Mathematically the answer is 4! x 12 keys (ignoring the double naming of some keys) = 288. However, as with triads, standard music theory only recognises the Root inversion (e.g. Cmaj7/C - root note in bass); 1st inversion (e.g. Cmaj7/E - major 3rd in bass); 2nd inversion (e.g. Cmaj7/G - perfect 5th in bass); 3rd inversion (e.g. Cmaj7/B - major 7th in bass) the order of the notes stacked above the bass note is ignored. So "standard" chord theory only give 4 inversions of a major 7th chord in 12 keys, so 48 in total. In other words there are two answers, either 288 (maths based answer) or 48 (standard chord construction theory answer).

Hi Scott!! Your lessons have really changed my bass playing. Thank you for sharing all this top level stuff for free here on KZfaq. As soon as I start working I hope to join the academy because it really is incredible. I just wanted to throw this idea out there because I noticed you have a lot of subscribers but I think that there is not enough for how good your stuff actually is and that may be due to a language barrier. For example: I'm originally from Brazil, so I only started watching your videos after I moved to America and learned English. I just think what you are doing is so good that you should have millions of subscribers. Maybe (but I am not sure about this) having translations on a couple of main languages could double if not triple the number of subscriptions! God bless, man!!

I learnt loads from Phil Mann at SBL. My favourite teacher there!

4* 3 *2 * 1 = 24 for permutations in a key x 12 keys = 288

6 permutations per inversion. 4 inversions per 7th chord. 12 keys That's (6×4)×12=X 24×12=288

Thanks Scott & Phil !! Great video ... very informative.

using the four notes in any order, there are 288 combinations possible. Using the standard inversions, the number of permutations in all 12 keys is 48.

Exactly what I need to know more about, taking it to the next level. By the way, that bass....sweeeet!

Years later this is so interesting still

There are six permutations for the arpeggio without inversiones (1357, 1375, 1537, 1573, 1735, 1753), then 3 inversions, so 6+6+6+6=24 permutations in just one key. For 12 keys, 12 times 24 equals 288.

4 x 3 x 2 x 1 (number of ways to order notes) x 12 (number of keys) = 288 permutations

well, if we don't count the root in an octave higher and stay within one octave then my answer is 288 possibilities. 6 permutations per inversion and no permutation is repeated. if we should use elements in octave positions the numbers multiply exponentially depending on how many elements we use within the range of multiple octaves.

(4 notes x 3 permutations x 2 inversions) x 12 keys = 288 :)

Great video guys! Really enjoyed it! The answer is 288!

There are 1152 permutations. I thought it was 288, but that's always playing the lowest note first. Taking root position as an example, we can play any of the four notes first. So it becomes 4x3x2x1=24. 24 permutations per position, 96 per tone and 1152 total.

4x3 x2 x1 = 24 for permutations in a key x 12 keys = 288

Loved it! And the answer, as everyone else said, 288,

you can do 48 different permutations in all 12 keys if you don't allow repetition of the permutations during the inversions

It's a shame that two different names are given for what the subject is here, namely 'chord tones' and 'arpeggios'. Beginners are likely to take some time to realise that they are one and the same thing.

Any chance we can have Phil give us a lesson in resolutions?

288 in Spain!

permutations of a 7th chord in a single position, 4 notes available, is 4 * 3 * 2 * 1 (aka 4!) is 24, there are actually 15 -written- major keys, you mention 12 actual major keys. so, it's 12 * 24, and the way I can keep it in my head, is if I turn it into 12 * 2 * 12, and I know 12 * 12 is 144, times 2 is 288

Great stuff!

There are 6 possible permutations, and 4 possible inversions. Times these two together = 24 (and that's just one chord!) Translate this to all 12 keys and you have 288. Wow, time to get in the shed! ;)

288! a year of hard work for sure!

1152 ( 4 notes have 24 possible orders, for 4 inversions for 12 keys )

I can't come up with any. Perhaps this book would help me? ;)

I'm going to take a chance with 288. Cheers!

288, and now the trick is to practice them all in one day!!

Isn't it 4x3x2x1 for permutations of one position of a maj7, multiplied by 4 for all the inversions, multiplied by 12 for all the keys. So, 1152?

(4x3x2x1) x 12 = 288 ouch!

there are actually 30 keys, major minor and sharps and flats.....Anthony Jackson teaches this...

I can't find this book anywhere

great video mate and now to the main thing I've calculated all the possibility of all maj7 in a single key which is 12 and multiplied it by 12(total no. of keys) which gives us a total of 144.

288 of course

I would say 1152

nice bass! what type of fender is it?

288 (4 factorial = 28 X 12 = 288)

288! Love the videos Scott, Im 18 and at uni doing music Production, but getting madly into Bass, and want to become the best :)

My face is melted but I'm gunna say 288

3072. Great chat with 2 great players. Nice bass BTW.

288, so many to learn

1152 or 288

288! And yes I used my calculator haha

I thought there were 15 major keys, C, 7 sharp, 7 flat.

288 !!! Hope I'll win

Personally... 1 😂 I think I need this book

288 is my answer

I'm gonna go all out and scream 288.

Hey Scott, you will get 288 Permutations!

1152 right?

144 x 2 with inversion 288

2500+ permutations

Man I'm 3 years late to the 🥳. Oh well 288!

1152

1x2x3x4 = 24 24x12 keys = 288

Yes, it's 288.

24

= 288 Btw you forgot to Add Phil's Link 🔗

Look at all of us breaking the 'Bass players are stupid' stereotype. 😀 Anyway, 4x3x2x1=24 and 12 keys, so 288. Cheers!

3072 daaaaamn

12 key is 288

the anwser is 288

That'll be... 4!*12=288 wow

288

My music teacher asked us this last semester 288

288!!!

288?

144

288. Is the answer....

Dammit, I never thought of checking other peoples' answers. I'm a dumbass. ;) Anyway my personal HAL-9000 says 288.

288 ... I think. unless it's a trick!

288.

No idea

I'm gonna say the answer is 288

288 boom

4! x 12 = 288

dude, 3, 3 permutations. so easy.

Too many for my slow brain to remember! lol (naw, I think its 1152)

The Answer to The question Is 288. See you scott. peace.

288 :)

288 Greetings !

1440 because there are technically 15 keys.

288 to easy fam

Yeah, but... jazz...

I find it really hard to listen to Phil, this distracts from the potential great info he has to share.

1152

288?

144

288

288 :)

1152

288?

144

144

144

144

144

288

288