Math Olympiad | A Nice Algebra Problem | VIJAY Maths

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VIJAY Maths

VIJAY Maths

Ай бұрын

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Пікірлер: 72
@biswanathbera1260
@biswanathbera1260 Ай бұрын
Unnecessarily lengthy. Just get abc=√(100×200×300) =1000√6.. a=1000√6/200=5√6, b=1000√6/300=10√6/3 and c=1000√6/100=10√6. Adding a, b and c we get 55√6/3.
@sy8146
@sy8146 Ай бұрын
Thank you for explaining. [My method:] (ab)(bc)(ca)=6,000,000 ∴ (abc)^2=6,000,000 ∴ abc = ±1000√6 ∴ a = (abc)/(bc) = (±1000√6)/200 = ±5√6 b = (abc)/(ca) = (±1000√6)/300 = ±(10/3)√6 c = (abc)/(ab) = (±1000√6)/100 = ±10√6 ∴ a+b+c = ± (5 + 10/3 + 10) √6 = ±(55/3)√6 0, c
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Very Good 😊
@user-ji5su2uq9m
@user-ji5su2uq9m 26 күн бұрын
this is the normal method. Why VIJAY does use the complex method?
@dyrattanak2248
@dyrattanak2248 28 күн бұрын
Why you go to far, if we know a,b,c a = √150, b= √200/3, c= √600 a+b+c = √150+ √200/3+ √600= 55/3 √6
@satyanarayansharma9364
@satyanarayansharma9364 24 күн бұрын
Bilkul
@RealQinnMalloryu4
@RealQinnMalloryu4 Ай бұрын
10^10 2^52^5 1^12^1 2^1 (b ➖ 2a+1) 10^20 2^55^4 2^1^14 2^1^12^2 1^1^1^1^2 1^2 (c ➖ 2b+1) 10^30 2^55^6 2^1^13^2 1^1^13^2 3^2 (c ➖ 3a+2)
@urmilas5356
@urmilas5356 29 күн бұрын
Nice example with enough best tricks 🎉
@N_Kumar26
@N_Kumar26 26 күн бұрын
LCM of (1,2,3)=6 6abc=6cx100=600c 3abc=3a×200=600a 2abc=2bx300=600b Add 11abc=600(a+b+c) ab×bc×ca=100x200x300 (abc)^2=(1000)^2×6 abc=1000√6 11x1000√6=600(a+b+c) a+b+c=110/√6=(55√2)/√3
@N_Kumar26
@N_Kumar26 26 күн бұрын
About quadrilateral kzfaq.info/get/bejne/nMCBeZlixsDTd4E.html
@thomasharding1838
@thomasharding1838 15 сағат бұрын
A long time ago you determined that a squared = 150, and b squared = 200/3, and c squared = 600. Extract the square roots of those values and add them up.
@Wynb824
@Wynb824 23 күн бұрын
Find out the ratio of a:b:c by dividing those eqs, then just use k method
@sie_khoentjoeng4886
@sie_khoentjoeng4886 Ай бұрын
Let p=10a, q=10b, r=10c, then pq=1, qr=2 and rp=3 And (pqr)^2 =6 pqr=√6 or r=√6 since pqr=1 By same way, p=(√6) /2 and q=(√6) /3 Here a+b+c=10p+10q+10r =10(p+q+r) =10(√6+(√6)/2+(√6) /3) = 10 (11/6 √6) = 110/6 √6.
@marcgriselhubert3915
@marcgriselhubert3915 Ай бұрын
(a, b and c are of same sign. ab).(bc).(ca) = 6000000 =(abc)^2, so abc = 1000.sqrt(6) or abc = -1000.sqrt(6) *If abc = 1000.sqrt(6) then a = abc/bc = 5.sqrt(6), in the same way b = (10:3).sqrt(6) and c = 10.sqrt(6) Then a +b +c = (55/3).sqrt(6) *If abc = -1000.sqrt(6) then a, b, c are the opposite of the former values and a +b + c = (-55/3).sqrt(6)
@satrajitghosh8162
@satrajitghosh8162 23 күн бұрын
a b * b c * c a = 6 * 10^6 a b c = 1000 √6, - 1000 √6 a + b + c = 10 √ 6 *(1 + 1/2 + 1/3) , - 10 √ 6 *(1 + 1/2 + 1/3) , a + b + c = 110 /√6, -110 /√6
@vijaymaths5483
@vijaymaths5483 23 күн бұрын
Yes answer is same but don't leave denominator as rational , do rationalise the denominator 👍
@abdeltifelbihel3076
@abdeltifelbihel3076 Ай бұрын
From 1 and 2 : c=2a From 1 and 3 : c= 3b ca= 300 so : 2a^2= 300 then : a^2= 150 so: a=5√6 * c=2a so : c = 10√6 * b= c÷3 then : b= 10√6/3 a+b+c = 15√6+10√6/3 a+b+c= (45√6+10√6)/3= 55√6/3
@UrievJackal
@UrievJackal 29 күн бұрын
You have just forgotten a minus, while solving a^2=150. Btw, I used the same way. (3)÷(2) gives a/b =3/2 and so forth...
@andreysidor9912
@andreysidor9912 28 күн бұрын
аb/ac=b/c=100/300=1/3 b=c/3, bc=c^2/3=200, c=√600 b=200/√600, a=300/√600 a+b+c=55√6/3
@sudhakaranpillai9623
@sudhakaranpillai9623 Ай бұрын
a=5√6,b=10√2/√3,c=10√6 a+b+c=5√6+10√2/√3+10√6 =15√6+10√√2/√3 =(15√6.√3+10√2)/√3 =(15.3√2+10√2)/√3 =(45√2+10√2)/√3 =55√2/√3=(55√6)/3
@nalapurraghavendrarao6324
@nalapurraghavendrarao6324 Ай бұрын
Such a laborious tedious of solving .if you multiply all equations and taking square root We get abc=1000√6 which is equation (4).divide eq 4 by ab,bc ,ca to get a,b,c. Add a,b,c to get required answer.
@tapaspatra6148
@tapaspatra6148 6 сағат бұрын
It's completed .If we do by ratio of proportion, answer will be 11 and very easy
@julietavakian5380
@julietavakian5380 Ай бұрын
Your method is too complicated ! I found the result using proportions! b=100/a; b=200/c; 100/a=200/c; a=c/2. Because ca=300, then cxc/2=300; c^2=600;c=10sq.root of 6;a=5sq.root of6; b=10sq.root of6/3; a+b+c= 55sq.root of6/3
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Thanks for sharing!
@EllmarRosales
@EllmarRosales 29 күн бұрын
(abc)*2=™[(100)(200)(300)]; abc=(10)[10sqrt(2)][10sqrt(3)]; Then c=10sqrt(6) a=5sqrt(6); b=10sqrt(6)/3 so that a+b+c=[5sqrt(6)]+[10sqrt(6)/3]+[10sqrt(6)] a+b+c=[5+10/3+10]sqrt(6) Or a+b+c=(55/3)sqrt(6)
@Rocio62154
@Rocio62154 29 күн бұрын
SENSATIONAL PROFESSOR!
@vijaymaths5483
@vijaymaths5483 29 күн бұрын
Thanks
@santokhsidhuatla7045
@santokhsidhuatla7045 Ай бұрын
b=100/a bc=200 C=200/b=200/100. X a=2a Ca=300 2a*a=300 a^2=150 a=150^1/2=12.25 b=100/12.25=8.16 C=300/12.25=24.49 a+b+c=44.90
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Well try 👍
@crazyindianvines1472
@crazyindianvines1472 Ай бұрын
Great explanation
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Glad you liked it
@crkr1955
@crkr1955 Ай бұрын
Very lengthy procedure indeed Simply find out c/a You have ca Multiply U get c Then finf out a n b Add a+b+c This is done in 40vsec Any sum should b done in 1 minute only
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Good, very good 👍
@NhaNguyen-cx1ri
@NhaNguyen-cx1ri Ай бұрын
ab=100 bc=200 ca=300 >>a=100/b c=200/b ac=100b×200b 100b×200b =10000b 10000b=300 b=3/100 ab=100>> a=100:3/100 =10000/3 Ca=300 >>c=900/10000 C=9/100 a=10000/3 b=3/100
@superiorlyrics8326
@superiorlyrics8326 Ай бұрын
👏👏
@kidas0808
@kidas0808 29 күн бұрын
I have another solution for this math problem. a*b=100: b*c=200: c*a=300: b=100/a: b=200/c: c=300/a 100/a=200/c: a=sqrt(150): b=100/sqrt(150): c=300/sqrt(150) a+b+c=sqrt(150)+100/sqrt(150)+300/sqrt(150)=550/sqrt(150)=302500/150=2016.666666...
@mythilir1358
@mythilir1358 21 күн бұрын
a100, b-0c-200 100+0+200=300
@Srikanthvedios
@Srikanthvedios 14 күн бұрын
How to got A2 value .u r not displayed. Display that value also
@andryvokubadra2644
@andryvokubadra2644 Ай бұрын
ab = 100 bc = 200 ca = 300 =========== Metode I ab*bc*ca = 100*200*300 = 100*6*10000 (abc)² = 100*6*10000 abc = ±10*√6*100 = ±1000√6 a = ab*ca/abc = 100*300/(±1000√6) a = ±30/√6 b = ab*bc/abc = 100*200/(±1000√6) b = ±20/√6 c = bc*ca/abc = 200*300/(±1000√6) c = ±60/√6 a + b + c = ±(30+20+60)/√6 a + b + c = ±110/√6 ========== Methode 2 ab/bc = a/c = 100/200 = 1/2 a/c = 1/2 --> c = 2a bc/ca = b/a = 200/300 = 2/3 b/a = 2/3 --> b = 2a/3 ca = 300 (2a)a = 300 2a² = 300 a² = 150 a = ±5√6 a + b + c = a + 2a/3 + 2a a + b + c = 11a/3 a + b + c = 11(±5√6)/3 a + b + c = ±(55√6)/3 a + b + c = ±110/√6 ========= Method 3 As video ========= • • • Do we other method? Comment below 🙏🏻🙏🏻🙏🏻
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Good try..Thanks for sharing! 😃 Yes there is also one more method as well to solve but it will take longer video length so I couldn't solve that but if you wish I can make a separate video by using another method.
@andryvokubadra2644
@andryvokubadra2644 Ай бұрын
​@@vijaymaths5483 3:26 with this result, it's 4th methode 😊😊😊 You can check manually the comment below. . . then you resume it for some methodes in other video 👌🏼👌🏼👌🏼
@Fmacian59
@Fmacian59 Ай бұрын
Muy bueno. 👍👍👍
@vijaymaths5483
@vijaymaths5483 Ай бұрын
Thank you!
@kadappadevarmani9616
@kadappadevarmani9616 6 күн бұрын
Why u have put bc in the nr. ..plz.give mathematical reason
@sumit-mn6ys
@sumit-mn6ys 27 күн бұрын
Super explanation 👍
@vijaymaths5483
@vijaymaths5483 27 күн бұрын
Thank you ⚘️
@prakritipattanayak7423
@prakritipattanayak7423 20 күн бұрын
This math is related to which standard/class?
@Danieswors
@Danieswors Ай бұрын
55√6/3
@AllanPoeLover
@AllanPoeLover Ай бұрын
Why discarded negtive root ?
@crkr1955
@crkr1955 Ай бұрын
Why this lengthy method
@vijaymaths5483
@vijaymaths5483 Ай бұрын
The problem can be solved by various methods Instead of solving in shortcuts we should also know the other ways too.
@crkr1955
@crkr1955 Ай бұрын
But olympiad questions should be solved in less than a minute. I m too tutoring for olympiad
@brajeshreshamiya3821
@brajeshreshamiya3821 22 күн бұрын
Bhai tum solution de do.....jo padha Raha usko bhi anguli karte hai....tum ek KZfaq channel bana lo ​@@crkr1955
@nantesloire
@nantesloire 27 күн бұрын
Keine gute Lösungsmöglichkeit ... statt in einander zu multiplizieren , wäre besser dividieren ...
@satyapatrudu9802
@satyapatrudu9802 15 күн бұрын
20000
@RayArias
@RayArias Ай бұрын
You for got to carry the ±.
@user-rw7de5oh1b
@user-rw7de5oh1b 27 күн бұрын
Проще почленно перемножить ивозветсти в квадрат сумму аивис
@vijaymaths5483
@vijaymaths5483 27 күн бұрын
जि हां
@subbaraob8474
@subbaraob8474 28 күн бұрын
Why need payment for download
@ajeethpandey
@ajeethpandey 29 күн бұрын
Took 11 min for one min problem !
@chesettianandkumar4492
@chesettianandkumar4492 8 күн бұрын
Jai shree Ram 🙏
@vijaymaths5483
@vijaymaths5483 8 күн бұрын
Jai shree Ram🙏🙏
@jamesjacob8863
@jamesjacob8863 28 күн бұрын
a+b+c =600 😅😅😅😅😅
@krishansaxena7889
@krishansaxena7889 27 күн бұрын
hopeless solution. This man made it complicated.
@vijaymaths5483
@vijaymaths5483 27 күн бұрын
Thank you so much ⚘️ It shows your mindset how you are having😊
@sanjeevroy824
@sanjeevroy824 10 күн бұрын
Thora bare karkay likhia
@vijaymaths5483
@vijaymaths5483 10 күн бұрын
Thik hai 👍
@trevordsilva506
@trevordsilva506 Ай бұрын
Ask an expert .extra 2AB qualified hole sq man
@KhinMaungSan-qc9uv
@KhinMaungSan-qc9uv 7 күн бұрын
Easy,/
@guerrino50
@guerrino50 29 күн бұрын
A=100 B=0 C=200
@raghuvennelakanti2851
@raghuvennelakanti2851 27 күн бұрын
Why do you call it math olympiad? your explanation is for 3rd graders.
@vijaymaths5483
@vijaymaths5483 27 күн бұрын
Math Olympiad organises exams from students of grade 1 to grade 12 here I can't mention a particular grade for every problem so it's kind of knowledge to share with everyone for quick practice.
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