L4 1 4Ideal Diode Conducting or Not Part 1

Рет қаралды 76,690

Lee Brinton

9 жыл бұрын

Analyzing diode circuits using the ideal diode model

Пікірлер: 43

@sunnyleung7118 5 жыл бұрын

For people who are still confused, here are what you should know: If there is no current flow, resister will not consume energy/voltage, therefore no voltage drop across resistor. Think of current as it was water flow, voltage is the pushing force to the water, if 1:there is current flow, resistor will "resist" current flow such that there is a voltage drop across resistor according to Ohm's Law, thats the resistor will "push back" the driving force(voltage) such that it matches the driving force of the other end of the resistor, thus voltage drop will be 5V. if 2: there is no current flow, resistor do not consume energy/voltage because V=IR I=0 V=0, in terms of water, there is no water flow, but the driving force is still here and still "pushing" although there is no water flow, thus voltage will not drop if there is no current.

@luciamonedero1999 4 жыл бұрын

Shouldn't it be 0-(-5)=5V in c)?

@leochung3245 2 жыл бұрын

Ya the answers of my book is -5v

@WillowWarrenFarms 4 жыл бұрын

Great explanation on the way diodes conduct. Very clear and gets to the point. Great job!

@MrHusseinhijazi 7 жыл бұрын

wow. thank you so much. very helpful, straight to the point and easy explanation.

@Odnsnchickedn 9 жыл бұрын

Thank you sir. Very helpful and straight to the point

@manuelsojan9093 5 жыл бұрын

part c is +5 V...The way V is labelled, it is the voltage across the diode, not the node voltage

@husamalardah890 4 жыл бұрын

yes i was thinking the same thing.

@karabgut 4 жыл бұрын

This course is perfect,thanks sir :)

@TheVeemon Жыл бұрын

Thanks for the help, understood how diodes works in less than 10 minutes

@danielstoy171 4 жыл бұрын

Great video! Really helped

@raymondholidjaja3371 6 жыл бұрын

really helpful prior to my quiz!

@ishowhalal 3 жыл бұрын

Amazing

@ieatcrayons3322 3 жыл бұрын

Thank you sir.

@jaysurya3313 3 жыл бұрын

Thanks 👍😍😊

@pipilzin 4 жыл бұрын

Salt Lake Community College ... my Alma Matter for my generals and EE first courses before transfering to the U !!

@davidpower2054 8 жыл бұрын

What videos should I see, in order to fully understand this tutorial

@hamto1416 8 жыл бұрын

perfect

@ezgiboz6660 3 жыл бұрын

thank you sir

@omarDgenrationX 6 жыл бұрын

excuse me , but i don't get why only one diode can be conducting in the 3 diodes problem .. can u repeat it ?

@NVMElectronic 9 жыл бұрын

wonderful :D ur explaination's very clear :D

@MsAbrar43 6 жыл бұрын

I Still don't get it :(

@TechNewsZone 4 жыл бұрын

In problem (e) 1v will conduct because time taken for f/b is least one. So my point of 1v conduct is that right.

@JurekPrzezdziecki 3 жыл бұрын

In real life situation the (a) Vo should be 0,7V - not 0V. Right?

@appahoopjack2514 5 жыл бұрын

Why is there NO Voltage Drop across that Diode in A?

@RingmasterRoss 5 жыл бұрын

It’s an ideal diode so it can essentially be replaced by a short as long as it is forward biased which it is. Thinking of it as a short means any voltage drop would not make sense.

@jonesmath 5 жыл бұрын

Shouldn’t there be a voltage drop across the diodes in e and f. So shouldn’t it be 2.3 in e be a of the 0.7v voltage drop across that diode and likewise for f.

@jessenunez1718 10 ай бұрын

he is talking about Ideal Diodes so 0V, I believe you are referring to Practical Diodes, which makes you statement correct.

@jorgema41 6 жыл бұрын

on Part D why is the voltage 0

@regale5359 3 жыл бұрын

Because its an ideal diode and voltage drop across ideal diode is zero and v is voltage across ideal diode hence v=0

@acidburner1058 7 жыл бұрын

So in ideal diodes, they can be ON whenever they have a zero or more voltage at their anode? meaning they don't need to have a forward bias voltage of 0.7 V?

@YewTide604 5 жыл бұрын

If you are still wondering a year later, that is correct lol

@prasadchabbi6065 Жыл бұрын

Hi, Please take 0.7 V into consideration to turn on the Diode.

@ElectrcRadiation Жыл бұрын

He's talking about ideal diodes, so 0V drop. The standard 0.7V comes from an assumption of non ideal diodes

@WINCHOism 4 жыл бұрын

toledo me va a clavar

@uzairwarraich8961 8 жыл бұрын

part c should be positive 5 volts

@bonfire62 8 жыл бұрын

+Uzair Warraich incorrect, there is no way it can be +5 volts because the source is going from -5 V to ground.

@bonfire62 8 жыл бұрын

+wjs no, because there is not voltage drop across the resistor, so it is pulled to 5 volts

@desentilabeqja7969 6 жыл бұрын

The anode is at -5V and cathode at 0V. V is the cathode to anode voltage = 0-(-5V) = 5V!!!!

@satanicmonkey666 5 жыл бұрын

You are right, the way it is drawn is 5 volts. However, if we accept that the anode terminal has a -5 voltage applied to it, the diode is then operating in reverse bias, or operated in the reverse direction. This occurs when you apply a negative voltage to the anode(+) of the diode. He should re-draw the diode to be in the reverse bias orientation since a negative voltage is being applied to the anode, that is flip the diode 180 degrees. This would then agree with the instructors answer choice. Microelectronic circuits, Sedra Smith, 6th edition, P 166 section 4.1.1 .

@davidpower2054 8 жыл бұрын

furthermore, they cannot be different voltages in parallel it is a violation of kirchhoff laws, how did you dare make examples with different voltages

@bachnhan08 7 жыл бұрын

what wrong with it? we did a lab with the same circuit, where there are different voltages in parallel.

@brinton417 7 жыл бұрын

I assume you are referring to the circuits "e" and "f" examples. They aren't connected in parallel electrically. Parallel means they have the same voltage across them. These don't. Each diode is connected to a different voltage. Only one of the diodes will conduct. The other diodes will have a different reverse biased voltage that does satisfy Kirchoff's Voltage Law. In example "e", only the diode connected on the left to 3 V will conduct. This makes the output voltage also 3 Volts (assuming ideal diode model). This voltage keeps the other two diodes reverse biased and "off". The diode connected to 2 Volts will have a 1 Volt reverse bias. The diode connected to 1 Volt will have a 2 Volt reverse bias.