A) Drop Ball = 3:56 B) Throw Ball Up = 10:04 C) Throw Ball Down = 20:11

Thanks Ben Affleck. Highly appreciate it!

Incredible! Thank you so much for emphasising on the sign convention.

I wish I can give u a hug irl. These videos are SOOO HELPFUL. STEP BY STEP. YOU didn't skip a single step, matter of fact you showed us multiple ways to do it with diff formulas. You're an absolute GOAT. Thank you! truly an inspiration

I really took the advantage of your lecture. I studied kinematic in 1995. But your lecture retained them quickly to my memory.

On FREE FALL This is the best video ever which I didn't found anywhere on whole YT ...I am so glad I found it and now my free fall concept is crystal clear.......Thank you so much sir !!

Well explained, brief and clear.

You explain the concept clearly and beautifully! I subscribed to your channel!

Thank you so much. The explanation is amazing!

Thank you so much for this.

Not only did you explain the thing I was stuck on for ages but your teaching style is AWESOME. I wish I had a teacher like you!!!!!!!!! Yeeeeeehaaaaaaaaaa3wwwwwwwwwwwww

thank you very much sir,you made me understand free fall, keep it up and may God bless you

Dude, you just saved my freaking life 🎉🎉 keep going

Thank you so much!

Absolutely! My kids are studying online and this video presents the concept in the clearest way. Thank you. Subscribed

Thank you for this good explanation you explained it even better than my teacher! *tips hat*

This video helps me a lot. Thanks bro

Question, how did you get the 2×7 in the first problem I mean I get where you got the 7 from but not the 2.

THAAANKKK YOUUUU AHHH😭😭😭💗💗💗💗

in part 20:06 why did you not add the time to get up to the max height as well ? How does using 7 meters in the equation give you the total flight time ?

Very clear and easy to understand thank you very much sir

Clearly explained thanks

On the second question when finding the total time of the flight why are we using negative 7 instead of the 13. Which we found as the total displacement

When you are trying to find the max speed before hitting the ground you can also you 0 as your initial velocity and 8.84 as your total displacement to get the same answer

How do you find the range for part B. Throwing ball up?

A). A stone is thrown straight with a speed of 24m/s. It is caught on its way down at a point 7.2m above the position it was thrown. How fast was it going when it was caught?

Thank you so much

On the last question why did you use -8 velocity for the first equation then +8 for the other equation

Thank you so muchhhh!!!

So if the initial velocity is not given when u are throwing the ball down, would u solve like u are dropping the ball down and then add the 1/2(a)(t^2)?

Thank you so much :)

If you know the initial velocity is 15m/s and the height is 21m and the angle is 40 degrees is there anyway to solve it without using the quadratic equation.

Never have I ever seen such an ad infested video

Can you do that examples to me please... Q1.A ball is thrown upwards with an initial speed of 20 ms-1. a) how far does the ball rise in 1s? b)how long does it take to reach the highest point of its motion? c)what is the maximum height reached by the ball? Q2.An object falls vertically from the edge of a building and strikes the ground 40 m below. a)calculate the velocity of the object as it strikes the ground. b)how long did it take the object to fall 40 m? c)what is the velocity of the object half way down? Q3.A golf ball is thrown vertically upwards with initial velocity of 25 m/s and returns to the thrower in 5 s. a)what is the velocity of the ball at the highest point? b)how long did it take to reach the highest point? c)what is the highest point reached by the by? d)calculate the total distance traveled by the ball. e)what is the total displacement of the ball? f)draw a velocity - time graph representing the motion of the ball over the 5 s, showing the following: 1.initial velocity 2.final velocity 3.time to reach the top 4.section representing upwards motion 5.section representing downward motion... please !!!

Please use this example While sitting on a tree branch 10.0m above the ground you drop a ball. When the ball has fallen 2.5m, you throw a second ball straight down. What initial speed must give the second ball if they are botb to reach the ground at the same time?

THANK YOU

first time watching and its like zachary levi is explaining physics pretty cool

What if, say, a ball is thrown vertically up, reaches its peak, then falls back down to 20m above its original position? How should I approach this problem? Should I divide the problem in two? Or is there a one equation solution?

Thanks!, Hope your successful

For the first one your answer is right but working is very in accurate,you teach like a math teacher than a actual physics teacher

i have a question, for the first number, where did you get 2.7?

For the total flight time, couldn't you have just added added the time for the throw, calculated the time of the fall, and added those together?

where do u get 2 times 7 over 9.8 on the first one

if someone dropped an object off a cliff how far would it travel in 8 seconds and how fast would it be traveling at the point of impact. I really would like to know. Thank you. : - )

Thanks for the great explanation, my only question isn't Vf for the last problem suppose to be negative because it is going downward?

Why when u calculate total flight time not using the time u found in a highest point/the time the ball was first thrown down

I have a question, my teacher told me that in his case, when the object drops down it's a positive value but when it goes up it's a negative value, so does acceleration due to gravity depend on the sign convention we wish to follow?

Is the object still in free fall when it is thrown down?

Great explanation, definitely subscribing

at 11:42 why you didnt use initial velocity on the Y direction Vsinx ? you used the Vinitial 6

why is the acceleration vector pointing down(ie negative) when the ball is thrown up ?

Use the formula a = Δ Q. When the ice block was at point Y, the rope slipped through the caterer’s hands, and the block fell. The acceleration of the block toward the ground was 9.8 m/s2. What was the velocity of the block after 0.2 seconds? _______ m/s

Great Video clear. Thank you very much. I got this question, kindly help me. A ball is dropped from rest a height h above the ground at the instant the first ball is released. Determine the velocity of the second ball, if the two meet at h/2 above the ground.

This video helped a lot but I do not get the 'negative-Down and positive-Up' stuff.

Hello! I have a tiny doubt. At 15:47, you mentioned that the change in displacement for y would be -7. Why shouldn't it be 8.84; i.e the calculated height? Because the ball is dropping from that maximum height - or would that be considered the distance rather than the displacement? Thanks!

how do i identify if its velocity, velocity initial, speed, displacement and all the other ways to classify them?

For question B, why don't we use the max height of the ball? I calculated the velocity that way and also got -13.6. Is it just a coincidence or is there only one height we should be using.

on the second problem when you are finding the speed before hitting the ground should the intial velocity not be 0m/s and the height be 8.84 meters. As the ball would speed up a lot more from a height of 8.84 meters rather than 7 meters.

alright bro youre the goat

why did you use 7m instead of 8.84?

I hope you can answer in time but why in B) around 15:14, wouldn’t initial velocity be 0 as we’re finding the speed before it hits ground? Knowing that as it falls the velocity should be 0 as it de-accelerates

So, for the final answer, since upwards is positive, it's either 14.2 down or -14.2 right? I'm a bit confused because you canceled out the positive value but still took the positive value. Otherwise, great video though. Thanks for the help! Edit: Also in B3 shouldn't it just be the magnitude since it's asking for the speed?

ur the best physics teacher in youtube.your video helped me a lot

Wow men I totally understand the use example in this explanation! You nailed it men thanks! have a great day

Thank you so much holy shizz

Super cool presentation and so helpful keep it up well done.

7:28 What do you mean by "two at the top?"

alot of free fall questions ask for the velocity of an object WHEN it hits the ground, which is different from just BEFORE hitting the ground. Im just confused on weather those are interchangable or not. does the velocity when the ball hits the ground equal 0? Also alot of free fall problems ask for the velocity when a person CATCHES the ball. Does that also mean the velocity is equal to 0? Thank you for such a helpful video by the way! :)

in your formula you derived has a negative g because you said that objects in free fall goes to the negative y-axis, but why did you use that formula in getting the displacement of the ball thrown upward to the positive y-axis, i think the answer should be d=5.48m not 1.83m

Respectful sir thankyou for this video ..... I was struggling in this cocept for my neet 2024 . Now I've got a real good clarity ❤

Thanks alots sir for your neat presentation,, however i have got doubt why did you initially consider "g"= -g? May you explain for me

I have a question how did you get 2 times 7 or 2•7 in problem A?

Should g be positive wen ball is dropping because it's gravity and be negative wen the ball is thrown or Is rising because it's going against gravity

May I ask, how did you get that square root of 2.7. I'm hoping for your response because I am confused. Thank you.

Top notch

Shouldn't the vf in the 3rd example be -14.2m/s since it's going down?

1) In the second task (can we find the displacement of the ball in the air of the y axis - trajectory of the ball in the whole movement?) 2) Also can we find the displacement of the x axis (how far the ball landed from the starting position?); 3) Can we separate the different segments deltaYAB and deltaYBC and calculate the paths, which the ball spent in the air? I hope you can give me a hint.

Total flight time should be the time you throw the ball up plus the time it lands on the ground right?

Plz apploded full kinematics concept

Total flight time includes it being thrown up and then going down, why didn't you use 8.84m for delta y. Why only 7, do you forget the time it took to reach the top and then fall??? Flight time is how long was it in the air, it being thrown up should still be included in flight time... Makes no sense

When an object is dropped from above gravity is positive...Why you using negative g?

I have question sir how did you get 7

At drop ball first problem while solving by yourself, Please take note It is not 0.7 but 0-7 therefore after solving 14 will come not 2.7. at 7:32

Let’s say you only have the seconds it takes for the object to fall to the ground from a cliff. Let’s say a stone takes 12 seconds to fall from the top of a cliff, what’s the height of the cliff?

But why is time negative? Isn't it positive?

Speed before hitting group is just 11.719 m/s

what do you use to find 13.16 m/s number 2 situation.

How you get 1.2 seconds?

Is throwing a free fall?

Good day sir! I have a question, how did you get the 2.7 in the problem A?

I guess dropping an object from a hot air balloon wouldn't have a initial velocity as zero right? Dropping from a stationary object, initial velocity will be zero

From the roof of a building of 30m height, a stone is vertically thrown upward with an initial speed of (10m/s), in the vertical frame OZ downward oriented. Determine : 1 The speed v of the stone when it reaches the ground 2 The total duration t of the freely falling motion.

4:55 why is t=1.96 secs??

For (A), I realized that if a 80kg drunk dude walked off a 7m ledge, he will still take 1.2s to hit the ground at 11.7m/s(43km/hr or 26.7mph), even though his weight(or should i say mass) is many times heavier than the ball. From the equation, the mass of the object is irrelevant. Then I imagine the same drunk dude walking off the top of Empire State Building at 381m to his death. He will take 8.8s to hit the ground at 86.4m/s(311km/hr or 193.3mph). I want to know the force just before impact so I tried to apply F=ma= 80(9.8)=784N but the value seems to be too small for a falling human being becoming pizza on the ground. In fact 784N seems to be just the weight of the dude standing on the ground due to Earth's gravity. Where did I calculate wrongly?

@9:22 balls dropping lmao

Have you ever heard g=-9.81 instead of a=-g? this happen in now malaysia spm physics, and the teachers are still think it is right

I hope I get an answer real quick 🙏 I really need this.. On 12:11 why does the 9.8 became a denominator? I really didn't understood how the 0=6-9.8t became t=6/9.8. How did it happen?? In my understanding, to isolate t, it should be -6+9.8=t. But it became 6/9.8 here. Please somebody explain🥺

Hey you didn't take air resistance into account..

I am so confuse for the sign of g ,😢 is that if the ball is throw going down ,so the g is negative?and if the ball is going up ,so the g is positive?,can someone explain it to me ,thank you

Problem 2