he is right,always use the worse case or scenario.thanks. I stand to be corrected.

Thanks for the sub and your comment Luke. Welcome aboard!

You cannot wire two batteries in series parallel. It's either series or parallel. Since you have a 12V inverter, you will have 12V 200Ah.

It is sunhours. 1kw/M2 = 1 sunhour. Don't confuse with hours of sunshine. 1 hour of sunshine can be 500w/m2

It's not oversizing if you calculate 3 days of autonomy. Check out my video sizing off grid solar system.

Most 48V batteries cannot do this because the BMS is limited to 48V. Check your manual of the battery.

It depends on the max input voltage calculation. If you are grid tied then it's probably not worth it. This is for off-grid.

@@cleversolarpower sorry - found an important typo in the question. Have edited it… can I get you to re-read ?

PV1 has 1265W and 150.6V PV2 has 1765W and 155.5V Inverter is LuxPowerTek SNA5000WPV. Need more PV capacity but concerned about MPPT voltage limits on Inverter. Please advise

​@@hamiltonkpasipamire7454to keep voltage down, put panels in parallel

​@@hamiltonkpasipamire7454 if the inverter can handle it, parallel the panels. BUT the inverter has to be able to handel the SCC short circuit of all panels. if a panel has 33Voc 30V mpp and 22A Scc 20A mpp (600W) and the inverter can handle 150V 25A you could put them all in series. because 4 times 33V open circuit is 132V => plus 10% safety magin => 145,2V open circuit is below 150V inverter capabilitiy. for the current nothing changes because in a serial string the amps keep the same like the individual panel. thats 22A short circuit. 10% safety margin => 24,2A is below 25A inverter capability. if the inverter can handle 80V but 50A you could put 2 panels as series strings and then parallel them with another series twin of panels. so you had 66V open circuit including 10% safety => 72,6V => below 80V. and the two paralleled twin strings would double the amps to 44A short circuit => below 50A inverter capability. still you need to take into consideration the battery voltage level. like 12V, 24V or 48V. you can all-parallel the panels, if 1.: the inverter is capable ( 22+22+22+22 = 88A short circuit) AND the battery voltage level is about +/- 33% BELOW the mpp maximum power point voltage of the panel. that would be about 18V for a typical 12V system. so panels rangeing from 17 to 21V mpp would fit well for a 12V with all paralleled panels. on a higher voltage stage like 24V you could never get a single watthour in your battery. so putting two in series for a string of 36V is the minimum. you can stack as many 36V strings in paralel as the inverter can handle. but you could also put 4 panels into a single string of 72V mpp. but always look for the open circuit voltage and take that into account with you calculations. a single 18V mpp panel might produce 21V open circuit. also never chose an inverter below the short circuit rating. it might fry.

Amp-hours is not really a measure of energy storage. Its amp-hours x volts. Presuming LiFePO4 batteries, you don't buy 12V batteries for this. You buy 48V (which is actually 51.2V nominal for LiFePO4, 16s) batteries. 5kWh of storage winds up being ONE 100Ah 48V LiFePO4 battery. That would be ONE EG4 LL or EG4 LifePower4 rack-mount battery. Around 100lbs. I'll reinterpret your other question as "How much solar to produce 5kWh/day". The answer is roughly 1.5kWp worth of solar panels in summer, and roughly 2.5kWp in winter. kWp = nameplate installed solar panels. Of course it depends on many factors, in particular where you live in the world, but those are rough numbers that work almost anywhere. Generally you just multiply the nameplate by 2 to 3 for winter and by 4 to 5 for summer to get the energy/day. 1 kW solar panel = 2 kWh to 3 kWh/day in winter and 4 kWh to 5 kWh/day in summer. Roughly. Something like that. Depends on where you live. So choose which setup you want. 1.5kWp worth of solar with 300W panels is roughly 5 panels. 2.5kWp worth of solar with 300W panels is roughly 8 or 9 300W panels. The 1.5kWp setup will be able to produce 5kWh/day of energy for roughly 240 days out of the 365-day year. A 2.5kWp setup will be able to produce 5kWh/day of energy for roughly 300 days out of the 365-day year. And less for the remaining days (winter storms, excess cloudiness, etc). -Matt

@@junkerzn7312 awesome explanation. I really appreciate your thorough explanation. Much love from Nigeria

The battery has 3 days of autonomy. That means on day 1 you will use 5kwh, day 2 5kwh, and day 3 5kwh. Then the battery will get recharged from 0 to 100%. This is the worst case scenario for off-grid purposes.

Obviously it would not be that neat more likely you will have random days of full and partial recharge. But the spare power would just sit in the battery bank (just like cash savings in a money bank) waiting for the rainy days.

@@cleversolarpower but you don't answer my question what happens to the % you don't use.

@@grahamjohnson4702 It gets thrown away. The charge controllers will curtail the solar, reducing the power output from the panels to exactly match your real-time loads once the battery is full. Excess power that the panels COULD have been producing is thrown away. So it will be able to keep the battery full until sun-down, but it can't use the extra power unless there is a load there to soak it up. This is how renewable energy works. You either have more than you need, or less than you need, but never exactly what you need. Always better to have more than you need. Instead of throwing it away, some people are able to leverage the extra energy by adding extra real-time loads to the system to soak up the extra energy. For example, a little crypto-currency farm (Mining monero, for example... but to be honest nobody ever makes enough money that way for it to be worth doing). If you have access to the grid you just push the excess to the grid. If you don't you can use the excess energy to heat water in your water heater, or heat a sand-battery for overnight home heating purposes, and so on and so forth. At least up to a point. So there are plenty of use cases for the extra energy instead of throwing it away, but those uses have to be constructed. Most people don't bother beyond heating up a tank of water or a sand-battery to help with overnight home heating needs. Theoretically... well, actually in practice, some greenhouses generate extra heat and inject it into the ground during summer and the heat then reduces winter operating costs. It can actually radiate back into the greenhouse over the entirety of winter. -Matt

​@@grahamjohnson4702nothing. It just stays there until it's needed.

Yes, a 48V system should be used. If you have a 12V system, you need 350A worth of charge controllers. If you use 48V, it's reduced to 90A.

Not if you are off grid 😉

But, it's Fun! 😊

Yes that is correct, but what size battery bank would be needed?

@@geoffreykaila depends, now if average sunshine hours in a day is 4 and the maximum PV wattage that can be connected to the inverter is 5000 watts, so that means your solar panels will generate 5000 watts * 4 hours (average sunshine) = 20,000 Watt-hours , Now since the inverter has a battery voltage input of 48 Volts and if we take 4 batteries each having voltage of 12V and 200Ah we connect 4 of them in series the total voltage will add up to 48 Volts , 200Ah, here the total energy of the battery will be 48V * 200Ah = 9,600 Watt-hours. So the total energy generated from our panels is 20,000 Watt-hours as compared to the total Energy of the battery which is only 9,600 Watt-hours which is clearly sufficient to charge the battery bank. 20,000 Watt-hours (Generation from Solar ) > 9,600 Watt-hours ( Total Energy of the Battery Bank). Hope this helps!! Cheers!

I design from the battery backwards and but as many batteries as I can. Then the inverter charger and then as many panels as I can fit. I didn't calculate anything. Just go as big as possible.. my inverter charger has AC in for charging even the sun doesn't shine