Analyzing diode circuits using the ideal diode model
Пікірлер: 13
@99redninjas6 жыл бұрын
I immensely appreciate this video. Great thorough explanation.
@prashantbhatta87595 жыл бұрын
So effective tutorial , tons of thanks to you man :)
@ezgiboz66603 жыл бұрын
thank you so much
@abdullahal-qadi36444 жыл бұрын
Thank you 🙏🏻
@JuGGerJuGGs8 жыл бұрын
So if both are conducting, then how can there be a current in the D1 branch? Vb = 0 volts and the other end of D1 is connected to ground, so how is there a potential for the current to flow?
@brinton4178 жыл бұрын
+JuGGerJuGGs We are using an ideal model - ie. the diode acts as an ideal switch with no voltage drop across it. Because the lower side of the 5 K ohm resistor is tied to -10 volts, there is a 10 volt drop across the 5 k ohm resistor which draws 10 mA. But only 1 mA comes through the 10 k Ohm resistor. The other 1 mA comes through D1 from ground. In reality, there is approximately a .7 V drop across the diode needed to overcome the junction potential Vo
@manuelsojan90936 жыл бұрын
if we assume D1 is on and D2 is off, how would we know if the voltage drop across 10 k-ohm resistor doesn't exceed 10 volts, making the node voltage less than 0 at the node right above D2? Wouldn't that then mean D2 is off?
@luisqylalli70318 жыл бұрын
thanks man !!!
@ayeshapanchavi80937 жыл бұрын
if we change the resistors, it means 5 K to 10 and 10 K to 5 K,what will happen? can u explain?
@iMAANfinity4 жыл бұрын
can we use piecewise linear model as assumption which Vgamma =0.7v? hence give Vb =0.7v.I need your replyy