Stoichiometry Involving ΔH
Рет қаралды 11,047
10 жыл бұрынThis video is a discussion about how stoichiometry can be used to determine the amount of energy absorbed or released by a chemical reaction (i.e. the change in enthalpy) given the quantities of reactants consumed or products produced by the reaction.
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@BensChemVideos 4 жыл бұрын
CAUTION: This video has a mistake at the end, as several have pointed out in the comments. The correct answer to the problem is -318.3 kJ, NOT -1273 kJ. Apparently I forgot to divide by the "4 mol H_2O" in the last conversion factor. To those who corrected me, thank you SO much! You guys are awesome! -BeN
@kurtlangeberg1329 8 жыл бұрын
I think the answer is supposed to be -318.5. I also came up with that same answer and I would like to think 3 people can not come up with the same wrong answer.
@hmusicfranczak 9 жыл бұрын
Your videos are very helpful, and you are also very easy on the eyes ;) Thank you for your time!
@tashabaker6071 9 жыл бұрын
Maybe I'm wrong, but should you also include dividing by 4 in the equation? Answer would then be -318.5 KJ.
@margueritethomas8180 9 жыл бұрын
I also got this answer. Can someone please explain?
@anthonyelenga8939 8 жыл бұрын
+Tasha Baker I also got that same answer, he forgot to divide by 4
@moonafter767 5 жыл бұрын
really helpful. Thx this video helps a lot.
@syedumair3172 10 жыл бұрын
Nice
@aaronn.3397 7 жыл бұрын
I got around -318 KJ as well...
@julmart1370 8 жыл бұрын
the answer is wrong, it should be -318.2, but the equatio is right!!!
@juliabickram1892 9 жыл бұрын
Why isn't delta H in kJ/mol?
@anthonyelenga8939 8 жыл бұрын
+Julia Bickram the moles cancel each other, only the kj are left
@AppleSahil02 10 жыл бұрын
the new haircut suits you
@jlj1757 7 жыл бұрын
I too got -318.2 ( gyazo.com/776f3eefab9731891da7d121ebe1c40e ) I believe that he forgot to divide by 4 in the second parentheses.
@josenava4555 7 жыл бұрын
Hi Still don't understand
Conquer Chemistry
Рет қаралды 27 М.