How to determine the Final (and Initial) course angle of a Great Circle Course??

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How to determine the Final (and Initial) course angle of a Great Circle Course??

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Күн бұрын

Many mariners and students struggle to determine the Final (and Initial) course angle of a great circle course between two geographical positions. This video focuses on the procedure to determine the initial (ICA) and Final (FCA) course angle, the quadrant, and the true course value.
I have used a number of different examples to explain the point lucidly to students.
Contents of this video will benefit mariners preparing for exams (written and oral examinations).
Mariners will also benefit by watching the following videos:
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Пікірлер: 62

@furkantok5298 2 жыл бұрын

The best maritime channel in the world mannn !!!!

@gauravrana1716 4 жыл бұрын

Sir , Thanks a lot for this outstanding explanation , I am sure this is the best video on KZfaq for initial and final course ,cleared doubts, really appreciate your hard work.

@dineshthesailor689 Жыл бұрын

Thank you Sir! Precise explanation....I was struggling from past 4 months to understand the concept and finally all my doubts cleared.. Thanks again Sir !!!

@sailorsingh4723 4 жыл бұрын

Really thankful to you for clearing this concept it was confusing me earlier.

@pranjulgupta4072 3 жыл бұрын

you are best teacher ever thankyou soo much for making this vedio

@discountcuppon 3 жыл бұрын

Hi good morning friends For preparation of second mate / DNS/ BSC nautical science/NCV come in #kundanpatna

@wizard5592 8 ай бұрын

i passed cargo stabilit and meterology by lookin ur vedio nd study(last month qustions are came based on your questions,some questions are exact same.) thank you sir

@mariner-cg3xx 2 жыл бұрын

Love from BANGLADESH ...you are very popular in our country ...

@SteeringMariners 2 жыл бұрын

:) Thank you so much my friend.

@anthonydenver8086 9 ай бұрын

Thank you Sir! this brilliant video cleared all my doubts on final course.. Grateful🙏

@raymondallenjhangiani7670 Жыл бұрын

Fantastic explanation ! Truly appreciate all your videos , Thank you 🙏 sir ! God bless you always 🙏😇

@ayazsayed9009 4 ай бұрын

The best explanation

@hanifmallik4704 3 жыл бұрын

Sir by watching this video's my doubts are all clear ...thnx alot sir❤️❤️❤️❤️

@BeardedOutlawInternational 3 жыл бұрын

Appreciate the effort, way better than what they teach at Eurotech !

@MrAnup964 4 жыл бұрын

you did a good job clearing my doubts

@joshuawilliams6210 4 жыл бұрын

Thanks :) that cleared up all my doubts .

@SteeringMariners 4 жыл бұрын

Excellent:)

@AakibKhan-ns6bh Жыл бұрын

sir EX 57 ka sums solve ho gaya thanks......😊😊😊😊 great help....

@anandgupta2588 4 жыл бұрын

you are a great teacher sir. thanks

@discountcuppon 3 жыл бұрын

Hi good morning friends For preparation of second mate / DNS/ BSC nautical science/NCV come in #kundanpatna

@yeasinfarhan4027 Жыл бұрын

Helped me a lot. I can't thank you enough

@amanchaudhary4313 Жыл бұрын

Well understood sir .

@parmeshwartiwari4211 3 жыл бұрын

Really it's helped me a lot... thank you sir

@SteeringMariners 3 жыл бұрын

You are most welcome:)

@pratikbillade2888 3 жыл бұрын

Understood Sir. Nicely explained 😃

@arvinkumar6187 2 жыл бұрын

very helpfull

@RishabhSingh-kc3tc 8 ай бұрын

It's a too good thing I got it everything !!

@ganeshviswanathmannarmanna6244 4 жыл бұрын

Nice explanation. great job

@discountcuppon 3 жыл бұрын

Hi good morning friends For preparation of second mate / DNS/ BSC nautical science/NCV come in #kundanpatna

@dev7020 2 жыл бұрын

Really helpful 👍

@hasanshaikh3004 3 жыл бұрын

Very useful video

@discountcuppon 3 жыл бұрын

Hi good morning friends For preparation of second mate / DNS/ BSC nautical science/NCV come in #kundanpatna

@ashutoshyadav1000 Жыл бұрын

Sir thanks and lots of love 🙏🙏🙏

@sumitkajla5563 2 жыл бұрын

great explanation sir

@hiphopforlife20 5 ай бұрын

Captain u r phenomenal , just 1 doubt ! Do we always substract the final course from 180 ? To get the outer angle , bcz in some questions in the book ! The answer states the internal angle !

@SteeringMariners 5 ай бұрын

Yes, the process remains the same.

@mohamedaljehani4049 2 жыл бұрын

Thank you very much

@mfaisal2873 2 жыл бұрын

Thank you Sir

@waelsailor5414 2 жыл бұрын

I can not thank you enough ,

@amangupta7303 3 жыл бұрын

Excellent

@josephadereni8202 6 ай бұрын

Draw vertex in latitude closer to equator?

@mariner-cg3xx 2 жыл бұрын

Sir thanks

@manikandans98315 3 жыл бұрын

Sir if Lat A : 40°N & Lat B : 40°S, then towards which pole we have to draw the triangle? Please answer sir...

@SteeringMariners 3 жыл бұрын

Then you can choose any pole:)

@shainmendis2564 5 ай бұрын

❤

@amanmishra6946 Жыл бұрын

Hlw sir, in great circle question can we take any pole?? Either north or south??🙏🏼🙏🏼

@Riderla 2 жыл бұрын

Sir, If dlong is 90 or more than 90 then vertex should be between A&B in samehemisphere , is it correct ?

@manjeetrathore6409 4 жыл бұрын

Sir can u tell when my A long is w and B long is E What will be the direction of initial course

@SteeringMariners 4 жыл бұрын

I need more details buddy, like what is the latitude, and what are values of the longitude:)

@manjeetrathore6409 4 жыл бұрын

@@SteeringMarinersA- 39•S 20•W B-40•S 142•E

@manjeetrathore6409 4 жыл бұрын

@@SteeringMariners ????????????????

@SteeringMariners 4 жыл бұрын

@@manjeetrathore6409 Initial Course is South East

@manjeetrathore6409 4 жыл бұрын

@@SteeringMariners okay thank you sir

@jimmassey7513 11 ай бұрын

Should show actual course from the example coordinates and how you get that course, not some arbitrary internal angle.

@hariompandey518 2 ай бұрын

Very nice 👍

@tarekwaleed4743 3 жыл бұрын

When I transfer from initial course to final course ?

@hi6747 3 жыл бұрын

using north magnetic pole is necessary, isn't it?

@SteeringMariners 3 жыл бұрын

the choice of pole will depend on the latitude of greater value. If you have a South latitude which has a greater value than North, then you have to choose the South Pole.

@parmeshwartiwari4211 3 жыл бұрын

Sir What if final value like CosB = 110