Error Detection in just 5 mins . Dude u saved my exams . Thanks

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Neso Academy will be at heights one day, I am really wondering that why I am giving money to my college, if they are just explaining orally without even pointing out. Once again thankyou so much Neso Academy.

very helpful. . .your 5 minutes lecture is much better than our professor 5 hour's lecture. thank you neso

Congratulations! I am trying to figure this out for a week from the books of Hellenic open university. I was starting to think that I was dumb. Thank you very much!!!

I just watched your Hamming Code Error Detection and now your Error Correct -- Your teaching was so very clear!!!! Thank you, Thank you, Thank you!!!!! I learned from you what I could learn from my professor, the textbook and several hours of online research!!!! You are the best!!!!

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Wow! Nice and clear. A very good explanation keep making a difference in students life with your lessons. :)

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Thank you so much nice explanation. Moreover, for finding the value of p1, p2, p4, ...pn, we can also use this method; how it works? It depends upon how many parity bits we have. For example here we have three parity bits p1, p2, p4, if we write them as three binary bit notion since they are three parity bits, we get the below table. For each parity bit we only note down the bit which is 1 vertically and we get the specific value for each parity bit. p4 p2 p1 0 0 0 =0 p1 = (1, 3, 5, 7) or (p1, d3, d5, d7) 0 0 1 =1 p2 = (2, 3, 6, 7) or (p2, d3, d6, d7) 0 1 0 =2 p4 = (4, 5, 6, 7) or (p4, d5, d6, d7) 0 1 1 =3 1 0 0 =4 1 0 1 =5 1 1 0 =6 1 1 1 =7

Thank you Neso Academy for the quality and useful info.

Thank you for giving a good presentation on hamming code. Very useful.

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HATS OFF "NESO ACADEMY".IT HELPED ME A LOT.(STUDENT FROM NIT ALLAHABAD)

Thank you for help me, I was freaking out with that 😄

Your method of explaining is explicit. Thanks so much you just saved my exams

Thankyou So much! Your videos are of great help!

The explanation was imazing thank you :)

Dude you r a time saver as a whole.

This was an amazing explanation. Thanks for the video. But the question I saw didn't mention if they're assuming the parity to be even or odd

Great way to communicate concepts Thank you

I appreciate so much for making me understand Hamming code.

it is just awesome sir...amazing....hats off to u...

sir...... i got it my confusion from 1st video....thank you so much. its very simple explained.

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Great explanation. Thank You!

best explanation, thankyou neso acedmy.

THANK YOU!! Very useful for upcoming exam.

awesomely described.thank you

A really beautiful explanation Thank you for this video

very well explained ! thanks a lot

very well explained..but a query what if the parity bit itself is affected by channel noise and is affected? how will I know the error then??

Nice, this video and the previous one are gold, so simple and to the point, thank you so much!

best teaching channel i ever seen in youtube . i hope you should have 10 million subscribes soon. i learn 7 bit hamming code in 5 mninutes. you are the main reason to qualify in my semester exams thank you neso academy love you so much.

Thank you! Very well explained!

Your videos are helpful :)

i found this video very helpfull for my last preparation of my exam. thanks alot🤠

Your explanation way is fabulous. One day your channel will be as famous as today's khan sir channel. Keep it up ❤️

As usual ...best explaination

thanks a million simple and straight forward

Just awesome sir .......... Helped me a lot ...... Tqqqqqqqqqq

Thank you. It's so helpful.

Very helpful video sir, Thank you ❤

Thank you neso ❤

I was having so much trouble trying to understand the text book but your video helped immensely, the Indian guy meme in the CS community was not wrong afterall

So nicely explained!!

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Clear explanation. Thank u

Veey helpful sir...thanks a lot

awesome. cleared each and every doubt

12 hours to my digital exam and this comes to help

Thank you so much!!

dhoom Dham full too best ...very well explained. ...

good presentation!

thank you very much you saved my exams

This video is great and trully exlpains the algorith of correcting the single bit error in a hamming code. But i want to mention that by just learning to execute the correction hamming algorith you dont realize at all the essense of the hamming code or the basic theory behides codes, valid codewords, distance and so on

In my book Digital electronics by Anand Kumar P1 P2 D3 P4 D5 D6 D7 These are written in this ⬆️ order But in sir's explanation it is opposite in order. Which one to follow, both are giving different answer for same question.😐

Very explained sir... thanq..

I had gone through a digital electronics book, there I found that the arrangement of hamming codes are in reverse order like P1 P2 D3 P4 D5 D6 D7 & the bits were arranged as per this order only not as you have said. I also verified with this pattern for above explained example but I found a different in error place as 7 instead of 5.can you please tell me that which order I have to prefer?

thanks for the presentation...

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amazing. Thank you.

Thank u very much. U are very helpful.

Beautifully explained

Helpful video..Keep it up!

thank you sooooo much clear and clean

Nice. Didn't learn this at uni

Beautifully done (y)

Very nice presentation.... I give 5 stars for this. A very very thanks for this creation.

Great Video!!!

Very helpful . thank u

Any suggestions on how to implement this system using logic gates? That will be amazing!

Thank You sir!

Thanks sir nicely explained

thank you u saved my life

Very good explanation

Very well explained❤

thank u sir.. very helpful

Very well explained...

Actually, I think we can do this error correction by logic. D3 D5 D7 P1= 1 0 1 1. There is an error here. So either D3 or D5 or D7 must have an error. D3 D6 D7 P2= 1 0 0 1. Here there isn't an error. So the data bits D3, D6, and D7 are errorless. So in P1, the error must be in D5 coz from the above we can see that D6 and D7 are errorless. We can also calculate the error in the data bit by using P4 as follows: D5 D6 D7 P1= 1 1 0 1. There is an error here. So either D5 or D6 or D7 must have an error. From P2 we know that there isn't any error in D6 or D7 so the error bit must be D5.

thanks for very well explain

thank you so much

nice video.it really helped me Nd great presentation

Thank you 🤗

thnx sir...very good presentation

Thank you sir for teaching us...our exam is in half an hour

You've showed how to follow the procedure of correcting the error, and thanks for that. It would be beneficial also to explain why does it actually work (which in my opinion is more important than only knowing how).

thanks sir. excellent video

excellent explanation sir

Nicely simplified .

Thank you so muchhhh!

Thank You

Thanks!

Thank you prof, the problem I have is that what if the mistake is in the parity bit?

Thank u so much

Sir, Uploading videos are so helpfull .plz upload 2out of 5 code,63210 code,Biquinary code ,ring counter code

Thank you sir