.250000 >> Zs=inverse(Y)+40*ones(2) Zs = 47.143 41.429 41.429 44.286 🙂
@biswadeepchakraborty2460
@biswadeepchakraborty2460 3 жыл бұрын
can we solve it directly using eq of Y parameters?
@JaspreetSingh-er2qr
@JaspreetSingh-er2qr 2 жыл бұрын
same doubt i have
@syedismail1849
@syedismail1849 Жыл бұрын
🔥🔥🔥
@anshumanmishra4172
@anshumanmishra4172 3 ай бұрын
Guys the best method is not this it is to use nodal analysis and directly obtain the Y parameters
@nesoacademy
@nesoacademy 3 ай бұрын
This lecture is not about the best method but the conventional method. This solution is important to set the tone for the upcoming lectures.
@hansrajbagaria794
@hansrajbagaria794 5 жыл бұрын
Sir why can't we take current(I2") through the 20 ohm resistor as : I2"= (V1-V2)/20. ??? Problem becomes very easy using the value of this current(I2") in terms of V1 and V2. I solved and got almost same answers not exactly the same. If anybody can tell my method is right or wrong? Thanks
@yashmahalle5675
@yashmahalle5675 5 жыл бұрын
Forget everything and use mesh analysis
@yashmahalle5675
@yashmahalle5675 5 жыл бұрын
Don't get complicated, use mesh analysis to calaculate current.
@s.m.senses7199
@s.m.senses7199 3 жыл бұрын
🙏❣
@theoldgamer3643
@theoldgamer3643 Жыл бұрын
13:32 / 13:53
@vinayadharsh9488
@vinayadharsh9488 8 ай бұрын
genco and transco exams 1minute to solve the answers how will be time sufficient and with out calculator.
@ranjithk1877
@ranjithk1877 4 жыл бұрын
Ok
@abinokselvin
@abinokselvin Жыл бұрын
Wheree did I²' & I²'' go
@prakharpandey7062
@prakharpandey7062 3 жыл бұрын
For delta to wye connection, refer to this video: kzfaq.info/get/bejne/bdSgZMdmyuCVmKc.html
@fyesilyurt
@fyesilyurt 4 жыл бұрын
Bu çıkmaz
@kishoreperam5162
@kishoreperam5162 3 жыл бұрын
Sir,after getting Z values, can't we get Y parameters just by reciprocal of Z values
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