3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
3 жыл бұрын
Пікірлер
@Totalier 17 күн бұрын
🙏
@ashisghosh9349 Ай бұрын
Thank you so much sir
@PranavSuryawanshi1264 Ай бұрын
Hello sir I am doing my college project on waste mixer. On shaft the scre blades are fixed pls help me for calculation
@xyzdevil7765 Ай бұрын
Can you give the pdf of full notes?
@KarthyA-jc1kf Ай бұрын
sir how to assign a material for each components?
@pryansh-kw2lb Ай бұрын
Can we have more videos like fastners, gears , belts etc
@diplomajobfinding2024 Ай бұрын
Achha sir
@ankitsocial2644 2 ай бұрын
What about hollow shaft??
@DeepakKumar-mo2of 2 ай бұрын
Method of finding bending moment(Mb) is wrong .when load acting on the center of the shaft bending moment will be WL/4
@Y9096841236D 2 ай бұрын
At the centre of Shaft, bending moment changes it's sign, I.e. it is a point of contraflexure where Bending moment is zero.
@RajeshGurjar-em1ki 3 ай бұрын
Bikaner technical university ke liye sahi h kya syllabus
@RajeshGurjar-em1ki 3 ай бұрын
Sir ye notes pdf share karo
@adityamahure3311 3 ай бұрын
Sir in above problem calculation of value "b" .. and diameter of pin based on bending stress "d" that in sigmab is wrong.. Please reply
@Y9096841236D 3 ай бұрын
What is your answer for b
@Y9096841236D 3 ай бұрын
Is it 20
@ravibarha5160 3 ай бұрын
I think you did mistake in the calculation of the maximum torque my answer is 1375092N-mm Inner diameter=60.77mm Outer diameter=121.54mm
@kaustubhs.sakpal7691 3 ай бұрын
In step no. 4 socket diameter there is mistake. You multiplied π/4 with d1 square & gave + sign and in 9 multiplied by +d1 you gave minus sign. & 9 multiplied by -34 you gave + sign. Explain please
@Y9096841236D 3 ай бұрын
I think there is no mistake...it is just simplification of equation..still if you think there is mistake, please type here equation where you find difference
@aliatanerickson4543 3 ай бұрын
that mosquito was terrible
@Y9096841236D 3 ай бұрын
Mos was the part of quality checking of video...some students were frequently complaining about video quality [they were not able to see the text on page] but many were not facing issue and you are among them, you saw Mos means video quality is not that bad. 😉
@URaj253 3 ай бұрын
Nice explanation sir Very very thank you
@Y9096841236D 3 ай бұрын
Thanks for your comment💐💐💐
@Mechanical114 4 ай бұрын
NICE ONE
@Y9096841236D 4 ай бұрын
Thanks Sirji 😊
@otisdickinson4884 4 ай бұрын
I have a question, with regards to the bending stress moment arms, how do you consider these if the fork thickness is much much larger. For a design im working with, the fork thickness a is 2x the eye diameter and hughely overestimates bending.
@Y9096841236D 4 ай бұрын
kzfaq.info/get/bejne/pMqYfdynl7nJZps.htmlsi=9bVd1RVWRWImqO1W
@Y9096841236D 4 ай бұрын
Watch this video...you need to change Thickness of fork a=2d and derive the equation for bending stress. In Video I have used a=0.25d
@otisdickinson4884 4 ай бұрын
@@Y9096841236D thanks for your response. The part I am assessing is a 30mm long 2mm diameter pin connected between rod 8mm and lug of thickness 11mm each. As the pin is slender I believe it will deform so the contact area reduces prior to yield but unsure how to assess this
@sumitrawat2762 5 ай бұрын
In torsional moment why you have taken P=2πNMt/60x10^6 here why there is a 10^6 and how it comes and where it is written or given in books
@Y9096841236D 5 ай бұрын
10^6 gives you answer of calculated Power in KWatt. If you want Power in Watt just divide by 10^3
@Y9096841236D 5 ай бұрын
Further why 10^3 also required? Ans: Mt (Torque) in above equation has unit N-mm. So to convert N-mm to N-m, we need to divide by 1000 (or 10^3)
@Y9096841236D 5 ай бұрын
In totality, 1. To convert Torque N-mm to N-m we have divided by 10^3 2. To get Power in KW we have divideed by 10^3 3. 10^3*10^3=10^6
@akgamer3920 7 ай бұрын
In power eqn in denominator how 10^6 come
@Y9096841236D 7 ай бұрын
To get Power in KW, we are additionaly diving by 10^3
@nagendrak9769 7 ай бұрын
A rigid coupling transmits 40 kW at 150 rpm. The service factor for the application is 1.5 (take design torque as 1.5 times the mean torque). Select the suitable material for the various parts of the coupling. Take the material for shaft as 40C8 (Syt= 380 MPa), material for bolts is 30C8 (400 MPa) and flanges are made up of cast iron FG 150 (Sut=150 MPa). Take factor of safety as 2.5 for all components. Sir please solving the problem and answer send me sir please please please
@aakashkadam2937 7 ай бұрын
tommorow is my EndSem exam , this tutorial helped me a lot
@Complete501 7 ай бұрын
Isme 2 bearings kaise agayi
@sampathcm5054 7 ай бұрын
When should we use an equivalent torque equation?
@Y9096841236D 7 ай бұрын
In the above to calculate we have single value of Torque. But when a Shaft is subjected different Torque across the length, then we need to Calculate single value of Torque I.e. equivalent Torque by using Equivalent Torque equation. Now this single value of Equivalent Torque can be used to find Diameter
@sampathcm5054 7 ай бұрын
Sir please make vedios on SFD AND BMD
@luckyman4945 8 ай бұрын
❤TQ sir
@user-qb9ee2fs1t 8 ай бұрын
keep on!!!!!!
@ayonyawo1558 9 ай бұрын
why did you divide by 60x10^6 instead of just 60? I got lost there
@Y9096841236D 9 ай бұрын
Ohh ...let me clear that... P(KW) = 2*Pi*N*Mt/60*10^6 Here, 1. N is in RPM and we want to use N in RPS, So we are dividing by 60. If youn put N in RPS no need to decide by 60. 2. Unit of Torque Mt is in N-mm, but we want Mt in N-m. So divided by 10^3 3. So if divide by 60*10^3 the answer of power will be in Watt but as we want answer in KW we are futher dividing by 10^3. Hence, In totality we are diving by 60*10^6
@ayonyawo1558 9 ай бұрын
THANK YOU SIR @@Y9096841236D
@valr1658 9 ай бұрын
how to find permissible angle of twist
@Y9096841236D 9 ай бұрын
First thing Permissible Angle of Twist is not a parameter that we need to Calculate. Why? Because Permissible angle of twist indicates the value (Angle in degree or radian) within which twisting of shaft is allowed or permitted while transferring power. So Permissible Angle of Twist will be known to us or Can be taken from Design Data book and we can determine Shaft diameter which can keep twisting well below the Permissible Angle of Twist. Hope this is making sense
@valr1658 9 ай бұрын
@@Y9096841236D thanks I'll try
@mujammil4152 9 ай бұрын
35
@mujammil4152 9 ай бұрын
45
@daamjordanshadrach842 9 ай бұрын
Hi need assistance on a certain analysis on an augur
@kamalbhardwaj407 9 ай бұрын
Great 👍👍
@vineetkarmakar2305 10 ай бұрын
Sir you saved me in machine design I was confused about the knucle and cotter joints problems
@Y9096841236D 10 ай бұрын
Thanks @Vineet
@Sumitunstoppable 10 ай бұрын
How step number 5 second b is calculated
@Y9096841236D 10 ай бұрын
At 13.44 on left side, Equation of bending stress in Cotter is given, from which equation for b derived...and this is equation is used to calculate b
@umeshchavhan024 7 ай бұрын
The value is calculated as a 50.73 =b
@priyangshu7767 Жыл бұрын
Absolutely helpful in every way possible..thank you for the series of lectures on design...<3 <3
@Y9096841236D Жыл бұрын
Thanks for Positive Feedback 🙏 ☺️
@MrAvin-xj2oc Жыл бұрын
Sir please make video projection of solid🙏🙏🙏
@bksahal7601 Жыл бұрын
Sir you are a great. Sir what is Ssy or Syt ?
@Y9096841236D Жыл бұрын
Ssy=Yeild strength in Shear, Syt=Yeild Strength in Tension
@akinyemihabeeblahi387 Жыл бұрын
Thank you very much. What is the name of the examination the question was gotten from?
@Y9096841236D Жыл бұрын
This is from University Exam from Maharashtra, India
@swapnilawalekar334 Жыл бұрын
Please shear the rack pinion sliding.sliding force Used pneumatic cylinder. Who to calculate for cylinder stroke and rack stroke
@karimmamdouh8454 Жыл бұрын
great content. very helpfulll
@f3nunez Жыл бұрын
good job. what is yoour reference for the formulas
@Y9096841236D Жыл бұрын
Design of Machine Elements by Prof. V B Bhandari
@RicardoTakayama Жыл бұрын
Something seems strange in this analysis. The stresses shouldn't be permanent on the location where the part goes through, should it? The stresses should be just under the piece on the "time" the regions are in contact, not on all the time.
@harshvatre3348 Жыл бұрын
Sir your imperical equations are different from psg
@harshvatre3348 Жыл бұрын
These standard relations are different in psg. What should I do? Plz reply sir🙏🙏🙏🙏🙏🙏
@Y9096841236D Жыл бұрын
Definitely go with PSG if you are implementing these Concepts in Project
@Peace_loverboy Жыл бұрын
How to find Mb??
@Y9096841236D Жыл бұрын
From Power P(KW)= (2×Pi×N×Mb)÷(60000) put value of Power in KW, N is RPM, and get Mb
@Peace_loverboy Жыл бұрын
@@Y9096841236D thanks sir How to calculate factor of safety
@Y9096841236D Жыл бұрын
@@Peace_loverboy Fs we need to select. Thumb Rule, For Steel 1.5 to 3, CI 3 TO 5
@Peace_loverboy Жыл бұрын
@@Y9096841236D but how to select it?
@shahidshaikhs22 Ай бұрын
Using this we get torque not maximum bending moment@@Y9096841236D
@kunaljhariya7231 Жыл бұрын
mean torque is 11.45 x 10^5 N-mm
@user-mn6jd6kx6h 3 ай бұрын
Can you tell what's the correct answer of do and di
@ajsurvase Жыл бұрын
Thanks Sir
@sahilshinde3753 Жыл бұрын
thankyou sir but what if the stresses exceed the limit
@Y9096841236D Жыл бұрын
That is considered as failure means component is not safe. What we can do, either increase the dimensions or alter the material having higher strength. In our case, we increase the dimension.
@sidshinde8256 Жыл бұрын
Only u are the one in whole KZfaq who get question of grade and bearing thanks ❤️