mimic logic gets harder and harder

  Рет қаралды 670

Bobby The Bandit

Bobby The Bandit

Ай бұрын

Mimic Logic, Level me level 3

Пікірлер: 6
@flarklooney
@flarklooney Ай бұрын
11:00 Box #7: "1 Mimic is hiding in a black box." If this is true, then black Box #1 is a Mimic. Both red boxes become Mimics because they both say: "The top row has no Mimics." Box #5 says: "Diagonal down left from me is a Mimic." which can't be true from original presumption, making 4 Mimics total which can't be true; therefore, Box #7 is a Mimic. That makes Box #1 and Box #5 true. This leaves 2 Mimics out of 4 boxes - 2 of which say the same thing; therefore, either both red boxes are true or both are Mimics. If both red boxes are true, that means box #4's statement of: "1 Mimic is hiding in a red box." means 'Exactly 1 mimic is hiding in a red box.' If both red boxes are Mimics, that means box #4's statement means 'At least 1 Mimic is hiding in a red box.' I think box #4's statement of: "1 Mimic is hiding in a red box." means 'Exactly 1 mimic is hiding in a red box.' making boxes #4 and 6 Mimics. Please let me know if that's what it means.
@ArcheoLumiere
@ArcheoLumiere Ай бұрын
That's what I got out of it too
@betree6809
@betree6809 29 күн бұрын
all i got was box 2 and 3 are the same which defends 1 and 4 agrees with 1 which makes 3 boxes left
@flarklooney
@flarklooney Ай бұрын
14:45 Box #7: "The leftmost column contains no Mimics." If this a MImic, that makes boxes #1 and 4 also Mimics making a total of 3 Mimics and thus *_all_* remaining boxes must be true. But Box #3 can't be true because it says: "The top row contains no Mimics." making 4 Mimics; threrefore, Box #7 must be true. This makes boxes #1 and 4 true and because their statements are true, box #6 is also true and Box #5 becomes a Mimic. Box #9 says: "The rightmost column contains is no Mimics." If this is true, no blue box would be a Mimic -which contradicts Box#6. That makes Box #9 the 2nd Mimic and Box #2 becomes true. Boxes #3 and 8 are undeterminable. 😢
@betree6809
@betree6809 29 күн бұрын
because of the fact that there is too many boxes that say their rows have no mimics then the simplest thing to do is eliminate those boxes if box 9 is true then box 3 is true then box 1 is true and theres only two boxes left so its safe to assume box 9 is a mimic if only box 3 is true, then box 1,2,3,4,6,7 are true which makes 3 boxes remaining 5 that opposes 7 8 that opposes 2 the elimination of the too many defensive boxes which ended up being 9 the reason why i started at 9 was because it leads to the outcome with the most box usage i think thats the answer idk
@flarklooney
@flarklooney 29 күн бұрын
@@betree6809 I like your method of getting the most box usage by rows. I try to do that too but I saw that there was a lot of boxes with the same color o I started there 1st. But your method was quicker in discovering the 1st Mimic. Very nice!
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