8.01x - Lect 30 - Simple Harmonic Motion, Energy Considerations, Torsional Pendulum

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Lectures by Walter Lewin. They will make you ♥ Physics.

Lectures by Walter Lewin. They will make you ♥ Physics.

9 жыл бұрын

Simple Harmonic Oscillations - Energy Considerations - Torsional Pendulum - Nice Demos
Assignments Lecture 30, 31 and 32: freepdfhosting.com/180a4925b0.pdf
Solutions Lecture 30, 31 and 32: freepdfhosting.com/13b0dfbb45.pdf

Пікірлер: 145
@solidstatejake
@solidstatejake 5 жыл бұрын
The fact that you take an active role in your channel is one of the coolest things there is! Thank you for your work!
@Raphael_NYC
@Raphael_NYC 7 жыл бұрын
I so enjoy your lectures and your love of the material. I have to watch it more than once and that is one of the joys. Thank you. raphael santore
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
watching it more than once is very useful as the beauty of physics then becomes part of your culture.
@Kanishka_1801
@Kanishka_1801 4 жыл бұрын
Sir I am a 11th grade student from India....your lectures are so awesome. The experiments you do really help getting the feel of what we usually study as exhaustive theory and derivations. The lectures really do make you fall in love with physics!
@DERKONIG12345
@DERKONIG12345 3 жыл бұрын
The old good times, when U-tube meant just a a U-tube....:)
@OzieLombok
@OzieLombok 2 жыл бұрын
I have been watching your lectures since 2014 when I took master degree in science education and focused on physic education. I have got deeper of understanding physic for teaching my senior high school students by watching your teaching methods. very much helping me and awesome. thank you very much sir,,, from Indonesia
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 2 жыл бұрын
Excellent
@akankshaverma2503
@akankshaverma2503 6 жыл бұрын
I wanted to thank you sir. Your lectures really help in grasping the important concepts. I was facing trouble in understanding this concept. Now it is better :)
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
:)
@user-hs7qg5tt8t
@user-hs7qg5tt8t 5 жыл бұрын
look this over again when i take signal processing course , still impressive and valuable thanks sir ^^ together with lesson 10 so neat , in depth, amazing , so great to have you
@user-hs7qg5tt8t
@user-hs7qg5tt8t 5 жыл бұрын
i feel like myself have better understanding of the importance of the uncertainty of measurements than before , thankyou sir for being such a uniquely amazing teacher
@pat6595
@pat6595 5 жыл бұрын
Hello, Walter Lewin. Which science (physics or astronomy) book do you recommend me? (The style of 'A Brief History of Time'; 'Cosmos'; 'The Grand Design'). I'm learning how Nature works. So I want your recommendation of a science book. Thank you.
@wunxue
@wunxue Жыл бұрын
Professor has very elegant handwriting and sketch intuitive. He always has interesting demo for his theory. I wish I could have attended his lecture.
@ifrazali3052
@ifrazali3052 8 ай бұрын
you ARE attending his lectures
@UKSCIENCEORG
@UKSCIENCEORG 6 жыл бұрын
4:33 In Rod we trust!
@danielocitti7737
@danielocitti7737 4 жыл бұрын
Are you utilizing the chain rule or the product rule?
@saved4774
@saved4774 4 жыл бұрын
In that tube experiment, why don't you consider the air pressure?
@eugenioagolini6060
@eugenioagolini6060 5 жыл бұрын
Hi professor, i think i found my mistake, to find the work of the force with which i had to push down the liquid at the left side of the tube so that the liquid would raise up on the opposite side, i incorrectly assumed that the force was constant for all the delta h and equal to the force with which i had to maintain the equilibrium at the end, just like if i had to lift a rigid body with fixed mass, but then i noticed that for every dh the force would raise up proportionally with h, that's because the unbalanced mass in the system gets bigger and bigger the further I go down pushing, so the work would be (integral)--->S(rho)*Area*2h*g*dh, and not 2dMgy as i incorrectly assumed, the result of the integral is dMgy and not as i said before. If i could correct my error I owe it only to you professor, have a good day, greetings from italy!!
@abinbho
@abinbho 8 жыл бұрын
Hi Walter Lewin, i am really grateful for all the lectures of yours that are on internet for us to see. I watch your videos everyday and it's always interesting and awesome. I am a high school student studying Alevel in Nepal and these lectures helps me a lot to learn beyond our syllabus and for my own exams. Thankyou so much !!
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 8 жыл бұрын
+Pasa Production Thank you for your kind note. Happy 2016
@John10086
@John10086 5 жыл бұрын
Hi, I have a question about the assigment 8 ,8.4, c). The formula i got for r1/r2 (r1/r2=x) was : x+2x^2+x^3= (M*G/V^2*r2) = 0.53. But in the answer sheet it says it equals to 15.9 and I´m not sure what I´m doing wrong. Is this equation correct : x+2x^2+x^3= (M*G/V^2*r2)?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 5 жыл бұрын
Plse assume that the solutions of this classic problem are correct. Please check your (and our) calculations carefully - (the solutions were done by a graduate student). Unless you are 100% sure that our solution is wrong, I don't want to go over our solutions as that is very time consuming.
@John10086
@John10086 5 жыл бұрын
Thanks, you were right. I was plugging in the wrong values.@@lecturesbywalterlewin.they9259
@frenchy16785
@frenchy16785 4 жыл бұрын
Why should L have been longer in the liquid oscillation experiment?
@haldrianChannel
@haldrianChannel 6 жыл бұрын
Hi Prof, @24:25 when the water moves up on the right side of the u-tube, is there any loss of potential energy on the left side, since the water falls below the U=0 level?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
Look at the BIG picture. The net result is that I have moved some liquid vertically up. That means that the PE increased. Where I chose U=0 is IRRELEVANT. Listen to my words again and follow my arguments again.
@haldrianChannel
@haldrianChannel 6 жыл бұрын
Lectures by Walter Lewin. They will make you ♥ Physics. ah got it. Thank you for your time, sir.
@User39814
@User39814 6 жыл бұрын
haldrianChannel f
@CM-Gram
@CM-Gram 7 жыл бұрын
were questions prohibited during the lecture or they were cut out?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
questions were allowed. Remember there were typical 300 students in my audience. Students feel often embarrassed to ask questions with such a large audience. These students also meet twice a week with a "recitation" instructor (also a Prof at MIT but not the lecturer). Those classes have only 25 students and that's where they unload all there questions. That one of the major purposes of recitations.
@CM-Gram
@CM-Gram 7 жыл бұрын
Are the recitations different from the tutorials? And does the leader of the recitations hold a PHD degree too?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
recitations are run by Professors of Physics. Students ask lots of question - often related the that week's homework. They meet twice a week for an hour. Classes are about 25 students. I have been recitation instructor more than 30 times in my 43 years.
@eggonwalterlewinsshirt1071
@eggonwalterlewinsshirt1071 3 жыл бұрын
26:20 Can we Do this with Bernoulli's theorem
@InventTwig
@InventTwig 7 жыл бұрын
Professor I suppose that the 'l' @ 30:00 1. must be taken from the middle of the pipe OR 2.We can add the vertical parts of the pipe and then find the mass of fluid in the curved part by doing an integral over using small mass elements 'dm' is that correct professor?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
there are easier ways
@InventTwig
@InventTwig 7 жыл бұрын
Professor if I dump the fluid out and weighing it , then divide the weight by A*(rho) to get effective value for l ?
@JohnCena-gs1yv
@JohnCena-gs1yv 7 жыл бұрын
Sir, I have seen all of your lectures in 8.01x I want to ask that can I see lectures in 8.03 by skipping 8.02 or seeing 8.02 first is a must ?.
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
try it
@JohnCena-gs1yv
@JohnCena-gs1yv 7 жыл бұрын
I want to know whether 8.02 is a pre - requisite for 8.03 or are they completely different as I have waves and oscillation in my course this year and electricity and magnetism the next year. I thought whether I should do 8.03 first and postpone 8.02 for next year.
@yuanyi827
@yuanyi827 4 жыл бұрын
Dr.Lewin, I just want to prove that the actual “l” should have been taken a little bit larger than π(r1+r2)/2.(I only consider the bottom torus).r1 is the inner radius and r2 is the outer radius.I used integration to calculate the volume of a torus.But amazingly I got that the volume of torus is exactly equal to (π^2)*(r1+r2)a^2 =2A*l.So the bottom half of torus should have volume =A*l.I uses 3 different methods to calculate that and they all give me the same result. Can you explain me why l should have been taken a little bit larger.
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 4 жыл бұрын
Watch my lectures whereI I do it right and then learn what you did wrong.
@yuanyi827
@yuanyi827 4 жыл бұрын
Lectures by Walter Lewin. They will make you ♥ Physics. Thanks for your reply.Sir you use M=Alρ which l is equal to the the average length between the inner length of U-tube and outer length of the U-Tube.I think this u-tube is made of two cylinders and a half-torus is that right? I calculated the volume of this half-torus .Its volume is equal to A*(πR).(I also checked it on the Web)R is the major radius of this torus.Major radius R is the average between the outer and inner radius.πR is the circular bottom part of “l”So I get the total volume of this liquid is A*l.And the mass is Alρ.I think it is not an approximation. I think M is exactly equal to Alρ.Could you explain that further?I really don’t know where I did it wrong and I really want to know that.Otherwise I will have sleepless night.I am looking forward to your response.
@yuanyi827
@yuanyi827 4 жыл бұрын
@Lectures by Walter Lewin. They will make you ♥ Physics. Sorry for bothering you but could you tell me whether the reason why ”l” should have been taken a little bit larger have something to do with the formula of volume of the U-Tube ? I checked that formula but it is amazingly and exactly equal to the a cylinder with cross-sectional area A and length l.Which l is the average of inner and outer length of U-Tube.(the line you have drawn) I am looking forward to your response.
@suges2871
@suges2871 3 ай бұрын
@@yuanyi827did you find the reason why “L” should be a little larger
@mach2570
@mach2570 3 жыл бұрын
"l" in the differential eqn is taken as the displacement of the centre of mass of the displaced liquid, which will be higher than the "l" we get if we take the average of the two radii and measure it. Is this correct?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 3 жыл бұрын
I have no idea about what you are asking me. Search on line on how to calculate periods of oscillating liquids or use my lectures. I believe I cover that.
@mach2570
@mach2570 3 жыл бұрын
@@lecturesbywalterlewin.they9259 sir , I was attempting to answer the question asked in the lecture about why we should take "l" more than what is measured from the average of the radii.
@chakshupunj5943
@chakshupunj5943 5 жыл бұрын
At 30:00 you said L must be little bit larger then it's actual value. I think that's because of the thermal expansion of the liquid. Because when liquid will oscillate it's will loose some of it's energy due to viscosity (which will cause Damping) and that energy will be converted to heat, which will cause thermal expansion. Area is constant here, so the only thing that can change is the length of liquid column (This will give a tiny increase in volume also. ). I think that's the reason for L to be a bit larger.
@carultch
@carultch 4 жыл бұрын
Think about what properties of the liquid we assume to be uniform. Are they uniform in reality? Or is there position-dependence to properties of the liquid?
@jiriminarik6702
@jiriminarik6702 6 ай бұрын
@@carultch I will answer this since it is 4 years ago and will be probably burried anyway. The answer is due to density being dependent on the height. It is not constant. See previous lectures. If you would have linear column perpendicular to the board and you somehow oscilated fluid in it, the assumption would hold.
@eugenioagolini6060
@eugenioagolini6060 5 жыл бұрын
hello professor, at 25:19 you show that dM*g*y is the work of the force, shouldn't the amount of unbalanced mass be 2dM? and so the work would be 2dM*g*y
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 5 жыл бұрын
25:19 what I said and did is correct.
@eugenioagolini6060
@eugenioagolini6060 5 жыл бұрын
thank you professor, i couldn't figure out the right way of thinking about it, i'm struggling with this topic because my professor didn't handle it properly. With all respect my question wasn't meant in any way to question your preparation.
@tomhejda6450
@tomhejda6450 4 жыл бұрын
Think about the center of mass of the displaced fluid. It clearly moves only 1*l as it sits in the middle of the shifted fluid.
@coreywade3587
@coreywade3587 8 жыл бұрын
In the HW the astronaut ends up with negative blood pressure in the brain. What does this mean?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 8 жыл бұрын
which homework, which problem?
@safdershakil2401
@safdershakil2401 7 жыл бұрын
Sir, around 30:00 mins in the lecture you said that we haven't taken 'l' accurately , why is that ?or in other words why the value of 'l' should be a bit larger ?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
it's up to you to figure that out.
@safdershakil2401
@safdershakil2401 7 жыл бұрын
I'm not able to come up with a satisfactory answer.
@carultch
@carultch 4 жыл бұрын
At 36:38, the torsional constant kappa has a more interesting dependence on area, than just the number of square millimeters. The concept that matters is second polar moment of area, defined in a similar manner as moment of inertia. The essential difference is that density is dropped from the integral.
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 4 жыл бұрын
*Thank you carultch for you many thoughtful and very useful comments which you have made every day for the past few weeks. Please keep it up.* As a thank you note I'd like to send you a signed copy of my book "For the Love of Physics" if you don't have one yet.
@carultch
@carultch 4 жыл бұрын
@@lecturesbywalterlewin.they9259 No problem. Thank you very much for hosting your lectures, and the offer of your book. I enjoy discussing Physics, and am always seeking the opportunity to learn. You can PM me or email me carultch@gmail.com, and I can provide my address.
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 4 жыл бұрын
@@carultch plse send me your address in youtube. I will delete it so ONLY I will see it. make sure it is complete. I also want to know *which name I should use for the note in my book and for the picture that I will send you.* I may not be able to mail the book till Tue next week.
@savitridevi9632
@savitridevi9632 6 жыл бұрын
Professor.. what's your favourite experiment? :)
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
double slit diffraction of electrons kzfaq.info/get/bejne/aNN5npaop7Col3k.html
@brettweerasooriya3776
@brettweerasooriya3776 7 жыл бұрын
Hey do you know Dianna Cowern? AKA Physics Girl?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
Yes I do. I have met her at MIT and I have many pictures with her.
@brettweerasooriya3776
@brettweerasooriya3776 7 жыл бұрын
Have you seen her channel?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
yes
@idealthinker101
@idealthinker101 Жыл бұрын
If a tunnel is made through the centre of Earth, along an entire diameter, And, If an object is released at one end of the tunnel, Is it true that the object will be in Simple Harmonic Motion ?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 Жыл бұрын
its true if you assume that the density of the Earth is the same everywhere and you also have to ignore the temperature that will melt anhything - I have this as one of my bi-weekly problems
@blee6117
@blee6117 2 жыл бұрын
Hi Professor. In this lecture (22:55 min.) u mention that vellocity will be same for any moment in time due to cross section area of tube is not changing. But will it same or it will change by the time? Because derivative of (y) includes (t) and it is logical due to gravity. i think i misunderstood something or not? Thanks.
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 2 жыл бұрын
what I said is correct as liquid is incompressable.
@blee6117
@blee6117 2 жыл бұрын
Professor I got ur point. Thanks for lighting me up. I misunderstand ur sentence at 22:55 min. Thanks again.
@affandanish2594
@affandanish2594 Жыл бұрын
Sir, did the string broke? What was the summary of the tortional strain experiment?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 Жыл бұрын
question unclear
@affandanish2594
@affandanish2594 Жыл бұрын
@@lecturesbywalterlewin.they9259 Oh my god, Sir😳😳 I wasn't expecting a reply, Sir, I was asking that the demonstration of the tortional strain you were doing, the numbers of period at 10 rotations was still holding up with the calculated value , did you go beyond 10 times or it started to show permanent deformation after 10?
@affandanish2594
@affandanish2594 Жыл бұрын
@@lecturesbywalterlewin.they9259And I thought hard about the U-tube length you said it should be higher than (calculated average), Does the liquid lose contact with the ceiling of the mid section of U tube while moving?
@anesh1686
@anesh1686 3 жыл бұрын
Sir, can you please tell the answer of 30:00 question... I'm having sleepless night due to this question. But till now I didn't figure out the answer. It will be great if you please explain the answer. Thank you so much sir. Love from India ❤️.
@abhineetsharan4892
@abhineetsharan4892 4 жыл бұрын
Sir we love your videos , the very brilliance of your teaching does not let us lose our focus even once . Thank you so much for all of it as it makes the concepts crystal clear and easy to understand. ( at 36:41 though , the Mung's-Young's modulus is just memorable)
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 4 жыл бұрын
:)
@simrandeepbahal7594
@simrandeepbahal7594 7 жыл бұрын
Hello Professor Can u please tell me about the concept of centre of percussion in such physical pendulums please?? And thanks for your fantastic lectures
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
The Center of Percussion is the point on an extended massive object attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot. Translational and rotational motions cancel at the pivot when an impulsive blow is struck at the center of percussion.
@carultch
@carultch 4 жыл бұрын
It's also known as the "sweet spot" to baseball players. If the ball hits the bat at any other point, you'll feel a sting in your hands as they receive the reaction load from the ball's impact. Experienced baseball players strategically aim to have the bat hit the ball at this point, to minimize the pain in their hands.
@gnikola2013
@gnikola2013 6 жыл бұрын
Professor, I've notived that when measuring the torsion pendulum oscilation, when it was given 10 initial turns, the first full oscilation consisted of 17 turns instead of 20, and the second one, the one you actually measured the period of, consisted of only 13 turns. My guess is that there was permanent deformation that did not affect the period of oscilations, but the angle swept by the pendulum
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
very strange - I have no explanation for that. The amplitude would slowly decay due to air drag but not the number of oscillations. *A permanent deformation would not change the length therefore it should change the period of the oscillations - but you said it didn't.
@gnikola2013
@gnikola2013 6 жыл бұрын
Actually, it's not the number of oscilations what changes, but the amount of turns per oscilation (at least this is the case if what I understand for oscilation is the movement of the pendulum as it turns one way and then comes back). And the number of turns is directly related to to the angular amplitude. The original amplitude was 20pi, 20 turns per oscilation. Then, there where 13 turns, which translate to 7,5pi. So I think this phenomenon is being caused by air drag. Or at least I think so, my reasoning may be wrong
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
unclear what you want to say - when a torsional pendulum turns around twice it has made 1 oscillation. use google
@gnikola2013
@gnikola2013 6 жыл бұрын
I see, it can get difficult to make my ideas clear this way. Anyways thanks for answering my question and for uploading these amazing lectures! I'm about to start my bachelor's degree in physics and I find them not also useful but also very entertaining. Thanks for the available assignments and exams too!
@aman2426
@aman2426 3 жыл бұрын
I didn't know that glow in the dark chalk existed until 31:21
@five5059
@five5059 6 жыл бұрын
Dear professor, at 26:00 why are we adding potencial energy, i know in problems with conservation of energy (for example) its always mgh=(m*v^2)/2 so if we put mgh on the right side it will be negative, and in your case potencial energy has plus sign, why is that?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
when the liquid oscillates mechanical energy is conserved (KE + PE)
@five5059
@five5059 6 жыл бұрын
Lectures by Walter Lewin. They will make you ♥ Physics. Yes but PE is converted into KE so PE=KE which is equal to KE-PE=0 and in your equation its KE+PE=0, whys that
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
Mechanical energy is conserved (I have assumed that there is no heat loss due to viscosity in the liquid) thus KE + PE= C. It's NOT 0 and I do not have 0. Of course there is always some heat loss and thus the oscillation will die out. This is my last msg.
@five5059
@five5059 6 жыл бұрын
Lectures by Walter Lewin. They will make you ♥ Physics. Thank you for your time professor :) sorry for bothering you
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 6 жыл бұрын
you did not bother me. It seemed to me though that you wrote me before you had made an effort to understand the OBVIOUS!
@senselessnothing
@senselessnothing 9 жыл бұрын
Why should L be a bit larger? at 32:10 you mention it, but I see no reason as to why it should be larger.
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 9 жыл бұрын
Tasos Obscure Tasos, we use the length "l" in the diff eq to calculate the mass of the liquid. The volume of the liquid is Al, the mass is Al*rho. That is an approximation. To do this correctly you would have to do an integration of dm as a function of the radius of the bottom part of the tube. You will then see that the "average" value of "l" is somewhat larger than (l1 + l2)/2.
@carultch
@carultch 4 жыл бұрын
This simple calculation makes the first order assumption that the liquid is incompressible and inviscid. Meaning liquid density is uniform throughout the entire system, and all fluid friction is neglected. Density is not uniform in reality, because every real fluid will compress at higher pressures. It has to store evidence of that pressure somehow at the molecular level. Liquids in general are close to incompressible, much more than their gas counterparts. Water for instance, takes change from 1 to 22 atmospheres to increase its density just by 0.1%. An extreme example of a "stiff" liquid is mercury, with about 11 times the bulk modulus of water. "Stiff" only in terms of difficult to change its density, since liquids will easily change shape. An example of a liquid at the other extreme is acetone, about 1/3 the bulk modulus of water.
@ankanghosal
@ankanghosal 3 жыл бұрын
Sir please reply me . I am a huge fan of yours
@muhammadisrar1589
@muhammadisrar1589 5 жыл бұрын
When the length of second pendulum becomes four times what z the perid then???plz
@abhayshankar8762
@abhayshankar8762 4 жыл бұрын
Twice.
@carultch
@carultch 4 жыл бұрын
To see this in an example, consider the contrast in the design of the pendulum for the grandfather clock and the cuckoo clock. The grandfather clock's ~1 meter pendulum is built to have a period of 2 seconds, so each pendulum turning point ticks the seconds. The cuckoo clock has a pendulum about a quarter the length, and ticks twice a second. Grandfather clocks sound as "tick, tock, tick, tock" as the pendulum produces advances of the second hand. A cuckoo clock will make the sound "tick-a-tock-a, tick-a-tock-a" as its pendulum reverses each time. The turning points actually make the exact same sound. It is a psychological effect that makes us think they sound different.
@pranavdhawan4471
@pranavdhawan4471 3 жыл бұрын
Can Circular Motion be considered as SHM?
@carultch
@carultch 2 жыл бұрын
Yes. The projection onto the two axes of the plane of rotation, of an object in uniform circular motion, is simple harmonic motion.
@bite027_ketansharma6
@bite027_ketansharma6 6 жыл бұрын
I am from India And I read this is class 11 Our education system is broken
@SatishchandraChitrapu
@SatishchandraChitrapu 4 жыл бұрын
Ketan Sharma And how does statement two imply statement three?
@dhruvchaudhary3448
@dhruvchaudhary3448 11 ай бұрын
@@SatishchandraChitrapu as it is grammatically wrong
@Captain_Pikachu
@Captain_Pikachu 2 жыл бұрын
21:10 , To resume tomorrow
@g-force2745
@g-force2745 Жыл бұрын
"We have here a U-Tube..." Prophetic? lol. 😅 -G-Force
@JohnCena-gs1yv
@JohnCena-gs1yv 7 жыл бұрын
Sir, you said that any measurement without the knowledge of uncertainty is meaningless but some of the lectures at the later half of 8.01 you have not taken uncertainty into account. Why?
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
which lectures? and how many minutes into the lecture be very precise please
@JohnCena-gs1yv
@JohnCena-gs1yv 7 жыл бұрын
8.01x Lec.26 at 19:15 . Just to name one example
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
ha ha ha I made NO measurements! No timing at all!
@JohnCena-gs1yv
@JohnCena-gs1yv 7 жыл бұрын
You got me there sir thanks for clarification. :)
@JohnCena-gs1yv
@JohnCena-gs1yv 7 жыл бұрын
Sir can you please also tell whether or not I should skip 8.02 as those topics are next year in my course and continue to 8.03
@savitridevi6181
@savitridevi6181 2 жыл бұрын
Wow
@chandrushane
@chandrushane 5 жыл бұрын
Wat meaning of double dot theta
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 5 жыл бұрын
2nd derivative
@linnav.nguyen4628
@linnav.nguyen4628 5 жыл бұрын
Its the same as the angular acceleration :) One dot equals one-time-derivative(?)
@luchomolinari
@luchomolinari 9 ай бұрын
@withlove_moon
@withlove_moon 7 жыл бұрын
good evening proffesor .... I'm purva and I'm a science student preparing for the iit jee examination in 2017 ( considered the most difficult exam for sciences ) my syllabus is much vast than just what discussed about in the lectures..... is it possible to get help from you even beyond this syllabus . I mean can I contact you somewhere else if you are ready to help me out .... it will be really kind of you if you agree to help me ....hoping for a positive reply ....thank you very much .
@withlove_moon
@withlove_moon 7 жыл бұрын
if you wish to see my syllabus you can look up this book ..... physics by hc verma ..... it has all the topics 😊
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
I answer all physics questions if they take me less than 5 minutes. You can post questions here, only 1 question at a time. Keep it brief and clear and always refer to the lecture and the number of minutes into the lecture. Good luck on your examination!
@withlove_moon
@withlove_moon 7 жыл бұрын
Lectures by Walter Lewin. They will make you ♥ Physics. thank you sir ..... I'll be posting my problems soon .... tommorow I have a test so i will get back to you tommorow .... thank you so much for your support ..... Also I am facing problems in some topics which have no mentions in your videos ..... is there a solution for that
@withlove_moon
@withlove_moon 7 жыл бұрын
Lectures by Walter Lewin. They will make you ♥ Physics. Oh it's ok sir ....I'll do a few worksheets till your back .....and then ask .... honestly I would like to admit one thing ....I never used to like physics that much ...but after viewing your lectures I have started to actually love physics ...thank you so much
@withlove_moon
@withlove_moon 7 жыл бұрын
sir one more thing ....is it possible to contact you through email or whatsapp or something where I can send the pictures to the problems .... because my problems comprise of mathematical tools which is not possible to type .....so it will be a whole lot easier to share the picture
@godson200
@godson200 3 жыл бұрын
I feel the lecture was incomplete. It ended abruptly
@adnenabdessayed1813
@adnenabdessayed1813 8 жыл бұрын
Hi guys! I wanna thank you first for the amazing videos. However, I think we must take the moment of inertia of the bar into consideration while calculating the moment of inertia of the whole system (bar + 2 masses) . I'de appreciate it if you tell me why Mr Lewin didn't do so! :)
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 8 жыл бұрын
how many minutes into the lecture?
@adnenabdessayed1813
@adnenabdessayed1813 8 жыл бұрын
+Lectures by Walter Lewin. They will make you ♥ Physics. at 39:27. I thought I mentioned it, sorry
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 8 жыл бұрын
I am puzzled by your suggestion. Watch the video again. I am very specific about why the moment of inertia of the bar can be ignored. I mention that the bar has a very low mass (m) compared to the 0.4 kg. Thus the moment of inertia of the bar m*L^2/12 can be ignored in comparison with the moment of inertia of the 0.4 kg at a distance L/2 from the center of the bar. I then even mention "to a very good approximation".
@adnenabdessayed1813
@adnenabdessayed1813 8 жыл бұрын
thanks a lot. I was paying attention while watching but i kinda missed that. Thanks again :)
@aarjavjain1154
@aarjavjain1154 3 жыл бұрын
sir please bring lectures for chem and maths plzzzzzzzzzzzzz......love from INDIA🙏🙏🙏
@arpan2048
@arpan2048 3 жыл бұрын
He is a physics teacher 😂
@mohitoshdeb6579
@mohitoshdeb6579 3 жыл бұрын
i have seen a beautiful girl in most of your lectures ,in this lecture she was in black top (42:42) but nevertheless she is not more beautiful than your lectures and experiments.
@cfgauss71
@cfgauss71 3 жыл бұрын
She is indeed beautiful. However, during the lectures it's important to stay focused on your attraction to physics, not your physical attraction to the blonde.
@alexandraboehmke2102
@alexandraboehmke2102 7 жыл бұрын
U-tube lolol
@lecturesbywalterlewin.they9259
@lecturesbywalterlewin.they9259 7 жыл бұрын
:)
@aashsyed1277
@aashsyed1277 2 жыл бұрын
You tube
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