Digital Electronics: 3 bit and 4 bit Asynchronous Down Counter Contribute: www.nesoacademy.org/donate Website ► www.nesoacademy.org/ Facebook ► goo.gl/Nt0PmB Twitter ► / nesoacademy Pinterest ► / nesoacademy
Пікірлер: 207
@shakyhand96484 жыл бұрын
Watching this during the Corona Lockdown, when there are no Uni lectures and i was feeling totally lost! man thank you so much.
@nandukrishnan4563 жыл бұрын
Same bruh
@saurabhgairola91457 ай бұрын
This is not lockdown time and I am still watching
@ececse7 ай бұрын
@@saurabhgairola9145end sem😂
@keshav_c177 жыл бұрын
for the second configuration a separate state table has to be made as the outputs are now changed. In 1st configuration they were in complement form i.e. Qa' Qb' Qc' but now in 2nd configuration they are as Qa Qb Qc . And while you analyzing the values of Qa, Qb, Qc i.e. output of 2nd configuration ( 8:29 - 8:37 ) you have compared it with the 1st configuration state table which making all the confusion in the audience.
@pronoob48902 жыл бұрын
4 saal beet gye hai tumhare iss comment ko. Ab tak toh tumhari job bhi lag gyi hogi ?
@keshav_c172 жыл бұрын
@@pronoob4890 haa bhai 😅
@vvksailor2 жыл бұрын
@@keshav_c17 kaha job karte ho? Aur iss question ka answer bhi bata do…
@ak689 Жыл бұрын
@@keshav_c17 super senior 😁🙇
@mahendra756 Жыл бұрын
@@pronoob4890 aab tak toh tumhari bhi lag gayi hogi mujhe v clear kara do yaar😂😂😂😂
@manishchetiwal18114 жыл бұрын
Thank you sir for making video with great explanations.
@rushilsharma7628 жыл бұрын
In the second configuration, why did you start taking ouptput from the secomd clock pulse , and not from the initial state like you did in the first configuration?
@bitethebyte3 жыл бұрын
Coz first output will be the same in any condition
@alasamuel5611 Жыл бұрын
The best explanation i have got on counters so far
@vinayak186f33 жыл бұрын
In the second circuit , set values of qa' qb' qc' as 1 initially and analyse qa qb qc accordingly .
@SuperCineraria6 жыл бұрын
for down counter consider from pulse 1 as it gives decimal 7... continue till 8th pulse to get 0. pulse 0 is not considered as we assume all flip flops to be in power down state (no memory stored so Qa, Qb & Qc are 0 initially) 0th pulse is same as 8th pulse
@ahmedelafifi60976 жыл бұрын
thanks for your great effort
@shruthisreedhar21493 жыл бұрын
Sir, You are my life saviour! The word thanks is not enough to show my gratitude..
@nithinsai22503 жыл бұрын
Show your gratitude in cash
@osamaakhtar65254 жыл бұрын
I dont understand in the second circuit you are complementing Qa prime before feeding it in the clk of Qb. So is that not the same of feeding Qa in the clock of Qb? does that not make it positive edge triggered?
@apoorvakaniti39414 жыл бұрын
Sir in the waveform diagram of down counter it looks like it is positive edge triggered rather than negative triggered. But you had said that down counter is negative triggered as well.
@heavenintheworld1957 жыл бұрын
in the second circuit the graph or truth table follow the downward counter for complement outputs but how can you get the downward counter from not not complement outputs?
@duncanjr.59057 ай бұрын
awesome lecture, thank you!
@lastborn4sure8 жыл бұрын
i dont know how best i can thank you for this great lectures. please you have been using negative edge flip flop, if its positive edge, what will be the timing diagram?
@tenzindorjee76899 ай бұрын
Awesome lecture series ❤
@ravichandranz8 жыл бұрын
Thank you very much!
@SirJoco6 жыл бұрын
Thank you for the video. Great job you have done. But as far as I can see these two methods don't have the same result. In the first method initially it is 111 (as the compliment of 000) and that is fine, but in the second method we have 111 at the first impulse, and initially it is 000. Please comment.
@rockykumarverma9803 жыл бұрын
It' not 000 it's 100 anyhow it's not equal to 111
@nakulchauhan67136 жыл бұрын
Thank you for you videos...
@ibnuaziz304821 күн бұрын
THANK YOU so much sir
@nigambehera47957 жыл бұрын
sir did u had inverted the o/p? in both of the configuration
@niloykundu59469 жыл бұрын
In the second configuration of the 3-bit up counter where you feed the negated flip flop output, why do you start the counting from the 1st clock pulse?? why do you not assign the value for the initial clock pulse??
@RahulMadhavan5 жыл бұрын
The system is driven by Qa', Qb' and Qc'. There's an offset of one waveform to get all of these into zero state. Once that happens, it's just mimicking the first configuration.
@ir20014 жыл бұрын
Rahul Madhavan How does that answer his question? You've answered what happens after the max count which is way different than the OP's question which asks why the initial clock pulse is not considered?
@yashesvii4 жыл бұрын
@@ir2001 I would suggest that you observe the waveform diagram for the second circuit , the starting point is actually after the first timeperiod because the first wave is the end of the last wave
@ganeshs81456 жыл бұрын
What happens if both the output and the clock to the next flipflop is taken out of negated output of flipflop? It still gives down counting right? Thanks
@sarojyadav0827 жыл бұрын
sir, it is necessary to show second circuit condition on waveform ???
@thalupulasridevi3972 жыл бұрын
just awesome sir
@youknowwho19407 жыл бұрын
what happens when the 8th clock pulse edge is applied i mean does the counter go back to 111 ?
@kartikmudgal21278 жыл бұрын
sir in second circuit what u considered initially is zero Qa=0,QB=0,QC=0 fr initial state
@faizashah24655 жыл бұрын
Difference between up and down counter?? Does it depend on if we are giving logic state high or low??
@FatihErdemKzlkaya9 жыл бұрын
It is also possible to use positive edges instead of negative edges in a up counter to turn it into down counter.
@cheeragsridhar1696 Жыл бұрын
yes
@mihirvora391 Жыл бұрын
Yes for that we will use Qn as clock as well as output
@FatihErdemKzlkaya Жыл бұрын
@@mihirvora391 Well I've already graduated but thanks for reminding me what I went through lol
@anirudhani8160 Жыл бұрын
@@FatihErdemKzlkayaiam going through the same
@FatihErdemKzlkaya Жыл бұрын
@@anirudhani8160 Good luck brother, you'll make it through. Enjoy those times, do not stress over it too much!
@bishalyogi76387 жыл бұрын
sir u are great....i like the way u explained...thanks a lot..
@Ramu9119 Жыл бұрын
Man you are awesome
@rohitgaddi4825 жыл бұрын
In the second circuit ,initially we are taking 000 but initially there 010 because clock of second flip flop is already 1 as it is connected to qa complement which initially is 1 as qa is zero initiaally .pls explain
@kevalmistry77496 жыл бұрын
I have a question that why don't you use positive edge triggered FF's, can you pls explain!!
@codinguniversity89193 жыл бұрын
Everything that is concievable is clearly stated. Geat job.
@Baalika163 жыл бұрын
How did we get graph(rise/fall) for the last Qc?
@HelloWorld40408 Жыл бұрын
Thank You Sir
@polasaibhargavgupta83013 жыл бұрын
we can also use positive edge triggering
@TechReveals4 жыл бұрын
loved it...Nice content..
@RB-kj3qe6 жыл бұрын
in 2 nd method of down counter, for making waveform of Qc, can it is not follow the compliment of Qb of the previous method??
@sktttakx-_-99642 жыл бұрын
thx for the help
@krishanlakhiwal9 жыл бұрын
Just one suggestion.. Plz try to always tell about the next presentation topic so that it is easy to follow the lectures.. Coz youtube sometimes doesn't show the next video.. Or you can either number your videos.. That would be even better.. Nice work btw.
@sainimohit236 жыл бұрын
just open the playlist
@thomascarstens27296 жыл бұрын
kzfaq.info/get/bejne/pNWFlqakl-CykX0.html
@Pra_gyaPandey Жыл бұрын
@@sainimohit23 yup
@sainimohit23 Жыл бұрын
@@Pra_gyaPandey OMG I used to watch videos of NESO academy lol
@Pra_gyaPandey Жыл бұрын
@@sainimohit23 haha 😂
@hiteshkumar80756 жыл бұрын
Can i design a mod-5 asynchronous counter without using CLEAR Pin? I may use some sort of combinational circuit. Please Reply
@samirthegentlewind3 жыл бұрын
don't we need to take preset for all flip flops in the second diagram? then only all the outputs would be high for first clock pulse right?
@amanchaudhary88172 жыл бұрын
Thank you sir
@agstechnicalsupport2 жыл бұрын
Thank you !
@PriyanshuRaj-oc4tk4 жыл бұрын
At 8:20 you're reading 1,1,1 from the 1st clock pulse (triggering) but writing it down after initially in the table. Why is that so?
@user-xz1uj8yi1dАй бұрын
since it was a down counter
@duonghan47825 жыл бұрын
In my text book, the down counter operates with Q1=Q2=Q3=1 at the initial state, not the complement of them equal to 1 (in which Q1=Q2=Q3=0, this is the initial state of UP counter). Hope you check it again. And anyway, you’re doing God’s work, keep it up. Thank you.
@anandchaudhari14832 жыл бұрын
please explain
@anmol34577 ай бұрын
well, the initial state of the DOWN counter, even if you take it as the complement of the initial state of of the UP counter (Q1 = Q2 = Q3 = 0), will be Q1 = Q2 = Q3 = 1, which is the correct initial state.
@Nomadicvib38 жыл бұрын
i have a doubt.in practical experiments,how do we connect preset and clear to ic chips in a bread board
@deepikagundabathula286 Жыл бұрын
Thank you so much sir 😊
@meenayaduvanshi35837 жыл бұрын
for -ve edge trigger please explain the waveform for down counter without taking up counter compliment,
@boombeachnoob36424 жыл бұрын
here we are considering before first clock pulse Qa as 0 (zero ) what if it is 1 from initial ?
@talarivinodkumar55908 жыл бұрын
thank you very much
@debarshidas85938 жыл бұрын
please help as to how in the second circuit u start taking output number 1 after 1st clock pulse and u don't take the initial state 000 into account..as you have done for other counters
@ArpanDasS7 жыл бұрын
same question here.
@alikhanmehboob6106 жыл бұрын
This is a down counter in which we count in reverse order. In the previous videos sir explained us UP counter in which we start counting in sequential order (000, 001 etc.)
@avishekchoudhury33954 жыл бұрын
well you all from assam..Hello.In the second circuit the clock values are taken as complimented so
@md.shazzadhossain32884 жыл бұрын
@@alikhanmehboob610 that does not ans the question.
@Manpreet08916 жыл бұрын
sir why you made 3 flip flops in 3bit and 4bit synchronous down counter??
@awabazhar8063 жыл бұрын
Hey buddy. You are awesome man. Just splendid.I have completed a chapter from your Channel. I will be grateful to you vai.I am a Student of class Eleven. From Bangladesh 🇧🇩🇧🇩🇧🇩. Love you😘😘
@rajavignesh721611 ай бұрын
What will be the output if i take clock and output both as complemet (Qa,Qb,Qc)
@RahulSah-gd6pj Жыл бұрын
thank you
@chiragshilwant8865 жыл бұрын
If I want Q as output and Q only as a clock to nxt Flipflop then down counter be achieved using positive edge triggered clock.
@akashjai3094 жыл бұрын
It's only mandatory for B and C A is independent of it
@padigerimahendra49607 ай бұрын
which circuit gives efficient design sir ?
@satyakibose84027 жыл бұрын
Do I need to show both original outputs(i.e QA, QB, QC) and the complement of the outputs in the time diagram?
@anujbhattarai84933 ай бұрын
If you draw the second one it is necessary but if draw the first circuit it isn't necessary to draw at all.
@mahesh_555 Жыл бұрын
can we use T flipflop instead of jk to logic -1?
@revo5724 жыл бұрын
Bro ur god during exams
@sarabsaeed34304 жыл бұрын
oh may God ,lol.
@119_shrenikshah73 жыл бұрын
Was there a 4bit down counter diagram?? I didn't notice any, please provide timestamp.
@55_hetpatel74 Жыл бұрын
i will contribute to you once i will start earning thankyou soomuch
@Kanyeeastttttt5 жыл бұрын
you can use the up counter with positive edge triggering for down counting.but the initial state will be 0 and then it starts down counting from 2^n - 1.n = no of FFs
@ikshvaku_allegiance40152 жыл бұрын
if you use the second method that sir told, then too the first clock pulse is 0 and downcounting starts from 1st pulse
@honeysunny15958 жыл бұрын
ur videos are very helpful. In the second configuration of the 3-bit up counter where you feed the negated flip flop output, why do you start the counting from the 1st clock pulse?? why do you not assign the value for the initial clock pulse??
@abdullahmohammad56134 жыл бұрын
I had the same question, but it's the same thing really! You will start with (000) then (111 ) so you're basically going backward
@adolforojasespinoza96788 жыл бұрын
Thank You, Great Videos, Nice English.
@faramutia14508 жыл бұрын
Dear Neso Academy, can you have a lecture video about asynchronous system: how to make the flow table, how to reduct the state through partitioning and using merge diagram. Or an example problem like vending machine? I hope you can help me. Thank you.
@bessaihabdelkadermahieddin91522 жыл бұрын
for the second config isnt it initially 000 ?
@sharmilashetty56805 жыл бұрын
Fantastic
@rahulbera402 ай бұрын
Sir why u r not taking the initial values while calculating Qa,Qb, Qc for the 2nd ckt....pls solve this
@programminginbangla837 жыл бұрын
thank you sir :)
@vrajdobariya19503 жыл бұрын
Down counter’s wave form wrong , u have to take Qb on the bases of Qa’ and then u have to take Qb’ but u take Qb on bases of Qa . Am I right or wrong
@samundrabhandari87852 жыл бұрын
I don't understand it can you explain it for the down counter for 4 bits?
@kaboom78993 жыл бұрын
thankyou dude
@fatimaashraf10743 жыл бұрын
For 4 bit down counter ...t flipflop use or j k flip flop??
@aurangzaibvirk56774 жыл бұрын
but sir u use initial stage for 7 in first circuit and in second circuit u use first falling edge to show decimal 7 ?????
@sandipanmajhi27706 жыл бұрын
in the second config the counting starts from 000 then 111 then 110 and so on ....
@ajwakhan76344 жыл бұрын
Can you plz explain for up and down by using d flip flop?
@akarshmittal1124 жыл бұрын
Using second method we have 000 initially and 111 for 1st falling edge, and we should consider initial pulse which makes the answer wrong. Someone please help me clarify the concept.
@arunjithr5984 Жыл бұрын
What u said is correct its first coming 000 🥲
@crazyindian46507 жыл бұрын
Mention msb and lsb for second configuration please..
@alikhanmehboob6106 жыл бұрын
Qa=lsb and Qc=msb
@luckyly1142 ай бұрын
Sir the title was down counter but you drew the table for up counter I didn't get it
@competitiveexampreparation47012 жыл бұрын
Life saver before the exam ...
@nice-one8 жыл бұрын
can u start with 2nd configuration 1st , 1st one is easy to understand but 2nd one gets messed up with 1st one ?
@AnkushKumar-qg2ei4 жыл бұрын
Clock is negatively triggered or positively trigvt
@NEERAJ07058 жыл бұрын
please upload Analog electronics video too.
@and1fer9 жыл бұрын
In the second configuration of the down counter where we feed the negated flip flop output to the other, how do we start at '111' when Q_A is 0 initially?
@lwfabsman8 жыл бұрын
+and1fer I'm sorry if it took 6 months to see to your question, but QA is zero, and we're using QA' (the compliment) as the input therefore of course its 1. because when you compliment 0 you get 1.
@gagandeepshergill91537 жыл бұрын
lwfabsman No he's talking about the logic 2 where the clock is different. QA is 0 there initially.
@utkarshgangwar81256 жыл бұрын
lwfabsman but i want to kno for the second circuit , here we take qa,qb,qc not the compliment and it should start with 000??
@manoojkumaarbalasubramania38785 жыл бұрын
@@utkarshgangwar8125 my friend its starting with 000 and the next state is 111,110,101,100,011,010,001. After that it again goes to 000. In that way we get the downcounter logic. Next state of 000 is 111. Here logic is same don't confuse with what you get in the beginning.
@allanraju15705 жыл бұрын
Best sir👌👌👌💐💐
@samaysingh7483 жыл бұрын
No one can beat neso academy in terms of detailed explanation
@Easy-Lectures19844 жыл бұрын
Pls upload any asynchronous sequential ckt problem
@Nomadicvib38 жыл бұрын
what is logic 1.how do we connect it while wiring ic chips
@samuelbarham84833 жыл бұрын
He just means that a high voltage is applied to all of the inputs (a logical "1") as opposed to a low voltage (a logical "0"). In terms of practically wiring up IC chips, I'm not sure how it's done -- I believe you have to select two voltage levels (no doubt based on the parameters of the chips themselves) to serve as the "low" and the "high" voltages. Hope that helps a bit!
@HiBye-ks5iw3 жыл бұрын
Hello, how do I make it count down from 5 to 0?
@HiBye-ks5iw3 жыл бұрын
Sorry, I meant count down from 6 to 0
@sumangalsaha2378 жыл бұрын
Can't we take the output of the complement when complement is given as the clock?
@gagandeepshergill91537 жыл бұрын
Sumangal Saha No we can't because then it will become upcounter.
@aldisseferi65357 жыл бұрын
I was experimenting. Used same up counter, but with positive edge triggering, and my result was down counter. Is that true, or I made a mistake? :D
@bubunmazumder7 жыл бұрын
no,it's true..
@55_hetpatel74 Жыл бұрын
thanksssssssss GURUDEV
@mahendra756 Жыл бұрын
I thought i was the only one confused at last but theres chaos in the comment😂😂😂😂 Plz someone help me to understand the last part
@reshinmk20763 жыл бұрын
Can i design asynchronous down counter by t flip flop ?