An example of using the Lagrangian to find the equation of motion for a system.
Пікірлер: 29
@RexGalilae8 жыл бұрын
I'm still in 12th grade and I think your excellent way of teaching is directed at someone who's in his first year of calculus. It's hard to get confused on any part of your video due to the high amount of emphasis on detail. Keep up the great work!^_^
@vegeta94x9 жыл бұрын
Brilliant video! Thanks a lot for taking the time and effort to make such great videos. You make complex material easy to understand. Using different colours makes everything even more clear.
@Animegamernerd19 жыл бұрын
Edward Xavier I agree with you bro the colors were colorful bro. This guy so much better than my prof. He cant teach and he marks like a mad man. I made a decimal error he gave me one mark. :(
@sg48639 жыл бұрын
You forgot a minus in the last line...
@karimkhan13128 жыл бұрын
i am addicted to u r lectures - i see again and again
@benjamincordes2079 жыл бұрын
Thanks for sharing this. Great explanations and very clear.
@Chr0nalis10 жыл бұрын
Nice explanation , thanks
@nilaksh0075 жыл бұрын
Really good.
@PhysicsHelps11 жыл бұрын
Ah, thank you. I'll add a note. Good catch!
@wadiesama7 жыл бұрын
Thank You Very Much, you Are Better Than my Teacher
@inox1ck6 жыл бұрын
2:00 The length of a full circle is 2πl so l•θ is a length of a segment of θ radians.
@RSP1311 жыл бұрын
Thank YOU
@sanjayregmi49088 жыл бұрын
@PhysicsHelps r u taking QFT by any chance?
@khanTatifur8 жыл бұрын
The positive sign in the last line is absolutely correct if you consider downward positive. For that you must consider the potential energy to be negative.
@ernestschoenmakers81814 жыл бұрын
Not true must be negative because gravity is a restoring force in this case.
@AwesomeAngryBiker5 жыл бұрын
At 7:00 should the Euler Lagrange eqn be the opposite way around?
@kennyimammahardika38685 жыл бұрын
It's the same. If a-b=0, then b-a=0
@karimkhan13128 жыл бұрын
i wish i can meet u sir
@ultimatequantumguy31316 жыл бұрын
Quick question: Is there any way of finding an equation describing the motion with respect to time from that equation which is left at the end? (As in one of the form theta = f(t))
@PhysicsHelps6 жыл бұрын
Yes. It's a differential equation. The quintessential physicist's method for solving differential equations is to guess that it's an exponential and then work out what some constants should be. This one ends up being sinusoidal (i.e., the real part of an exponential with an imaginary number in the exponent).
@ultimatequantumguy31316 жыл бұрын
Thanks! Are there similar solutions for most ODEs, or is this a special case for having a solution?
@PhysicsHelps6 жыл бұрын
Exponential solutions (including oscillatory ones) are pretty common in physics scenarios. To be honest with you, my approach to differential equations is to guess an exponential solution, and if that doesn't work, I go to wolfram alpha.
@ultimatequantumguy31316 жыл бұрын
Thanks so much for all your help, it's really appreciated! I have seriously fallen in love with this Lagrangian!
@JoonasD610 жыл бұрын
I like the part where he says "Right?"
@RSP1311 жыл бұрын
In the latter passage would not be: (-1) * g/l *sin(teta) ?
@ernestschoenmakers81814 жыл бұрын
Yes and for small angles sin0 = 0.
@naturematters083 жыл бұрын
@12:29 there (theta)double-dot should be -(g/l)sin(theta). but you wrote (theta) double-dot equals +(g/l) sin(theta)
@LJpoz6 жыл бұрын
Thank you for help it's really helpful video man. SUBSCRIPTION
@MrGian915 жыл бұрын
good videos but sometimes you make too many mistakes and it gets a bit confusing, you should try writing the equations before.