3 bit & 4 bit Asynchronous Down Counter

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Neso Academy

Neso Academy

Күн бұрын

Digital Electronics: 3 bit and 4 bit Asynchronous Down Counter
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Пікірлер: 207
@shakyhand9648
@shakyhand9648 4 жыл бұрын
Watching this during the Corona Lockdown, when there are no Uni lectures and i was feeling totally lost! man thank you so much.
@nandukrishnan456
@nandukrishnan456 3 жыл бұрын
Same bruh
@saurabhgairola9145
@saurabhgairola9145 7 ай бұрын
This is not lockdown time and I am still watching
@ececse
@ececse 7 ай бұрын
​@@saurabhgairola9145end sem😂
@keshav_c17
@keshav_c17 7 жыл бұрын
for the second configuration a separate state table has to be made as the outputs are now changed. In 1st configuration they were in complement form i.e. Qa' Qb' Qc' but now in 2nd configuration they are as Qa Qb Qc . And while you analyzing the values of Qa, Qb, Qc i.e. output of 2nd configuration ( 8:29 - 8:37 ) you have compared it with the 1st configuration state table which making all the confusion in the audience.
@pronoob4890
@pronoob4890 2 жыл бұрын
4 saal beet gye hai tumhare iss comment ko. Ab tak toh tumhari job bhi lag gyi hogi ?
@keshav_c17
@keshav_c17 2 жыл бұрын
@@pronoob4890 haa bhai 😅
@vvksailor
@vvksailor 2 жыл бұрын
@@keshav_c17 kaha job karte ho? Aur iss question ka answer bhi bata do…
@ak689
@ak689 Жыл бұрын
@@keshav_c17 super senior 😁🙇
@mahendra756
@mahendra756 Жыл бұрын
@@pronoob4890 aab tak toh tumhari bhi lag gayi hogi mujhe v clear kara do yaar😂😂😂😂
@manishchetiwal1811
@manishchetiwal1811 4 жыл бұрын
Thank you sir for making video with great explanations.
@rushilsharma762
@rushilsharma762 8 жыл бұрын
In the second configuration, why did you start taking ouptput from the secomd clock pulse , and not from the initial state like you did in the first configuration?
@bitethebyte
@bitethebyte 3 жыл бұрын
Coz first output will be the same in any condition
@alasamuel5611
@alasamuel5611 Жыл бұрын
The best explanation i have got on counters so far
@vinayak186f3
@vinayak186f3 3 жыл бұрын
In the second circuit , set values of qa' qb' qc' as 1 initially and analyse qa qb qc accordingly .
@SuperCineraria
@SuperCineraria 6 жыл бұрын
for down counter consider from pulse 1 as it gives decimal 7... continue till 8th pulse to get 0. pulse 0 is not considered as we assume all flip flops to be in power down state (no memory stored so Qa, Qb & Qc are 0 initially) 0th pulse is same as 8th pulse
@ahmedelafifi6097
@ahmedelafifi6097 6 жыл бұрын
thanks for your great effort
@shruthisreedhar2149
@shruthisreedhar2149 3 жыл бұрын
Sir, You are my life saviour! The word thanks is not enough to show my gratitude..
@nithinsai2250
@nithinsai2250 3 жыл бұрын
Show your gratitude in cash
@osamaakhtar6525
@osamaakhtar6525 4 жыл бұрын
I dont understand in the second circuit you are complementing Qa prime before feeding it in the clk of Qb. So is that not the same of feeding Qa in the clock of Qb? does that not make it positive edge triggered?
@apoorvakaniti3941
@apoorvakaniti3941 4 жыл бұрын
Sir in the waveform diagram of down counter it looks like it is positive edge triggered rather than negative triggered. But you had said that down counter is negative triggered as well.
@heavenintheworld195
@heavenintheworld195 7 жыл бұрын
in the second circuit the graph or truth table follow the downward counter for complement outputs but how can you get the downward counter from not not complement outputs?
@duncanjr.5905
@duncanjr.5905 7 ай бұрын
awesome lecture, thank you!
@lastborn4sure
@lastborn4sure 8 жыл бұрын
i dont know how best i can thank you for this great lectures. please you have been using negative edge flip flop, if its positive edge, what will be the timing diagram?
@tenzindorjee7689
@tenzindorjee7689 9 ай бұрын
Awesome lecture series ❤
@ravichandranz
@ravichandranz 8 жыл бұрын
Thank you very much!
@SirJoco
@SirJoco 6 жыл бұрын
Thank you for the video. Great job you have done. But as far as I can see these two methods don't have the same result. In the first method initially it is 111 (as the compliment of 000) and that is fine, but in the second method we have 111 at the first impulse, and initially it is 000. Please comment.
@rockykumarverma980
@rockykumarverma980 3 жыл бұрын
It' not 000 it's 100 anyhow it's not equal to 111
@nakulchauhan6713
@nakulchauhan6713 6 жыл бұрын
Thank you for you videos...
@ibnuaziz3048
@ibnuaziz3048 21 күн бұрын
THANK YOU so much sir
@nigambehera4795
@nigambehera4795 7 жыл бұрын
sir did u had inverted the o/p? in both of the configuration
@niloykundu5946
@niloykundu5946 9 жыл бұрын
In the second configuration of the 3-bit up counter where you feed the negated flip flop output, why do you start the counting from the 1st clock pulse?? why do you not assign the value for the initial clock pulse??
@RahulMadhavan
@RahulMadhavan 5 жыл бұрын
The system is driven by Qa', Qb' and Qc'. There's an offset of one waveform to get all of these into zero state. Once that happens, it's just mimicking the first configuration.
@ir2001
@ir2001 4 жыл бұрын
Rahul Madhavan How does that answer his question? You've answered what happens after the max count which is way different than the OP's question which asks why the initial clock pulse is not considered?
@yashesvii
@yashesvii 4 жыл бұрын
@@ir2001 I would suggest that you observe the waveform diagram for the second circuit , the starting point is actually after the first timeperiod because the first wave is the end of the last wave
@ganeshs8145
@ganeshs8145 6 жыл бұрын
What happens if both the output and the clock to the next flipflop is taken out of negated output of flipflop? It still gives down counting right? Thanks
@sarojyadav082
@sarojyadav082 7 жыл бұрын
sir, it is necessary to show second circuit condition on waveform ???
@thalupulasridevi397
@thalupulasridevi397 2 жыл бұрын
just awesome sir
@youknowwho1940
@youknowwho1940 7 жыл бұрын
what happens when the 8th clock pulse edge is applied i mean does the counter go back to 111 ?
@kartikmudgal2127
@kartikmudgal2127 8 жыл бұрын
sir in second circuit what u considered initially is zero Qa=0,QB=0,QC=0 fr initial state
@faizashah2465
@faizashah2465 5 жыл бұрын
Difference between up and down counter?? Does it depend on if we are giving logic state high or low??
@FatihErdemKzlkaya
@FatihErdemKzlkaya 9 жыл бұрын
It is also possible to use positive edges instead of negative edges in a up counter to turn it into down counter.
@cheeragsridhar1696
@cheeragsridhar1696 Жыл бұрын
yes
@mihirvora391
@mihirvora391 Жыл бұрын
Yes for that we will use Qn as clock as well as output
@FatihErdemKzlkaya
@FatihErdemKzlkaya Жыл бұрын
@@mihirvora391 Well I've already graduated but thanks for reminding me what I went through lol
@anirudhani8160
@anirudhani8160 Жыл бұрын
@@FatihErdemKzlkayaiam going through the same
@FatihErdemKzlkaya
@FatihErdemKzlkaya Жыл бұрын
@@anirudhani8160 Good luck brother, you'll make it through. Enjoy those times, do not stress over it too much!
@bishalyogi7638
@bishalyogi7638 7 жыл бұрын
sir u are great....i like the way u explained...thanks a lot..
@Ramu9119
@Ramu9119 Жыл бұрын
Man you are awesome
@rohitgaddi482
@rohitgaddi482 5 жыл бұрын
In the second circuit ,initially we are taking 000 but initially there 010 because clock of second flip flop is already 1 as it is connected to qa complement which initially is 1 as qa is zero initiaally .pls explain
@kevalmistry7749
@kevalmistry7749 6 жыл бұрын
I have a question that why don't you use positive edge triggered FF's, can you pls explain!!
@codinguniversity8919
@codinguniversity8919 3 жыл бұрын
Everything that is concievable is clearly stated. Geat job.
@Baalika16
@Baalika16 3 жыл бұрын
How did we get graph(rise/fall) for the last Qc?
@HelloWorld40408
@HelloWorld40408 Жыл бұрын
Thank You Sir
@polasaibhargavgupta8301
@polasaibhargavgupta8301 3 жыл бұрын
we can also use positive edge triggering
@TechReveals
@TechReveals 4 жыл бұрын
loved it...Nice content..
@RB-kj3qe
@RB-kj3qe 6 жыл бұрын
in 2 nd method of down counter, for making waveform of Qc, can it is not follow the compliment of Qb of the previous method??
@sktttakx-_-9964
@sktttakx-_-9964 2 жыл бұрын
thx for the help
@krishanlakhiwal
@krishanlakhiwal 9 жыл бұрын
Just one suggestion.. Plz try to always tell about the next presentation topic so that it is easy to follow the lectures.. Coz youtube sometimes doesn't show the next video.. Or you can either number your videos.. That would be even better.. Nice work btw.
@sainimohit23
@sainimohit23 6 жыл бұрын
just open the playlist
@thomascarstens2729
@thomascarstens2729 6 жыл бұрын
kzfaq.info/get/bejne/pNWFlqakl-CykX0.html
@Pra_gyaPandey
@Pra_gyaPandey Жыл бұрын
​@@sainimohit23 yup
@sainimohit23
@sainimohit23 Жыл бұрын
@@Pra_gyaPandey OMG I used to watch videos of NESO academy lol
@Pra_gyaPandey
@Pra_gyaPandey Жыл бұрын
@@sainimohit23 haha 😂
@hiteshkumar8075
@hiteshkumar8075 6 жыл бұрын
Can i design a mod-5 asynchronous counter without using CLEAR Pin? I may use some sort of combinational circuit. Please Reply
@samirthegentlewind
@samirthegentlewind 3 жыл бұрын
don't we need to take preset for all flip flops in the second diagram? then only all the outputs would be high for first clock pulse right?
@amanchaudhary8817
@amanchaudhary8817 2 жыл бұрын
Thank you sir
@agstechnicalsupport
@agstechnicalsupport 2 жыл бұрын
Thank you !
@PriyanshuRaj-oc4tk
@PriyanshuRaj-oc4tk 4 жыл бұрын
At 8:20 you're reading 1,1,1 from the 1st clock pulse (triggering) but writing it down after initially in the table. Why is that so?
@user-xz1uj8yi1d
@user-xz1uj8yi1d Ай бұрын
since it was a down counter
@duonghan4782
@duonghan4782 5 жыл бұрын
In my text book, the down counter operates with Q1=Q2=Q3=1 at the initial state, not the complement of them equal to 1 (in which Q1=Q2=Q3=0, this is the initial state of UP counter). Hope you check it again. And anyway, you’re doing God’s work, keep it up. Thank you.
@anandchaudhari1483
@anandchaudhari1483 2 жыл бұрын
please explain
@anmol3457
@anmol3457 7 ай бұрын
well, the initial state of the DOWN counter, even if you take it as the complement of the initial state of of the UP counter (Q1 = Q2 = Q3 = 0), will be Q1 = Q2 = Q3 = 1, which is the correct initial state.
@Nomadicvib3
@Nomadicvib3 8 жыл бұрын
i have a doubt.in practical experiments,how do we connect preset and clear to ic chips in a bread board
@deepikagundabathula286
@deepikagundabathula286 Жыл бұрын
Thank you so much sir 😊
@meenayaduvanshi3583
@meenayaduvanshi3583 7 жыл бұрын
for -ve edge trigger please explain the waveform for down counter without taking up counter compliment,
@boombeachnoob3642
@boombeachnoob3642 4 жыл бұрын
here we are considering before first clock pulse Qa as 0 (zero ) what if it is 1 from initial ?
@talarivinodkumar5590
@talarivinodkumar5590 8 жыл бұрын
thank you very much
@debarshidas8593
@debarshidas8593 8 жыл бұрын
please help as to how in the second circuit u start taking output number 1 after 1st clock pulse and u don't take the initial state 000 into account..as you have done for other counters
@ArpanDasS
@ArpanDasS 7 жыл бұрын
same question here.
@alikhanmehboob610
@alikhanmehboob610 6 жыл бұрын
This is a down counter in which we count in reverse order. In the previous videos sir explained us UP counter in which we start counting in sequential order (000, 001 etc.)
@avishekchoudhury3395
@avishekchoudhury3395 4 жыл бұрын
well you all from assam..Hello.In the second circuit the clock values are taken as complimented so
@md.shazzadhossain3288
@md.shazzadhossain3288 4 жыл бұрын
@@alikhanmehboob610 that does not ans the question.
@Manpreet0891
@Manpreet0891 6 жыл бұрын
sir why you made 3 flip flops in 3bit and 4bit synchronous down counter??
@awabazhar806
@awabazhar806 3 жыл бұрын
Hey buddy. You are awesome man. Just splendid.I have completed a chapter from your Channel. I will be grateful to you vai.I am a Student of class Eleven. From Bangladesh 🇧🇩🇧🇩🇧🇩. Love you😘😘
@rajavignesh7216
@rajavignesh7216 11 ай бұрын
What will be the output if i take clock and output both as complemet (Qa,Qb,Qc)
@RahulSah-gd6pj
@RahulSah-gd6pj Жыл бұрын
thank you
@chiragshilwant886
@chiragshilwant886 5 жыл бұрын
If I want Q as output and Q only as a clock to nxt Flipflop then down counter be achieved using positive edge triggered clock.
@akashjai309
@akashjai309 4 жыл бұрын
It's only mandatory for B and C A is independent of it
@padigerimahendra4960
@padigerimahendra4960 7 ай бұрын
which circuit gives efficient design sir ?
@satyakibose8402
@satyakibose8402 7 жыл бұрын
Do I need to show both original outputs(i.e QA, QB, QC) and the complement of the outputs in the time diagram?
@anujbhattarai8493
@anujbhattarai8493 3 ай бұрын
If you draw the second one it is necessary but if draw the first circuit it isn't necessary to draw at all.
@mahesh_555
@mahesh_555 Жыл бұрын
can we use T flipflop instead of jk to logic -1?
@revo572
@revo572 4 жыл бұрын
Bro ur god during exams
@sarabsaeed3430
@sarabsaeed3430 4 жыл бұрын
oh may God ,lol.
@119_shrenikshah7
@119_shrenikshah7 3 жыл бұрын
Was there a 4bit down counter diagram?? I didn't notice any, please provide timestamp.
@55_hetpatel74
@55_hetpatel74 Жыл бұрын
i will contribute to you once i will start earning thankyou soomuch
@Kanyeeastttttt
@Kanyeeastttttt 5 жыл бұрын
you can use the up counter with positive edge triggering for down counting.but the initial state will be 0 and then it starts down counting from 2^n - 1.n = no of FFs
@ikshvaku_allegiance4015
@ikshvaku_allegiance4015 2 жыл бұрын
if you use the second method that sir told, then too the first clock pulse is 0 and downcounting starts from 1st pulse
@honeysunny1595
@honeysunny1595 8 жыл бұрын
ur videos are very helpful. In the second configuration of the 3-bit up counter where you feed the negated flip flop output, why do you start the counting from the 1st clock pulse?? why do you not assign the value for the initial clock pulse??
@abdullahmohammad5613
@abdullahmohammad5613 4 жыл бұрын
I had the same question, but it's the same thing really! You will start with (000) then (111 ) so you're basically going backward
@adolforojasespinoza9678
@adolforojasespinoza9678 8 жыл бұрын
Thank You, Great Videos, Nice English.
@faramutia1450
@faramutia1450 8 жыл бұрын
Dear Neso Academy, can you have a lecture video about asynchronous system: how to make the flow table, how to reduct the state through partitioning and using merge diagram. Or an example problem like vending machine? I hope you can help me. Thank you.
@bessaihabdelkadermahieddin9152
@bessaihabdelkadermahieddin9152 2 жыл бұрын
for the second config isnt it initially 000 ?
@sharmilashetty5680
@sharmilashetty5680 5 жыл бұрын
Fantastic
@rahulbera40
@rahulbera40 2 ай бұрын
Sir why u r not taking the initial values while calculating Qa,Qb, Qc for the 2nd ckt....pls solve this
@programminginbangla83
@programminginbangla83 7 жыл бұрын
thank you sir :)
@vrajdobariya1950
@vrajdobariya1950 3 жыл бұрын
Down counter’s wave form wrong , u have to take Qb on the bases of Qa’ and then u have to take Qb’ but u take Qb on bases of Qa . Am I right or wrong
@samundrabhandari8785
@samundrabhandari8785 2 жыл бұрын
I don't understand it can you explain it for the down counter for 4 bits?
@kaboom7899
@kaboom7899 3 жыл бұрын
thankyou dude
@fatimaashraf1074
@fatimaashraf1074 3 жыл бұрын
For 4 bit down counter ...t flipflop use or j k flip flop??
@aurangzaibvirk5677
@aurangzaibvirk5677 4 жыл бұрын
but sir u use initial stage for 7 in first circuit and in second circuit u use first falling edge to show decimal 7 ?????
@sandipanmajhi2770
@sandipanmajhi2770 6 жыл бұрын
in the second config the counting starts from 000 then 111 then 110 and so on ....
@ajwakhan7634
@ajwakhan7634 4 жыл бұрын
Can you plz explain for up and down by using d flip flop?
@akarshmittal112
@akarshmittal112 4 жыл бұрын
Using second method we have 000 initially and 111 for 1st falling edge, and we should consider initial pulse which makes the answer wrong. Someone please help me clarify the concept.
@arunjithr5984
@arunjithr5984 Жыл бұрын
What u said is correct its first coming 000 🥲
@crazyindian4650
@crazyindian4650 7 жыл бұрын
Mention msb and lsb for second configuration please..
@alikhanmehboob610
@alikhanmehboob610 6 жыл бұрын
Qa=lsb and Qc=msb
@luckyly114
@luckyly114 2 ай бұрын
Sir the title was down counter but you drew the table for up counter I didn't get it
@competitiveexampreparation4701
@competitiveexampreparation4701 2 жыл бұрын
Life saver before the exam ...
@nice-one
@nice-one 8 жыл бұрын
can u start with 2nd configuration 1st , 1st one is easy to understand but 2nd one gets messed up with 1st one ?
@AnkushKumar-qg2ei
@AnkushKumar-qg2ei 4 жыл бұрын
Clock is negatively triggered or positively trigvt
@NEERAJ0705
@NEERAJ0705 8 жыл бұрын
please upload Analog electronics video too.
@and1fer
@and1fer 9 жыл бұрын
In the second configuration of the down counter where we feed the negated flip flop output to the other, how do we start at '111' when Q_A is 0 initially?
@lwfabsman
@lwfabsman 8 жыл бұрын
+and1fer I'm sorry if it took 6 months to see to your question, but QA is zero, and we're using QA' (the compliment) as the input therefore of course its 1. because when you compliment 0 you get 1.
@gagandeepshergill9153
@gagandeepshergill9153 7 жыл бұрын
lwfabsman No he's talking about the logic 2 where the clock is different. QA is 0 there initially.
@utkarshgangwar8125
@utkarshgangwar8125 6 жыл бұрын
lwfabsman but i want to kno for the second circuit , here we take qa,qb,qc not the compliment and it should start with 000??
@manoojkumaarbalasubramania3878
@manoojkumaarbalasubramania3878 5 жыл бұрын
@@utkarshgangwar8125 my friend its starting with 000 and the next state is 111,110,101,100,011,010,001. After that it again goes to 000. In that way we get the downcounter logic. Next state of 000 is 111. Here logic is same don't confuse with what you get in the beginning.
@allanraju1570
@allanraju1570 5 жыл бұрын
Best sir👌👌👌💐💐
@samaysingh748
@samaysingh748 3 жыл бұрын
No one can beat neso academy in terms of detailed explanation
@Easy-Lectures1984
@Easy-Lectures1984 4 жыл бұрын
Pls upload any asynchronous sequential ckt problem
@Nomadicvib3
@Nomadicvib3 8 жыл бұрын
what is logic 1.how do we connect it while wiring ic chips
@samuelbarham8483
@samuelbarham8483 3 жыл бұрын
He just means that a high voltage is applied to all of the inputs (a logical "1") as opposed to a low voltage (a logical "0"). In terms of practically wiring up IC chips, I'm not sure how it's done -- I believe you have to select two voltage levels (no doubt based on the parameters of the chips themselves) to serve as the "low" and the "high" voltages. Hope that helps a bit!
@HiBye-ks5iw
@HiBye-ks5iw 3 жыл бұрын
Hello, how do I make it count down from 5 to 0?
@HiBye-ks5iw
@HiBye-ks5iw 3 жыл бұрын
Sorry, I meant count down from 6 to 0
@sumangalsaha237
@sumangalsaha237 8 жыл бұрын
Can't we take the output of the complement when complement is given as the clock?
@gagandeepshergill9153
@gagandeepshergill9153 7 жыл бұрын
Sumangal Saha No we can't because then it will become upcounter.
@aldisseferi6535
@aldisseferi6535 7 жыл бұрын
I was experimenting. Used same up counter, but with positive edge triggering, and my result was down counter. Is that true, or I made a mistake? :D
@bubunmazumder
@bubunmazumder 7 жыл бұрын
no,it's true..
@55_hetpatel74
@55_hetpatel74 Жыл бұрын
thanksssssssss GURUDEV
@mahendra756
@mahendra756 Жыл бұрын
I thought i was the only one confused at last but theres chaos in the comment😂😂😂😂 Plz someone help me to understand the last part
@reshinmk2076
@reshinmk2076 3 жыл бұрын
Can i design asynchronous down counter by t flip flop ?
@ganeshmula4508
@ganeshmula4508 3 жыл бұрын
S we can
@zhaonanliu1028
@zhaonanliu1028 2 жыл бұрын
How to pause and hold count
@nirupamasuryavanshi8790
@nirupamasuryavanshi8790 4 жыл бұрын
Great
@anuragkashyap9888
@anuragkashyap9888 4 жыл бұрын
Nice vedio
@zeeshankiyani2929
@zeeshankiyani2929 6 жыл бұрын
please done something with d-flip flop
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