5:28 I thought frequency was one over the period 1/p, not 1/(pi*p).
@cck0728 Жыл бұрын
I think that is for rising part of the signal....
@theomnivert Жыл бұрын
Thanks a lot man. This felt so easy once you explained it
@manueljenkin95 Жыл бұрын
I don’t think fast sampling and averaging removes flicker noise. It remains almost constant for all 4 samples and only the very fast white noise gets filtered by averaging either with a capacitor or by multiple sample averaging. The flicker noise is likely either removed by simple dsp curve fitting algorithms or by using analog band pass filters.
@manueljenkin95 Жыл бұрын
When capacitance becomes zero we do not need infinite voltage. It just becomes a singularity and disappears from the equation as an ideal wire.
@manueljenkin95 Жыл бұрын
Is the metal + oxide the region acting as capacitor (and maybe amplifier?) and is being read out? The photons whether they fall on p or n type semiconductor will cause electron hole pair, of which the electron will move to the edge of n type semiconductor from where it needs to be tapped into a readout. I think you did a great job at explaining visually but the 3 dimensional nature of the whole thing still poses challenges when visualised in 2d.
@MrCEHymowitz Жыл бұрын
Much of this advice is no longer applicable to most low voltage digital circuits. The only time to use a bead is NEVER. See kzfaq.info/sun/PLtq84kH8xZ9FNXAsf-odoGNe6h5A6D3in for current state of the art.
@wmlion1 Жыл бұрын
Thank you for video. Is there any book that you recommend about this subject, please?
@ambersmith6517 Жыл бұрын
thanks for doing what you are good at
@ambersmith6517 Жыл бұрын
you are a very good teacher my friend look up and God bless
@glenmartin24372 жыл бұрын
Thank you.
@Bianchi772 жыл бұрын
Nice video, keep it up, thanks for sharing :)
@user-bq6hv7ly5y2 жыл бұрын
Can u help me ? What about lvds 4 pin auto ? Bmw , audi?
@sridharchitta73212 жыл бұрын
The current (sinusoidal steady-state) in a capacitor is due to the resultant electric field E_net (resultant of the applied field and an opposing electric field, the fringe field). If the capacitance of the capacitor C is made large, then the fringe field does not build as fast as it would have if C were to be smaller. With a large C, the charge sprays on the plates do not result in developing a large voltage in a given interval of time as evident from the capacitor voltage-charge relation Q = CV. The fringe field is smaller and the net field consequently is greater. Therefore, at a fixed frequency, the current increases as the size of the capacitor is increased. The current also increases as the frequency is increased. So, we say it passes higher frequencies of applied voltage. If the frequency is made smaller, the fringe field builds very rapidly and in the limit when it is dc, it blocks the applied voltage. If a resistor R is connected to the capacitor then the resistor limited current is not enough to dump charge fast enough at such high frequencies and of sufficient quantity to produce any significant opposing fringe field. Therefore, for a given RC combination the output voltage picked across the resistor is able to reproduce the input signal with less attenuation. We say that the capacitor bypasses the high frequencies …..in reality, the electric field of the input voltage passes “through” the capacitor with almost no opposition. This makes the capacitor useful as a coupling capacitor for ac signals in amplifiers and also as an emitter bypass capacitor in transistors that will afford larger output swings by reducing the amount of ac signal feedback without affecting stabilising dc feedback. It is not possible in this post to discuss in more detail current in capacitor circuits and capacitive reactance. Electrostatics and circuits belong to one science not two. To learn the operation of circuits, Current and the conduction process, resistors and how discussing these topics makes it easier to understand the principle of superposition of potential which is a direct consequence of the principle of superposition applied to electric fields, watch these two videos i. kzfaq.info/get/bejne/irqkp5Vpx5fIiaM.html and ii. kzfaq.info/get/bejne/bqiBgMKp3Ji2lqM.html The last frame of video 1 contains in the References articles and textbooks which discuss the unified approach. Sections 3.1 to 3.3 in Chapter 3 of textbook 4 discuss the operation of the RC coupling circuit with sequential diagrams using the unified approach. Also, Section 3.6 in Chapter 3 of textbook 4 discusses the operation of the bypass capacitor tied across the emitter resistor using the unified approach with the help of sequential diagrams in a transistorised common-emitter amplifier.
@sridharchitta73212 жыл бұрын
The current (sinusoidal steady-state) in a capacitor is due to the resultant electric field E_net (resultant of the applied field and an opposing electric field, the fringe field). If the capacitance of the capacitor C is made large, then the fringe field does not build as fast as it would have if C were to be smaller. With a large C, the charge sprays on the plates do not result in developing a large voltage in a given interval of time as evident from the capacitor voltage-charge relation Q = CV. The fringe field is smaller and the net field consequently is greater. Therefore, at a fixed frequency, the current increases as the size of the capacitor is increased. The current also increases as the frequency is increased. So, we say it passes higher frequencies of applied voltage. If the frequency is made smaller, the fringe field builds very rapidly and in the limit when it is dc, it blocks the applied voltage. If a resistor R is connected to the capacitor then the resistor limited current is not enough to dump charge fast enough at such high frequencies and of sufficient quantity to produce any significant opposing fringe field. Therefore, for a given RC combination the output voltage picked across the resistor is able to reproduce the input signal with less attenuation. We say that the capacitor bypasses the high frequencies …..in reality, the electric field of the input voltage passes “through” the capacitor with almost no opposition. This makes the capacitor useful as a coupling capacitor for ac signals in amplifiers and also as an emitter bypass capacitor in transistors that will afford larger output swings by reducing the amount of ac signal feedback without affecting stabilising dc feedback. It is not possible in this post to discuss in more detail current in capacitor circuits and capacitive reactance. Electrostatics and circuits belong to one science not two. To learn the operation of circuits, Current and the conduction process, resistors and how discussing these topics makes it easier to understand the principle of superposition of potential which is a direct consequence of the principle of superposition applied to electric fields, watch these two videos i. kzfaq.info/get/bejne/irqkp5Vpx5fIiaM.html and ii. kzfaq.info/get/bejne/bqiBgMKp3Ji2lqM.html The last frame of video 1 contains in the References articles and textbooks which discuss the unified approach. Sections 3.1 to 3.3 in Chapter 3 of textbook 4 discuss the operation of the RC coupling circuit with sequential diagrams using the unified approach. Also, Section 3.6 in Chapter 3 of textbook 4 discusses the operation of the bypass capacitor tied across the emitter resistor using the unified approach with the help of sequential diagrams in a transistorised common-emitter amplifier.
@nikhilsen90072 жыл бұрын
Great Video. Made things very clear for me. I have a question: How is charge collected when there is oxide between n-silicon and metal?
@alejandroperez53682 жыл бұрын
Finally, I understood why a capacitor acting like a short circuit actually removed high frequency noise.
@souldog19712 жыл бұрын
We can here your toilet is running in the background. Go jiggle the handle
@hubercats3 жыл бұрын
Great tutorial. Thank you!
@JalapenoSoup3 жыл бұрын
Just finished the whole series. Man, you rock! Thank you for such clear explanations and precise drawings. Wish you were my professor back in my sensors course :)
@archie65863 жыл бұрын
🔥🔥🔥
@tuckfield6563 жыл бұрын
Great Job! Explains this convoluted topic succintly.
@khalfimoussa40413 жыл бұрын
Great video, I recommand it.
@caleb77993 жыл бұрын
why the fuck is there so much whistling??
@companymen423 жыл бұрын
Damn! An 8 bit adc for each pixel? That’s a fuck ton of transistors.
@baghdadiabdellatif15813 жыл бұрын
Great work thank you so much. Greetings from North Africa (Algeria)
@baghdadiabdellatif15813 жыл бұрын
Great work thank you so much. Greetings from North Africa (Algeria)
@baghdadiabdellatif15813 жыл бұрын
Great work thank you so much. Greetings from North Africa (Algeria)
@baghdadiabdellatif15813 жыл бұрын
Great work thank you so much. Greetings from North Africa (Algeria)
@kevinle47663 жыл бұрын
So with differential op amps, how do you determine positive or negative feedback?
@edvogel563 жыл бұрын
Thanks!
@arthurpc023 жыл бұрын
thanks a lot!
@theglobalgeek97783 жыл бұрын
Sir please explain about DI , BDI and CTIA. comparison of injection efficiency etc
@manojgutha56863 жыл бұрын
Why drop is more in decaps?
@somyagoyal60504 жыл бұрын
Hello sir I want to ask certain things that how will the ccd(silicon surface) segregate between the photons from the visible light ray or a uv ray ,so there can be some kind of distortion or noise if some x rays or UV rays are present in the environment where light is being captured??????¿
@zetaconvex19874 жыл бұрын
Excellent tutorial.
@Enkat4 жыл бұрын
Thanks you
@topquark224 жыл бұрын
I am trying to feed the AC-coupled signal into the input of an op-amp. The op-amp has a +/-5 V Vdd/Vcc bias. The input has a 0-5v bias.Since the input of the op-amp does not draw any current, how do I accommodate the requirement to draw the signal down to Vdd? Presumably after the cap stage? The frequency range is audio, say 10-10000Hz. Also keep in mind that the supply signal can only supply 35mA. Thanks.
@fullwaverecked4 жыл бұрын
What is the frequency of 5 volts?
@og76504 жыл бұрын
Is there really a separate capacitor at each pixel in real cameras?
@tramontz29984 жыл бұрын
Awesome
@jacopocanova75834 жыл бұрын
thanks for those videos! is it possible to move the ferrite bead just after the power supply or in between 2 bulk capacitors?
@qzorn44404 жыл бұрын
Wow, this lecture brings the photodiode info altogether. :~]
@shingoxy4 жыл бұрын
Could I repost this video to China web site?
@linchongwei68594 жыл бұрын
👍
@fsfss4 жыл бұрын
kzfaq.info/get/bejne/lauggqmH16rViok.html
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