The way you actually taught physics instead of math!

I have a question please help, we know when object comes downward PE will be -Mgh but you took +Mgh. Why?

Physics teacher here. Do you have any write up on how to put this together? Very cool demonstration.

Can you turn the music up? I can still hear the explanation.

amazing explanation

thank you Sir.

Friction

Shouldn't example 1 be 28.3m/s?

Besides that magnet is way to small to move the truck, the magnet will stick to the truck if it wasn't for that bar holding the magnet.

Yes! This IS the conservation of angular momentum! So many people don't explain the "why" aspect. Work is always done in such a manner that angular momentum is conserved. Amazing job!

Theses videos deserve many more views!

Cleared my concept very well ✅💯 thank uhh so muchh

99% awesome. (-1 because it sounded like you said “heighth” which isn’t a word).

Can equations be combined for various scenarios?? Just curious. Great video!

What if we only have like the distance between the two charges?

Of 4 videos ive watched on weightlessness this is the clearest because it is the only one that explains apparent weight. It may be possible to improve it further by also including a conceptual explanation of apparent weightlessness -- i.e. an explanation that is not formulated in terms of equations but only qualitatively, in terms of concepts. Here's how I understand this qualitatively (and this may be wrong...). Weight is mass times acceleration. Accelaration is relative to a frame of reference. If im in a free falling elevator, rellative to the elevator my accelaration is 0. So my (apparent) weight is 0. Does that make sense?

Thank you.

This is great, but is fails to mention one important thing, the coefficient of friction isnt static, it depends on the weight and center of Gravity of the car, because the heavier and higher the car, the more the weight transfer to the ouside wheels. And the thing with this is that the coefficient of friction varies not linearly with the supported weight on each wheel, so the biger the weight transfer, the lower the coefficient of friction of the tyres Still a like

Kinda of a long question, i apologize in advance. If we were to turn both of these cylinders into two separate hand powered bike tire air pumps, where each pump is moving the same volume of air with each complete stroke, except one has a smaller diameter piston but longer stroke and the other had a larger diameter piston but shorter stroke, would that mean the smaller diameter piston would require less input pressure to inflate a tire where as the larger piston would require more pressure, but inflate a tire quicker?

This is amazing! So helpful and concise. Thank you!

Thanks from india

So how do you make them double the dp ? That basically means I’m wasting my time wiring 2 speakers when I can just wire 1 cause 2 makes no difference?

That explanation doesn't work. It only explains the phenomenon in the part of the pipe where the diameter is reducing. Once you get into the smaller pipe section there is no acceleration, yet there is still lower pressure.

Thanks @INTEGRAL PHYSICS. Like @nozack5612 mentioned, the explanation through Newton's second is good but still left me missing an understanding of why the nozzle creates the pressure/velocity change. To round it out I offer this explanation (after researching more and thinking this through). My aha moment relies on considering the following: 1) static pressure fundamentally is a measure the fluid particles change in momentum to a surface (think walls of a container or more commonly the cross sectional area of a shape), and 2) continuity of mass flowrates between point 1 and 2 and the relation to incompressibility (i.e. the average number of particles in a given volume cannot change). Try to ignore the physical nozzle and imagine a setup where steady, incompressible flow goes from a larger diameter pipe to a smaller diameter pipe--the same fluid, the same density, the same mass flowrate. Take a cross section of the larger diameter pipe, there are more particle collisions (high static pressure) there because there are more particles flowing through that cross section at an instant in time. Now in a cross section of the smaller diameter pipe, with the same flow (i.e. flowrate) there are less particle collisions (low static pressure) because there are less particles flowing through that cross section at an instant in time. And since there are less particles in the cross section, to match the same mass flowrate as in the larger section the velocity must increase (i.e. the particles have to move faster through the pipe, otherwise that would mean the density is changing somewhere in the pipe!). Okay so working under that knowledge, how does a steady, incompressible fluid flow go from a larger diameter pipe section to a smaller diameter pipe section? A nozzle! I think the counter-intuitive part is that we expect the fluid to be squeezed by the nozzle getting smaller and that means a larger pressure right? Nope. That only happens if we take the same mass of non-moving fluid from a larger volume into a smaller volume. However, I think that does happen when talking about supersonic nozzles or fluids that are moving REALLY fast (i.e. Mach numbers greater than 1) because compressibility changes, but I haven't studied enough yet. That's my current understanding which still feels incomplete, but I hope that helps someone. I've been re-studying fluids for the FE exam which is why I'm here.

Man this guy newton is really destroying my childhood dream

Very good and simplified explanation.

Wish there was another spot for morhelp I have a reduction box so the gears don't make sense I have 4 sprockets total and I can't do the math what am I missing

I guess I'm just fuckin retarded cause I still don't get it

❤️🤣

How many are from india ❤

can you make a equation about gas leakage from pressurized tank? only given the volume, pressure, and the diameter of the leakage?

thank you this was really concise

Amazing videos. I completely feel ignorant of what seems like basic mechanical issues. The more you know, the more you realize you know nothing at all. Power, torque, speed, velocity, friction, tension, ratios, gears, teeth, pulleys, the materials used. It's endless. Who said the wheel was easy?

Wait! You just used Bernoulli (which is derived from Work-Energy) to support Newton. And then used Newton to justify Bernoulli in turn. How does that work?

hi, why do then water out of nozzle will sting on the skin more than water out of a pipe with no nozzle?

A pitot tube placed anywhere in your diagram will read the same everywhere. It is only the static pressure perpendicular to the flow that differs. The question remains, WHY does the static pressure drop when velocity goes up? I have an idea how it works. The particles spend less time in the higher speed area and so cannot exert as much pressure as they can when not moving. In addition the collisions they do have with the wall are at an oblique angle due to their speed and so less pressure is exerted. Imagine shooting a bb gun at the wall of a tank, it dumps all of its momentum into the wall but shoot the same bb gun at the walls of the inside of a tube and they just skip off keeping most their energy. ---->o| vs ---->o=====-->o Thoughts anyone?

how do i find the time period for this when its disturbed from equilibrium by ext force

thank youu i got my ans confirmed for my assignment

Great explanation, can you do a video showing how to Charge the ifp valve please ?

Shouldn’t radians be introduced to the Hohmann transfer?

Can you explain why hydrostatic pressure (rhogh) doesn't change between the two pipes even though one has a larger diameter so it has a higher colum of fluid

Wonderful video

Hello sir I am very confused about the concept of weighing machine measuring the normal force on it And also if it measures the normal force then why does it not measure Mg exerted by man + normal force

wow!!! brilliant!!! keep on doing great job man!

Does each brake heat up by 149⁰ or divided by 4, or the front brakes get hotter than the rear brakes so 149⁰C is not yet an answer is it?

Omg this vid is sooo helpful …

To much nagging. dislike bozo

I'm not sure if I'm understanding correctly, but it seems to me like a more intuitive understanding of the pressure relationship would be to look at the situation in reverse. I see the funneling as increasing pressure on the input side rather than decreasing pressure on the output 🤔

Learning indeed becomes fun when we have such wonderful teachers around us demonstrating experiments.

Thanks for this extensive video to find out if the tire pressure changes in the much higher altitude. My understanding is that the recommended cold tire pressure is based on 20C/68F at sea level in evenly shaded environment so the vehicle owners may adjusted their tire pressure accordingly based on their location, temperature & load. In Europe, cold tire pressure label in some vehicle have three listings: Standard = <100KM / High Speed= 160KM / ECO= same as High Speed due to some roads have no speed limit. To measure the contact patch correctly maybe jacking up the individual wheels before & after the drive, apply some coal or paint on the bottom of the tire and lower the tires down again to mark the patches accurately... that is, if someone really must know. Here are some references I have found related to tire pressure measurement: en.wikipedia.org/wiki/Cold_inflation_pressure#:~:text=Recommended%20cold%20inflation%20pressure%20is,when%20not%20warmed%20by%20driving. www.tirerack.com/upgrade-garage/does-altitude-change-tire-pressure www.rimex.com/wp-content/uploads/2020/05/understanding-cold-inflation-pressure.pdf