Understanding Common Mode Rejection Ratio

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Күн бұрын

This video explains the common mode rejection ratio, or CMRR, and in particular why CMRR is an important figure of merit for differential voltage probes.
Learn more about R&S Oscilloscopes: rsna.us/60569SNWm
Discover more about R&S Oscilloscope Probes: rsna.us/60579SNWW
Timeline:
00:00 Introduction
00:19 Suggested viewing
00:34 About differential amplifiers
01:29 About common mode signals
02:10 About common mode rejection ratio (CMRR)
03:10 About CMRR values
04:03 About differential probes
05:24 Summary

Пікірлер: 11

@Kenobiii 8 ай бұрын

I'm getting into RF engineering and your videos help me soooooo much to understand many of the concepts a lot better!!!! It's all explained so well and clear, thank you so much!

@pauldenisowski 8 ай бұрын

Thank you! I sometimes tell people that I'm making the videos I wish that I had when I started in engineering :)

@Floyd..B 8 ай бұрын

@@pauldenisowski And you are doing a perfect job at that.

@IcRDlayout 6 ай бұрын

真強你

@stud_mechatronic_polito_22 2 ай бұрын

thank you, now it's clearer; I was getting crazy with that indian accent -_- but apart the indian accent "all about electonics" is a great yt channel.

@nareshkumar4207 8 ай бұрын

Thanks for this good lecture

@pauldenisowski 8 ай бұрын

Thanks for the feedback!

@KingdomAddict 7 ай бұрын

Thank you for the lectures; they are very helpful, thank you. Question: Should Vout be Adm(V2-V1) instead of Adm(V1-V2) shown in the video?

@pauldenisowski 5 ай бұрын

Yes - thank you for catching that. Vout is Adm * (Vplus - Vminus). In retrospect, I should have used Vplus an Vminus instead of V1 and V2. Thanks again for the correction!

@user-jc9kn4uy2u 4 ай бұрын

What I don't understand, is that if noise is present in both inputs of the OA, when you subtract them, you should see 0V. So i do not understand why it's amplified.