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Thermochemistry: Heat and Enthalpy

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Professor Dave Explains

Professor Dave Explains

8 жыл бұрын

What is heat? It's not just a movie with Pacino and DeNiro. Learn all about heat, and more importantly, enthalpy! Energy exchange is a big part of chemistry.
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Пікірлер: 411
@mariovanderwal1695
@mariovanderwal1695 3 жыл бұрын
I love how he explains things as if I were 7 years old but without it seeming insulting
@mohammadaljarwan719
@mohammadaljarwan719 3 жыл бұрын
Fr😂
@caru3257
@caru3257 2 жыл бұрын
do you know who has the video for the six year old?
@somasch7552
@somasch7552 2 жыл бұрын
@@caru3257 tyler dewitt but idk if he has vids about thermochemistry
@CrankyRayy
@CrankyRayy 2 жыл бұрын
Idk he’s pretty condescending
@lalalanding234
@lalalanding234 Жыл бұрын
That's how one understands this well!!!
@josephpalmer3082
@josephpalmer3082 5 жыл бұрын
Jesus coming to save me for my chem exam lmfao
@mikeoxlong2077
@mikeoxlong2077 3 жыл бұрын
🙏, You made me laugh
@mujtabaktk6452
@mujtabaktk6452 3 жыл бұрын
🤣🤣🤣
@herbertant4096
@herbertant4096 2 жыл бұрын
@@mikeoxlong2077 it's Jesus bruh
@caru3257
@caru3257 2 жыл бұрын
I had a test on this, I would pray.
@sopchan3554
@sopchan3554 2 жыл бұрын
HAHAHAHAHAHAAH AMEN😭🙏
@andress9713
@andress9713 6 жыл бұрын
Most underrated science channel. College hack
@nathanwidjaja3652
@nathanwidjaja3652 4 жыл бұрын
college??? im a freshman in high school
@Waiter1986
@Waiter1986 4 жыл бұрын
@@nathanwidjaja3652 why do so many freshmen take chem. At my school, freshment take bio and then after that u can choose (among other things) either chem or physics, so sophomores usually take chem
@bamb8s436
@bamb8s436 4 жыл бұрын
@@Waiter1986 In my country this is taught in junior year of high school
@gen2208
@gen2208 3 жыл бұрын
@@bamb8s436 I learnt this in high school I was 16
@bamb8s436
@bamb8s436 3 жыл бұрын
@@gen2208 yeah same
@rashialimbona1078
@rashialimbona1078 3 жыл бұрын
I owe so much to your channel, Professor. Your videos are direct and very easy to understand. I'm studying for an admission test and you have been such a big help.
@PunmasterSTP
@PunmasterSTP Жыл бұрын
Did you already take the test, and if so, what was it and how'd it go?
@gabriellaunderwood1731
@gabriellaunderwood1731 7 жыл бұрын
I had to miss a class on this yesterday. What I watched in this 4 minutes taught me almost everything that my classmates learned in 2 two hours. Thank you so much!
@deepakghugardare8453
@deepakghugardare8453 5 жыл бұрын
Gabriella Underwood At which standard did you study this?
@jmmifsud1
@jmmifsud1 5 жыл бұрын
That's because lecturers have no experience in anything to do with learning and cognition - so they are robots - they just write or read notes which you take down.
@aditibisht22
@aditibisht22 4 жыл бұрын
@@deepakghugardare8453 tum 11th class m ho. Hain na? Lol
@stereotypo1
@stereotypo1 4 жыл бұрын
"I would drop this class, but it is the only place I can get any sleep."
@PunmasterSTP
@PunmasterSTP Жыл бұрын
I know it's been six years, but how'd the rest of your class go?
@aivareysala9526
@aivareysala9526 5 жыл бұрын
I watch the ads all the way through to make sure my chemistry Jesus gets his Adsense 🥺✨
@ProfessorDaveExplains
@ProfessorDaveExplains 5 жыл бұрын
my best disciple!
@hightttech
@hightttech 4 жыл бұрын
@@ProfessorDaveExplains : 11. Thou shalt not 'SKIP'
@rholin0997
@rholin0997 4 жыл бұрын
Sorry Dave, i've had add block on for a while so i sent you some patreon to make up for it. You can thank Aivarey for making me feel bad. : )
@kandypham2435
@kandypham2435 8 жыл бұрын
I'm so glad I found this channel BEFORE my final exam! Cramming for a midterm tonight and I've learned so much in just one hour. THANK YOU!
@PunmasterSTP
@PunmasterSTP Жыл бұрын
I know it's been seven years, but I just have to ask. How'd the midterm and final go?
@pbower4378
@pbower4378 5 ай бұрын
@@PunmasterSTPlol this comment actually made me giggle cause I was about to ask the same thing 😂 I have a gen chem exam in a week and I’m NERVOUS.
@PunmasterSTP
@PunmasterSTP 5 ай бұрын
@@pbower4378 I love making comments like these, and I've actually gotten a few people to respond, even after a decade! Good luck on your upcoming exam. I'd say that if you'd be so inclined, asking questions and engaging in the comments on educational videos might help prepare a bit for it 😃
@rohanrustogi5463
@rohanrustogi5463 7 жыл бұрын
Dude you are a beast man. Your videos are short and sweet goes straight to the point, keep it going David Grohl.
@jimmycarter5987
@jimmycarter5987 2 жыл бұрын
I'm going back through material to study for my ACS exam for GenChem II, and he has been an incredible help. He explains concepts and equations so simply I don't feel like I have to spend hours trying to figure it out. Thanks Professor Dave!
@PunmasterSTP
@PunmasterSTP Жыл бұрын
Did you already take the ACS exam, and if so, how'd it go?
@jimmycarter5987
@jimmycarter5987 Жыл бұрын
I did already take it. It went well. I’m not sure exactly what I made, but it was a big part of my grade and I ended up bringing my grade from a C to a B!@@PunmasterSTP
@kylerivers922
@kylerivers922 6 жыл бұрын
This taught me more in 4 minutes then my chemistry teacher has taught me all year
@cunted2241
@cunted2241 Жыл бұрын
blud had about thermochemistry all year 💀
@PunmasterSTP
@PunmasterSTP Жыл бұрын
I know it's been a few years, but how'd the rest of your chemistry class go?
@aaaa8784
@aaaa8784 6 жыл бұрын
Your vids are making my MCAT prep more feasible. Thanks!
@PunmasterSTP
@PunmasterSTP Жыл бұрын
Did you end up taking the MCAT, and if so, how did that (and med school) go?
@thaer25100
@thaer25100 5 жыл бұрын
You explained this in a 4 minutes video better than a 2 hour lecture by my professor
@PunmasterSTP
@PunmasterSTP Жыл бұрын
I know it's been a few years, but I just came across your comment and was curious. How'd the rest of your chemistry class go?
@jeweljeandyanntaojo9695
@jeweljeandyanntaojo9695 6 ай бұрын
i manifest that i will have 96 and above grade in advance chemistry, pls lord🙏🙏
@b6howell
@b6howell 7 жыл бұрын
Shouldn't the 2nd answer at 3:10 say that the delta H is -1780.6kJ, not kJ/mol? It is still -890.3kJ/mol regardless of how many moles you combust, correct?
@ProfessorDaveExplains
@ProfessorDaveExplains 7 жыл бұрын
oh man! what a dumb error. yes it should just be kJ. thanks for catching that!
@lienterryn9152
@lienterryn9152 4 жыл бұрын
why can delta H unit be Kj and Kj/mol?
@sebastianriedel8627
@sebastianriedel8627 4 жыл бұрын
And I believe in the comprehension example it is the other way round. KJ/mol and not kJ
@sarabourke7081
@sarabourke7081 4 жыл бұрын
@@sebastianriedel8627 Actually good either way in this example because talking about methane (CH4), of which there is only 1 mol. When providing molar enthalpy it should always be absolutely clear from the context or question which substance it is referenced to. In other words, because the question is talking about methane and the balanced equation indicates only one mol of methane, the enthalpy could be listed in kJ or kJ/mol (of methane). But if the question had asked about producing 10.0g of water, you would have to use -890.3 kJ for the equation, as balanced, or -445.2 kJ/mol (of water produced)
@pigeonlove
@pigeonlove 3 жыл бұрын
At 0:52 onward it would have been easier to understand, in my opinion, if the order was reversed, eg reactants to products and dH positive =products required energy = endothermic reaction
@daraquesca1886
@daraquesca1886 3 жыл бұрын
2:32 Thanks Dave, this is the first time I learned the difference between dietary calories and chemistry calorie.
@subhashreepanda4189
@subhashreepanda4189 4 жыл бұрын
This man taught me thermodynamics in half an hour which my chem teacher couldn't in half a month. U r amazing sir ! Keep up the good work!!
@PunmasterSTP
@PunmasterSTP Жыл бұрын
How'd the rest of your class go?
@Someone-youmaykn0w333
@Someone-youmaykn0w333 5 ай бұрын
Tbh I stil dont understand what I'm doing
@c.j3608
@c.j3608 5 жыл бұрын
Not sure why I need to attend school anymore? I just learnt more in 58 seconds than I have all semester. Thanks for being the awesome science teacher that don't have!
@not_obsidian
@not_obsidian 4 жыл бұрын
Ever since I got into high school i can’t help but notice that teachers are so lazy
@PunmasterSTP
@PunmasterSTP Жыл бұрын
How'd the rest of your studies go?
@calitreesweet
@calitreesweet 11 ай бұрын
when he said delta H is energy in bonds of product - reactant that just saved my life
@mei-xing
@mei-xing Жыл бұрын
Any Indian here?
@gugumakhubela339
@gugumakhubela339 3 ай бұрын
Yes
@alexiskironde7413
@alexiskironde7413 4 жыл бұрын
Thankyou for the video on Thermochemistry: Heat and Enthalpy.
@FaheemAhmed125
@FaheemAhmed125 4 жыл бұрын
Very informative series. The men like PROFESSOR DAVE are the essence of the humanity. If he continues to lots of other chemical topics he will be welcome. May God bless him time and enthusiasm to teach many other difficult topics in physical, inorganic, organic and applied chemistry.
@tharushipolgahadeniya4249
@tharushipolgahadeniya4249 5 жыл бұрын
Thank you.This video was helped me lot to clarify my answers.This is the best channel for science students.
@JessicaAbe
@JessicaAbe 3 жыл бұрын
at 3:45 why did you change delta H to a positive in the actual equation when it was originally a negative ?
@zdrasbuytye
@zdrasbuytye 6 жыл бұрын
I love this guy videos. He can explain everything very clearly.
@AK-op4be
@AK-op4be 2 ай бұрын
Your videos are my holy grail, thank you so much!~ You explain it so clearly & the visuals help so much.
@breezema3371
@breezema3371 Жыл бұрын
Studying for ap chem test this is really coming in clutch
@forsakengod6668
@forsakengod6668 Жыл бұрын
this was so clarifying and concise thank you sir
@user-pe2tv3xs9i
@user-pe2tv3xs9i 11 ай бұрын
Hi sorry but i dont understand how dix you find this result attend the end or thé video , can you please explain it ? 3:44
@jollyjokress3852
@jollyjokress3852 4 ай бұрын
Maybe it helps to know that the -890 is kJ/mol
@TARGETIIT2024
@TARGETIIT2024 11 ай бұрын
Correct the unit of it :- ∆H = -890.3 KJ/mol
@4m0d
@4m0d Жыл бұрын
Thank you so much for your videos sir, your videos have been very useful for both physics and chemistry in my current academic year.
@PunmasterSTP
@PunmasterSTP Жыл бұрын
How'd the rest of your year go?
@sroydetroy6404
@sroydetroy6404 4 жыл бұрын
Thank god there are people like professor Dave who can actually explain the material eloquently and in an interesting way and not bore you to death like my stupid chemistry teacher in school.
@PunmasterSTP
@PunmasterSTP Жыл бұрын
Yeah for real. Out of curiosity, how'd the rest of your chemistry class go?
@MsBaileybailey
@MsBaileybailey 4 жыл бұрын
2020 and he's still the best!
@arielgomes3168
@arielgomes3168 3 жыл бұрын
This is exactly the information I was looking for. Thank you!
@nukegold4565
@nukegold4565 3 жыл бұрын
The explanations helped me a lot, however the "comprehension" I had trouble with because I learned it much differently
@libelldrian173
@libelldrian173 3 жыл бұрын
Yeah, I don't get it either. He didn't say anything about it in the video. Apparently you just divide the mass you have by the mass of your substance in one mole and multiple it by the enthalpy given...
@jensenlanglois9138
@jensenlanglois9138 Жыл бұрын
you probably have figured it out 2 years later lol, but because the enthalpy is in units of KJ/mol, by knowing how many moles are actually being used in the reaction will give us a multiple to know how much of that energy (enthalpy) (which is per mol), is actually released. take this for example, though not precise, say i have a pizza of 4 slices, and that pizza gives me 800 calories for a whole pizza. now, one may wonder how many calories for 2.5 slices of pizza. I must divide the amount i want to know by the total amount per pizza, then multiply that by the energy for 1 whole pizza. boom, there's your answer
@Zahratalnoor
@Zahratalnoor 2 жыл бұрын
I finally understand enthalpy from ur 4min vid, and its better than those 40min or hour and a half crappy vids!
@medbrain7490
@medbrain7490 5 жыл бұрын
Thank u so much. So impressive and easy to understand
@elliehague5278
@elliehague5278 3 жыл бұрын
If a chemical equation has a delta heat value given, if the heat value is negative, does that mean the reaction is exothermic? just double checking, it can be kinda confusing, i love your videos thanks!
@PunmasterSTP
@PunmasterSTP Жыл бұрын
Yes.
@aladddinm2485
@aladddinm2485 3 жыл бұрын
the most important point in thermodynamics you said ,.. thanks Prof. Dave!!
@ayushaggarwal906
@ayushaggarwal906 2 жыл бұрын
What is the difference between q and H when both are defind as energy
@arjungupta3095
@arjungupta3095 2 жыл бұрын
Professor Dave is the GOAT.
@ShafayKhan-ch8se
@ShafayKhan-ch8se 13 күн бұрын
Hi can you please explain the comprehension part to me, I don't understand the method that you used?
@williamrice5150
@williamrice5150 8 жыл бұрын
Wish I found these videos 3 months ago. This is so helpful! But quick question. Why do we keep a positive answer? If the Delta H is negative and its Exothermic, shouldn't we right the number as a neg? If the problem had stated that 890 were positive, would the 556 have been negative? Whats the relationship there in writing the answer with the correct sign(_/+)?
@ProfessorDaveExplains
@ProfessorDaveExplains 8 жыл бұрын
+William Rice oh the delta H would be negative, it's the semantics of how the question is worded, it asks how much energy is released. it doesn't make sense to say a negative amount of energy is released, the negative sign simply means that it is released, specifically 556 kJ of it.
@atulpandey4308
@atulpandey4308 4 жыл бұрын
I was having the same problem.But now I am happy.
@lauraweynants8224
@lauraweynants8224 Жыл бұрын
im currently a student living off of subsidies but i promise! when i get my first paycheck when im graduated! i WILL make a donation to you to THANK YOU!
@MrGorling
@MrGorling 7 жыл бұрын
Hi could you pleas walk me through the calculation. I get that 16.0 g is the molemass but why divide everything by 1 mole? If use the formula m/M = n then n X 890 i get the same answer but units won't match.
@ProfessorDaveExplains
@ProfessorDaveExplains 7 жыл бұрын
so we take the mass and then multiply by 1 mole/molar mass to get it in moles. then we multiply by delta H/1 mole, because the delta H is telling us the enthalpy change per one mole, enthalpy is a molar quantity. besides, we need to cancel out moles to get an answer in kJ.
@nikhilphulari1394
@nikhilphulari1394 2 жыл бұрын
Love from India professor your teaching is So Amazing
@yeeoowyeeoow
@yeeoowyeeoow 8 жыл бұрын
Thank you so much for these great videos. Summing up with the comprehension check is awesome! Very very helpful! Thank you.
@watermelonely2248
@watermelonely2248 6 жыл бұрын
Chemistry Jesus. Thank you!
@_fiminim_
@_fiminim_ Жыл бұрын
I am so thankful for this video man
@Kumabear_945
@Kumabear_945 Жыл бұрын
I still don’t get it 🙃🙃🙃 is there any other topic I should know before this one to understand it better
@chrisgoldbach4450
@chrisgoldbach4450 5 ай бұрын
Bill gates wants to recreate butter with this.
@asiahassan947
@asiahassan947 4 жыл бұрын
from where did we get 16g f NH4 in the comprehension question
@ProfessorDaveExplains
@ProfessorDaveExplains 4 жыл бұрын
that's the molar mass
@nikan4now
@nikan4now 4 жыл бұрын
Good video. Could you please answer my question professor or anyone who is an expert? So if enthalpy of products is lower that means (u+p*rho) is lower. But the fact that heat is released and the temperature of products is higher means that "u" or internal energy must be higher! How do I reconcile these two ?
@bird9
@bird9 3 жыл бұрын
Q = △H when T and P are constants ? Have just P as a constant is sufficient, no ?
@favourihunwo1867
@favourihunwo1867 Жыл бұрын
Please prof. Dave explain why there is 16.0g CH4 and it is coming from.
@ProfessorDaveExplains
@ProfessorDaveExplains Жыл бұрын
Molar mass
@favourihunwo1867
@favourihunwo1867 Жыл бұрын
@@ProfessorDaveExplains ohh thanks
@olaleye_tof
@olaleye_tof 3 ай бұрын
Thanks for this video!
@ishaaqahamed3888
@ishaaqahamed3888 3 жыл бұрын
Can someone help me through this dilemma? Work is defined as the (W = F * s) when a body moves a straight distance under a constant force. However, since for a curved path of varying force, we break down the curve to infinitesimal segments where the Force is locally constant and the distance (ds) is essentially straight. Thus, for this tiny line segment, we apply the Work concept and we have dW = Fds. Summing up all the dW would give us the total Work. This is why dW = Fds (and never dW = Fds + sdF). I have the following problems: Under what circumstances is Enthalpy explicitly defined for a system? How can we say that dH = du + PdV + VdP when we never say dW = Fds + sdF?
@pradoprado9993
@pradoprado9993 4 жыл бұрын
Just to make sure, I thought that, if the energy of the bonds in the products is greater than the energy of the bonds in the reactants then it should be exothermic and viceversa would be endo. Am I wrong?
@sarabourke7081
@sarabourke7081 4 жыл бұрын
You are wrong. All of the chemicals in the reaction represent the 'system'. If you end up with more energy in the final state of the system...like in the bonds of the the products... then the system has gained energy from the 'surroundings' making the reaction endothermic with a positive enthalpy. Usually this is manifested as a temperature drop in the surroundings because the products take energy away from the surroundings.
@pradoprado9993
@pradoprado9993 4 жыл бұрын
@@sarabourke7081 That makes sense, thanks for the explanation.
@realizejust415
@realizejust415 2 жыл бұрын
Is the amount of heat denoted by q is the same as H (enthalpy) contained in the law of ΔH=Hp-HR In short, is the amount of heat q the same as the enthalpy H?
@kidzbop38isstraightfire92
@kidzbop38isstraightfire92 Жыл бұрын
2:30 You need to have "enthalpy" or "heat" at the top of the background when you are giving definitions/units..i kept having to rewind to see what you were referring to.. every "slide" should have what you're referring to so that each slide can be standalone.
@ET-oq9mg
@ET-oq9mg 4 жыл бұрын
Thank you Professor Dave for your explanation of enthalpy. Could you please make a video to explain effect of expansion valve in thermodynamics. what kind of effect it does on gases and gases take energy from surroundings.
@carultch
@carultch 2 жыл бұрын
The expansion valve, also known as a throttling valve, is a device that produces an irreversible drop in pressure, with no work or heat exchanged with the surroundings. It is known as an isenthalpic process. Unlike turbines that have a counterpart component like a compressor, that does the same, but in reverse, there is no counterpart to the throttling valve that raises pressure isentahalpically. Time would need to run backwards for such a component to exist. An application of the throttling valve, is the vapor compression refrigeration cycle that we use in refrigerators and air conditioners. From state 1 to state 2, we compress the vapor to high pressure; from state 2 to state 3, we condense the vapor to a liquid while it rejects heat; from state 3 to state 4, we expand the liquid through this valve to a 2-state mixture of liquid and vapor at a cold low pressure, and from state 4 to state 1, we boil the liquid in the evaporator so that it absorbs heat from the cold space. In concept, we could use a turbine from state 3 to state 4, but it wouldn't be practical to build such a turbine. To keep it simple, we use a throttling valve to drop the pressure. A throttling valve can also be controlled by a thermostat (called a thermostatic expansion valve) to govern the flow rate and differential pressure of an air conditioner.
@marry8294
@marry8294 2 жыл бұрын
Why is it said that it is not possible to measure enthalpy, but only the change in enthalpy, when enthalpy is equal to the amount of energy stored in one mole of a substance? This means that when energy is measured in a substance, we know the enthalpy of a substance. Is this true?
@ShawnDypxz
@ShawnDypxz 6 жыл бұрын
For those who are confused about conventions and saying the conventions in physics and chemistry are different It's same . It's different because of the different way we deal those things in physics and chemistry. We focus about the change of internal energy in chemistry but we focus on the heat and work done by gas in physics. for eg When heat is supplied to a system of gas and it expands , in chemistry we write ΔU = q - W (W as work done by gas) So If I add Heat to system it;s internal energy increases , right ? So ΔU should be positive (U2-U1) U2 will be greater than U1 . So change will be positive .So , there's a positive sign. And When gas does work , it's spending it's internal energy to do work . So , if you hadn't supplied heat to the system , ΔU will be negative , (U2-U1) , as U1 is greater than U2. So that's it. ΔU =+q - W So for the same scenario in Physics (Adding heat to the system and gas doing work ) , this would be the gas Added Heat = Positive change in Internal Energy of gas + Work done by gas It's the same as if you had $200 and you spent $100 on foods and $100 on rents. SO $200=$100+$100 You gave something , you get the things out of the same worth . So in Physics that would be Q=ΔU + W Notice the + there. It's not convention there. It's a simple math like I did in above money example. Let's make this exact same thing like I did for chemistry. When I put "W" on Left hand side , It will become , Q-W =ΔU Same equation I hope you understood. So again, it's not the convention. It's how we deal with them. But it's easy and time efficient if we deal them differently using the conventions.
@marcosaraque5101
@marcosaraque5101 5 жыл бұрын
In either case you start with first law of thermodynamics: ΔU =+q + W, but for a gas expanding, the work is defined to be negative as the gas is doing work and it loses energy. Thus, for an expanding gas: ΔU =+q - W. The confusion usually lies in whether the system is doing work has work done to it, which decides the sign of W
@arrogant_little_punk9701
@arrogant_little_punk9701 Жыл бұрын
Sir i just have one request can you please make a Playlist !!!
@angeliemaebonaobra4448
@angeliemaebonaobra4448 7 жыл бұрын
Thank you Professor Dave
@bryce7285
@bryce7285 2 жыл бұрын
Professor Dave, you're the man.
@aspektn.5066
@aspektn.5066 4 жыл бұрын
Seen once. Shall be seen again. Good vid.
@tatiana1310
@tatiana1310 4 жыл бұрын
2:29 My mind just exploded
@nathanboomershine4888
@nathanboomershine4888 3 жыл бұрын
Thanks, you're better than my actual professor.
@nadiahulwat.1788
@nadiahulwat.1788 2 жыл бұрын
Thank you Proffesor for helping us😁 in this subject,
@thanosthemadtitan1273
@thanosthemadtitan1273 7 жыл бұрын
love that opening 😂
@arway4766
@arway4766 3 жыл бұрын
Thank you for existing
@zaynabgassa1358
@zaynabgassa1358 4 жыл бұрын
I have a question, Don't you have to know the aggregation state to calculate enthalpy? Or is there a way to know it without it being mentioned in the question ...
@miguelduarte75
@miguelduarte75 6 жыл бұрын
+Professor Dave, do you have any videos where you talk about nutrition and exercise? I want to know more about ketogenic diet, muscle building and healthy foods.
@ProfessorDaveExplains
@ProfessorDaveExplains 6 жыл бұрын
not yet, but i do plan to do a nutrition series eventually!
@virupannamedikinal
@virupannamedikinal Жыл бұрын
Thank you
@Morpheus-zw4px
@Morpheus-zw4px Жыл бұрын
In this equation ΔH = (q + w) + PΔV: Can someone please explain the difference between work that is part of the internal energy and the other PΔV-work?
@captainkc6014
@captainkc6014 3 жыл бұрын
is there any terms that define the property of material,if it requires 60 sec to change the temperature by 1 degree in ambient air.
@helloimnisha
@helloimnisha 8 жыл бұрын
At 00.40, deltaH is described as the energy stored in bonds of products minus the energy stored in bonds of reactants. But how can energy be stored in bonds? Since formation of bonds releases energy, bonds should be defined by the amount of energy they RELEASE and not by the energy they possess. Am I right?
@ProfessorDaveExplains
@ProfessorDaveExplains 8 жыл бұрын
+Nisha Kamble when orbitals overlap to form covalent bonds, they are storing energy, that chemical energy is then released when the bonds are broken. on an energy diagram, think of this as potential energy. but it may be a matter of semantics.
@omw5032
@omw5032 3 ай бұрын
someone explain the comprehension part is that a formula i have yet to learn?
@deepakyadavmothuku3015
@deepakyadavmothuku3015 Жыл бұрын
How come entalphy and heat transfer are equal at cnst pressure and temperature
@tahabasrai4421
@tahabasrai4421 7 жыл бұрын
Great explanation, but I still have no idea how to do the qn at the end >.
@vidushanpat6894
@vidushanpat6894 4 жыл бұрын
@@gb7168 thank you so much for your kind explanation
@umairafatima5616
@umairafatima5616 4 жыл бұрын
no.of moles=maas/molar mass No.of moles=10/16 No.of moles =0.625 moles Heat released for 1 mole= 890Kj Heat For0.625 moles= 890×0.625 Heat released for 0.625moles=556Kj
@younesmecabih7959
@younesmecabih7959 4 жыл бұрын
if delta H for 1mole is negative , the energy is realesed from the systeme therefor it's an exothermic reaction so how could the enthelpy be negative for anoother amount of energy
@nthumara6288
@nthumara6288 7 ай бұрын
what is the difference between enthalpy and amount of heat tranfere
@rassimsimou1594
@rassimsimou1594 Жыл бұрын
Good
@basanttarik1561
@basanttarik1561 4 жыл бұрын
how can we measure the change in enthalpy if we can't measure the enthalpy?
@sarabourke7081
@sarabourke7081 4 жыл бұрын
we can't directly measure the change in enthalpy in the system...but we can measure how it affects the temperature of the surroundings...calorimetry!
@pankajkulkarni5647
@pankajkulkarni5647 3 жыл бұрын
Very nice your teching .
@eddiewyckoff5741
@eddiewyckoff5741 3 жыл бұрын
I really like this channel; however, the first part about bonds has an issue. Bonds do not "store energy." It takes energy to break bonds; it releases energy to form them. So to keep with the correct sign convention, an approximation of enthalpy should be reactant bond energies - product bond energies, NOT product bond energies - reactant bond energies.
@shahlaanjum9080
@shahlaanjum9080 3 жыл бұрын
I can't understand one thing. if more energy is released so will the bonds formed be stronger than those broken . If so how can it be true when it looses its enthalpy content
@GauravMishra-bo3hj
@GauravMishra-bo3hj Жыл бұрын
Damn man your videos really helping out for jee
@user-wy8cs2bb2z
@user-wy8cs2bb2z 11 ай бұрын
Mere bhi , bahut confusion tha isme
@bugtibaloch8240
@bugtibaloch8240 5 жыл бұрын
Sir u are the wonderfull teacher awesome sir
@user-pe2tv3xs9i
@user-pe2tv3xs9i 11 ай бұрын
Hi sorry but i dont understand how dix you find this result attend the end or thé video , can you please explain it ?
@arunprakash942
@arunprakash942 4 жыл бұрын
Hi sir, I watched your heat and enthalpy video at now, that is really very nice sir however in your end of the video you gave the comprehension question for find the answer and at the same time you are giving answer also but i don't know how do i find the answer so would you please explain the heat formation and how did you are calculated the answer from the comprehension
@divyeshparadava5629
@divyeshparadava5629 8 жыл бұрын
Nice , now I am little bit clear with enthalpy, but tell me if the enthalpy is the state property that means it is different from one state to another right..??? So if Enthalpy of H2O at 30°, 1atm and Enthalpy at 32° ,1atm are different...?? Or same...?? And and does the energy of bond change with atmospheric property like temperatures, pressure ...???
@ProfessorDaveExplains
@ProfessorDaveExplains 8 жыл бұрын
+mech div nope bond enthalpies should be independent of any of those parameters, as far as i'm aware.
@elixtirr2611
@elixtirr2611 5 жыл бұрын
My freaking savior
@atulpandey4308
@atulpandey4308 4 жыл бұрын
Best "Guru" ever....
@JAL07
@JAL07 3 жыл бұрын
Thank you, chemistry Jesus!!!!
@yeppeotrisha3098
@yeppeotrisha3098 5 жыл бұрын
I love this channel
@Ace-ry1gs
@Ace-ry1gs 9 ай бұрын
Thank you professor Jesus
@ashrafel-shahawy7655
@ashrafel-shahawy7655 6 жыл бұрын
i don`t understande the example in the end of the video
@r.i.p.volodya
@r.i.p.volodya Жыл бұрын
01:13 Heat is NOT a FORM of energy. Heat is a PROCESS. Heat is the TRANSFER of energy due to a difference in temperature. Please read Peter Atkins: "Four Laws that drive the Universe", p.30.
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