Limiting Reagents and Percent Yield

Рет қаралды 491,886

Күн бұрын

Chemistry doesn't always work perfectly, silly. Molecules are left over when one thing runs out! Also we never get all of the products that we thought we might by doing the math. You gotta know about the limiting reagents and the percent yield! Don't worry, it's as easy as bologna sandwiches.
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Пікірлер: 221

@AAG414 3 жыл бұрын

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Well,he kind of looks like Jesus😂

@-_-ZENN-_- Ай бұрын

@@denicagovender5029that was the point of the joke 🤦‍♂️

@katiecheng6551 5 жыл бұрын

professor dave whippin out the bologna sandwich analogy makes him my favorite person ever

@user-pp1bv7yr2n 4 жыл бұрын

@arjungupta3095 2 жыл бұрын

He’s a living legend.

@ivoryas1696 2 жыл бұрын

Katie Cheng It's so intuitive yet effective Some sandwiches are just Bologna(O) and bread(H), others are double or triple decker and have a different medium like... peanut butter (Ammonia), or have different things that act as bologna but aren't or dishes that don't need it (a turkey sandwich or literally just table salt). It's brilliant!

@tontonanharian6840 Жыл бұрын

The best teacher i never tell my friends to be the excell in class. I already speedrun math to linear algebra with professor dave videos and now i came to learn chemistry

@FaizaF 5 жыл бұрын

Came here from Khan Academy. Much clearer presentation than the current Khan Academy video on limiting reagents. Thank you so much!

@adarsh65kumar 4 жыл бұрын

I actually didn't understand this video, so I went to the khan academy video after reading your comment.. to see if it would be any different! Strangely enough, I understood their explanation! KA video is more detailed than this one is, I don't understand why you guys didn't like it! In any case ,I'm greatful to both these educators !

@talalarfi2888 4 жыл бұрын

i like khan academy more.. they explain it better (my opinion)

@spoicat5459 2 жыл бұрын

@@adarsh65kumar Perhaps learning the same thing from multiple teachers helps better, just a hypothesis though, it happens to me too. If I learn something from one video and don't get it clearly enough, I watch a different one on the same topic and it gives me a different perspectives on the same topic, making it a bit easier to understand.

@AryanSharma-kh5zw 5 жыл бұрын

I love you professor Dave, you know all about the science stuff and you made everything as easy as a piece of bologna sandwich ☺

@ericvaish 5 жыл бұрын

yeah yeah!!!!

@viper_3 Жыл бұрын

That's why "He knows lot about science stuffs Professor Dave explains" 🎶🎵

@Rieleyhunt 3 жыл бұрын

1 week of not understanding class into 4 minute video. thank you chemistry jesus

@aneesonhisknees1263 8 жыл бұрын

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@ProfessorDaveExplains 8 жыл бұрын

i tell myself that every day! pretty please tell your friends :)

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+Professor Dave Explains i don't understand

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@HyacinthChynthia Жыл бұрын

Limiting Reagents and Percent Yield are one of the most confusing topics for me in Chemistry. Thanks to you, I understand it better. This is really helpful for students like me. Thank you very much!

@rafyraffee 8 жыл бұрын

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@samisiddiqi5411 3 жыл бұрын

It's been four years. Did you pass?

@rafyraffee 3 жыл бұрын

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@thatsme6998 3 жыл бұрын

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@joelherring4071 Жыл бұрын

Thank you Professor Dave for explaining this so well, I've got a final in a few days and need someone to actually teach me well. YOU ARE THAT MAN

@desireehaiflich6836 3 жыл бұрын

I was here for my retake for a chemistry test, and I fell in love with these videos! Thank you professor Dave

@sarahotto7165 7 жыл бұрын

Thank you so much! I wasted so much time on Kahn Academy confused as all hell, and you summed it up perfectly in less than 5 minutes!

@angeliahanaa 4 жыл бұрын

exactly!!!!!!!

@maazkazi2591 7 жыл бұрын

literally speaking, i just stumbled across this channel looking for revisions before mah test but i was bowled over by the content and clarity of the video. u literally have earned a new subscriber... :)

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@haidegee142 7 жыл бұрын

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@richardjohnson9820 6 жыл бұрын

This video is life saving, thanks tons for the explicit explanation.

@electromc9295 7 жыл бұрын

This is perfect for studying for my grade 11 chemistry exam. Thank you Professor Dave!

@mgrn7106 2 жыл бұрын

How is college 😂😂

@electromc9295 2 жыл бұрын

@@mgrn7106 no cap you be doin this on the daily in intro chem classes

@BigLizardEnergy 6 жыл бұрын

Probably the best thing I have ever subscribed to.. thank you.

@okthen9145 2 жыл бұрын

Thanks for the brief refresher. I love you!

@barbzgu6518 3 жыл бұрын

New subscriber here. Big thank you proffesor Dave for sharing these. It is indeed a big help to us students who are having hard time in understanding the world of chemistry. Peace Be with you.

@poorna4424 4 жыл бұрын

Indeed your way of teaching is extremely easy to understand you actually deserve 10m or even more than that

@noobageownerx3 7 жыл бұрын

thank u i love u i was getting rly stressed out about my chem exam but this video SAVED ME all the other vids i watch sucked

@Aurora-lw1gb 8 жыл бұрын

Thank you for this. I now fully understand how to compute for the theoretical yield.

@monicab1779 7 жыл бұрын

I'm a freshman in college and your videos are helping me so much!! :D thank you for these awesome videos!!!

@mohamedalj3ly929 7 жыл бұрын

Thanks a lot for your explanations.

@ladyinred396 7 жыл бұрын

Great! with you Chemistry is so easy! thank you for your tutorials!

@tonyzhang4368 3 жыл бұрын

This is enormously helpful!

@izzahshahirah4900 3 жыл бұрын

love ur expalnation so much..u help me a lottt, tq prof

@codosacho5924 9 жыл бұрын

Thanks for your explanation :)

@golaiet2 6 жыл бұрын

Thanks you helped me a lot !

@bigpotato4898 3 жыл бұрын

Thank you for teaching me in 4 minutes what my teacher could not teach for the past few months

@yousefelzoghpy1885 3 жыл бұрын

Thank you very much professor dave 💓

@waleedmian3114 5 жыл бұрын

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@GutterBratt 7 жыл бұрын

you are saving my life gr11 Chem exam tomorrow and 0 idea what I'm doing

@SA-be1bn 3 жыл бұрын

howd it go?

@mohammedsulaimanmohammedal1512 5 ай бұрын

i need answers how did it go?

@triple_gem_shining 9 ай бұрын

fun mix of puzzles and math! this is fun! im getting the answers right as well!! woo!!! thanks dave!!!

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@user-ww3pf4cr8c 3 жыл бұрын

Your explains is more than great Mr Dave 🖒🖒🖒🖒

@devmehta5658 7 жыл бұрын

sir can you please a separate video for difficult questions of limiting reagents and tricks to solve them.

@rehanroy9219 10 ай бұрын

Thank you professor dave. Because of your teaching skills my exam was easy

@applekingkong129 5 жыл бұрын

Thank you for your vids prof

@thechemmole 3 жыл бұрын

haha great! I use a similar example when explaining the limiting reactant to my students; sandwiches make for great examples!

@alexpapas99 6 жыл бұрын

Awesome analogy...

@fatimahanwar9324 7 жыл бұрын

thank you 🌸

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prof dave literally saves my life

@EetMyFlyingV 6 жыл бұрын

Thank you very much Sir.

@isaacchewe1825 3 жыл бұрын

Thanks Prof. Dave..

@spencersled7191 2 ай бұрын

Great teacher

@sanaaanwarr 7 жыл бұрын

Thank you sooo much.😊☺️

@ahmedhisham6598 6 жыл бұрын

you are a very good chemistry teacher

@jadisvaz 7 жыл бұрын

I have an A in Chem thanks to you!! my prof honestly gives me no help

@miaab7143 6 жыл бұрын

thank you 🌷

@BenjieKabakoff 3 жыл бұрын

You are amazing!!!

@semhararadom1491 Жыл бұрын

fantastic...How can I thank you .professor Dave

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I am come from Bangladesh. Really your lecture helped me

@spiritforlearning8829 5 жыл бұрын

How do you do the last question professor dave?

@jlpsinde 5 жыл бұрын

Very good!

@munyaipatientndivho 3 ай бұрын

Wow❤u teach well...I now understand chemistry ⚗️

@lucialandero9721 6 жыл бұрын

thank you so much.....

@angeliemaebonaobra4448 7 жыл бұрын

Thanks!

@memershub8353 3 жыл бұрын

Very nice explanation......in a small amounta time.... :)

@hudsonbeyore7786 Жыл бұрын

Khan academy took 20 minutes to explain what you did in 4 and yours is still better 💀

@sitotagirma9556 Жыл бұрын

thank you, professor you gave us, a clear explanation

@ChemistryTeacher-qz6vp Жыл бұрын

This is ez stupid face try takin an art degree then tell me what's hard

@hindah55 7 жыл бұрын

thank you ssso mmuch

@rb-deos8808 3 жыл бұрын

How did you get the mole in the problem???

@poorna4424 4 жыл бұрын

Sir if u have time please try to make a video on equivalent concept in chemistry really hard to get feel and intiution of that topic I would be very very thank ful to you ( from India Telangana)

@idaraa1162 5 ай бұрын

Bruh how did I understand this in 5 minutes but not in a 2 hour class.😩❤️

@boogiewoogit5597 Жыл бұрын

Dammit Dave, that’s a glorious flowing mane you have

@panlaura3541 2 жыл бұрын

quick question, when we getting the theoretical yield for CH3COOH, why we taking 21.4g as our final answer, not 21.42g. I went back and rewatch the sig figs chapter, but it still couldn't help me with the result. Thank you in advance for helping !

@valeriejackson7416 Жыл бұрын

its 3 sig figs so you wouldn't add the 2

@mavycarrasco370 5 жыл бұрын

so for the same reaction, if i change the masses of the reagents, could the limiting reagent change? or is it always the same for the same reaction?

@ProfessorDaveExplains 5 жыл бұрын

yep it totally depends on how much you have of them!

@jinkang8009 Жыл бұрын

thanks professor dave!

@ChemistryTeacher-qz6vp Жыл бұрын

If I had $1 per everytime I called someone a stupid face I'd be rich

@tcg-astral 6 ай бұрын

@@ChemistryTeacher-qz6vpI think your the stupid face here 🤣🤓

@user-xi8yh8qi9j Жыл бұрын

Am I missing something or is the first conversion factor at 2:37 totally not equal to one?

@sogomomogoso1032 7 жыл бұрын

thanks

@ansamsertawi367 Жыл бұрын

Where were you the whole year good sir...

@WeirdSpaghetti Жыл бұрын

holy shit bro ty

@JuhoHartikainen 7 ай бұрын

The final percent yield 89.3% is a little off because of a rounding error: 19.1 ÷ 21.42857 ≈ 89.1333% ≈ 89.2%. Don't round to sig figs too early in the process and you should be fine 😊

@user-abd_almer313 Жыл бұрын

رقم افوغادرو 6.022×10²³ رقم ٦ هذا المقصود به كاربون . الكتلة المولية : العنصر × كتلته . C⁶ × 12 . عندما يحصل تفاعل كيميائي العنصر يتغير من جهة اليسار إلى اليمين اي النواتج ، لذلك يجب حساب مول جديد وهذه هي الطريقة : - قبل التفاعل الكيميائي البروبان × عدد المول / الكتلة المولية = المول . - بعد التفاعل الكيميائي المول × عدد المول الجديد / عدد المول القديم المول المحصول × عدد البروبان / عدد المول .

@noelliekouedan6743 4 жыл бұрын

Do you HAVE to find out how much of both reactants can react with each other to subtract and find the excess.

@noelliekouedan6743 4 жыл бұрын

Well like the amount of excess

@mawadaabdalaal9916 2 жыл бұрын

عاد يا بروفيسر ديف انت الزيك منو 😍..تتعلى ما تتدلى

@sraaahsraaah9793 2 жыл бұрын

"if you don't understand stoichiometry clap your hands"👏👏

@sraaahsraaah9793 2 жыл бұрын

👏👏

@Jean-qg6gx 6 жыл бұрын

Professor Dave is the best of the best... oooops

@jiinjung1445 4 жыл бұрын

Hi, professor Dave. May I ask you why the answer of the question is 89.3, not 90? I thought sig fig would be 1 since the one with the fewest sig fig is 100 (1 sig fig). Sorry if the question is too silly :( and I very apprieciate your well-made videos.

@jiinjung1445 4 жыл бұрын

if anyone else could reply to me, I would also very apprieciate.

@Tech-cy9yo 3 жыл бұрын

Legend...

@mya4855 4 жыл бұрын

sophmore taking ap chem with no chemistry background. you made this much easier to understand, thank you!

@lmaoo6948 Жыл бұрын

thank u chemistry jesus

@ceeces 3 жыл бұрын

I still don’t know how did he get the stuff that appeared in 1:39 Update: I got it

@oliverlopez4236 7 жыл бұрын

why did you round two sig fig, when calculating?

@ProfessorDaveExplains 7 жыл бұрын

no reason, just to keep it tidy

@emilyfridman6308 6 жыл бұрын

At, 3:59 is the chemical CO , Carbon and Oxygen or Cobalt?

@ProfessorDaveExplains 6 жыл бұрын

CO is carbon monoxide! All elemental symbols have just one capital letter, so cobalt is Co.

@user-me1pw6zh1w 11 ай бұрын

when converting to moles in the ex. in 1:45, why can't I convert between the substances after I have just the first substance in moles? and also why do I get different result while doing it in comparison to just calculating it separately? 10g NH3* 1 mole NH3/ 17g NH3= 0.588 moles NH3 0.588 moles NH3* 1 mole CO2/ 2 moles NH3= 0.294 moles CO2 --------while calculating separately will give me 0.227: 10g CO2* 1 mole CO2/ 44g CO2= 0.227 moles CO2

@user-me1pw6zh1w 11 ай бұрын

ok so the answer is because if I do that, I will get the amount of the other substance in moles that will theoretically react flawlessly with the first substance and not the actual amount of the substance. I don't know if anybody needs it but there you have it

@Zixxer_rider 7 жыл бұрын

This is great work, but unfortunatley it would be nice if the problem showed how the understanding of dimensional analysis played a role. But other than that it helped me get to an answer!

@ProfessorDaveExplains 7 жыл бұрын

i have a separate clip on dimensional analysis, take a look!

@Krankenwagen757 Жыл бұрын

Thank you, chemistry jesus

@ChemistryTeacher-qz6vp Жыл бұрын

Shut up stupid face

@SummerDiablo 5 ай бұрын

Guys pls someone explain how to find the actual yeild if not given

@adr5617 3 жыл бұрын

if during the experiment, you only included 97% of grams of 1 of the reactants, would you still get the same substance you’re expecting? only that, you wont get the theoretical yield amount in grams? OR the whole experiment would be wrong because the expected substance wont happen?

@adr5617 3 жыл бұрын

oh wait!!! i think, we can still get the same substance for as long as we have the reactants necessary. the change in grams in the reactants does not affect the expected substance, only the amount in weight afterwards. please tell me if im right or wrong, Prof Dave. :) if im right or wrong, why or why not

@aldunlop4622 Жыл бұрын

@@adr5617 That’s right. Change the amount of inputs only affects how much of the product you get. In the bologna example, no matter how much you change the amount of bologna or bread, you always end up with bologna sandwiches.

@poorna4424 4 жыл бұрын

Sir please please I beg your pardon infinite please video on equivalent concept in chemistry