Iteration method | fixed point iteration method

Рет қаралды 103,973

4 жыл бұрын

This video contains a numerical and an extra example at the end.My purpose of doing so was to make clear about why do we need arrange the given equation in all the possible forms of x=fie(x).
Bisection method:
• Bisection method | Bis...
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ForGauss Elimination Method by Partial Pivoting check out the following link:
• Gauss elimination meth...
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For Newton's forward interpolation method check out the link
• Newton forward interpo...
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Пікірлер: 35

@vinodjones5452 4 жыл бұрын

Nice explanation brother Tq♥️

@aishwaryahunnur83 3 жыл бұрын

Well Explained Sir, Keep on doing more vedios

@muwongeevanspaul9166 2 жыл бұрын

Very good explanation esp at the end

@sulekhasreenivas3279 3 жыл бұрын

Very helpful

@flooglewarp1567 2 жыл бұрын

13:11 should the 2nd equation be x = (-x+1)^1/3 with negative x in argument as oppose to positive x? or am i wrong?

@swapnab8221 2 жыл бұрын

@Ciaran K Campbell I think you are right...

@Rajukgeorge 3 ай бұрын

In this case |g'(x)| is not less than one on [0,1]@@swapnab8221

@mthokozisindlovu873 2 жыл бұрын

you the best😉

@pallapothubhanuganeshkumar3247 3 жыл бұрын

Super excellent

@sharonkendi4426 3 жыл бұрын

Nice one

@user-rm8yz2hw9i 6 ай бұрын

🎉 good job

@emmanuelenobong5549 Жыл бұрын

Is fixed point iteration still the same as method of successive approximation

@reethiyasree2116 3 жыл бұрын

Nice explanation bro Tq

@Civillearningonline 3 жыл бұрын

Welcome

@pronk4321 Жыл бұрын

Thank you 😭

@chathuranadun8264 Жыл бұрын

Thankss broo

@bandaruravanamma738 2 жыл бұрын

How to take xnot value

@yusuffabdulmusawwir6807 Жыл бұрын

Why is the second form for the second example not valid?? Since the root lie between 0 and 1 and once we plug it to to the derivative we get less than 1 for both, why is it not still valid?

@jerrychiwato6303 9 ай бұрын

You're right have seen this as well

@komalavanis6235 3 жыл бұрын

Why we take x0=4 ? If we take x0=5 means

@Civillearningonline 3 жыл бұрын

Hello dear, Here is your answer. We take x0 =4, not x0=5 because we have got the -ve and and + ve value between 4 and 5 which mean our root will lie between 4 and 5. And its up to us either we proceed by taking x0=4 or x0=5. There is no any hard and fast rule for this. So go for it it's totally your choice and i am sorry that i am replying you late. Have a nice day.

@abhijiththankachan167 3 жыл бұрын

❤️

@holyshit922 5 ай бұрын

Transform equation to the form x = f(x) and there we have two options Solve x = f(x) or solve x = f^{-1}(x) How to choose correct one ? In this example f(x) = 100/x^2 - 1 If we try to solve x=f(x) we will get divergent sequence but if we solve x = f^{-1}(x) sequence will converge

@jesisahana2307 2 жыл бұрын

Thanks 🙏🙏🙏🙏

@Spirit0026 4 жыл бұрын

sir can we put f(0) and f(1) in the beginning equation itself means in the question

@Civillearningonline 4 жыл бұрын

Hello dear, Thanks for your comment. The thing is you cannot apply f(0) and f(1) in the beginning because in iteration method one must satisfy what the theorem says i.e. modules of fi(x) must be less than one. You can apply f(0) and f (1) if the theorem has satisfied. In to this video i have added an extra Example at the end to enhance your understanding so do watch the video till end. And i am sure that you arr going to find it very helpful. Thank you. Have a nice day

@Civillearningonline 3 жыл бұрын

Galerkin method. Hope you like it. kzfaq.info/get/bejne/mqificiqytmYiYU.html