complex analysis Taylor's and Laurent's series for function f(z) =1/(1+z^2)(z+2) || complex integral
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@indrakumar8414 5 ай бұрын
Thankyou ma'am very well explained.
@SwatiThengMathematics 5 ай бұрын
Thank you 😊
@invisibledreams2004 8 ай бұрын
A big thanks to you ma'am ❤
@SwatiThengMathematics 8 ай бұрын
Thank you! Please share with others.
@Deepjyoti71 6 ай бұрын
Why we take common z^2 in first and 2 in second ?? please reply anyone know that 8:27
@SwatiThengMathematics 6 ай бұрын
To find the series, we utilize the formula (1+a)^-1 = 1 + a + a^2... with the condition |a| < 1. Applying this to the given equations |1/z| < 1 and |z/2| < 1, we simplify the expressions. In the first bracket, taking z^2 as common, we get a = 1/z^2 < 1. For the second bracket, taking 2 as common, we get a = z/2 < 1. This allows us to apply the formula. Otherwise, it won't be applicable. Refer to the explanation at 07:14 for further clarity
@Deepjyoti71 6 ай бұрын
thank you so much❤
@ShriyanshKanojiya-oj3he Жыл бұрын
Hello mam I am your school student of class 9th 1:31
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