show a self-looping system in the kilowatt range and discribe it with a circuit and data so people can replicate. It must be an ether extracting system like an heat pump but for electricity. See how long this data/ifno will be on youtube after video is posted ;) 10 minutes?

@@zekeriasvarg530 I want to see any practical overunity please

@@motobacktoconstitution4138 teslas tower. The earth is a capacitor with the ground negatively charged. That means that for every electron that goes to ground nature have to pay with energy. That energy can be extracted as Tesla did with his tower. The idea is like the heat pump on your house, but instead of making a cold sink outside the use of induction puts an very high plus charge on the coils upper sphere. The energy stored in the negatively charged ground therefore will do electrostatic work by repulsion towards you induced plus pole. In that way you will have energy out in the primary. The problems with this construction is that you have to ground your tower very well. The bankers hated this idea anyhow so they blowed the tower to peaces. Thunderbolts project demonstrated under safire a birkeland terella putting out plenty of energy från hydrogen plasma spinning an anode in thin atmosphere. Same principle as in the suns corona. Simpler ideas exist and the guy to ask about this is "Peter Storm" or Broström the guy that started the sweden free party movement. He talks very much about free energy technology as he wants the sheeple to become free and independent.

@@zekeriasvarg530I want to be free & independent JFK said that too. thank you very interesting repry sir🙏. I typed Peter Storm Brostrom , Elvis came up I couldnt find him

@@motobacktoconstitution4138 he is a controlled opposition shill with a big wallet. The elite uses their inbreads to control the public arena. You will find very many free E tech if you study the shills and what they cover for.

actually I already have free energy. I am now in the process in converting it into free usable electic power

Thank you Eric Fontaine

Happy to share ;)

If you need help, just ask.

thanks

Not NICE but SUPERB !? LOL ; ) (ASAP as I can will donate !)

sounds incredible, can you show us?

@@MasterIvo Yes I will try to upload a short vid showing it. I made a mistake though: the series bifilar was the one with ~80khz resonance. The parallel bifilar didn't pick up anything after the fix. I accidentally coupled the coil as a monofilar and shorted the other pair thats why it had response to the primary coil. Silly me. I knew it wasn't right. But my point still stands. Obviously the lower resonance has to do with the internal capacitance of the coil but this would mean nanofarads of capacitance and millihenrys of inductance which is large for an air core. I will post another comment If I have records. I checked if this wasn't just a very low harmonic, all other harmonics were lower in voltage. Another interesting thing is that tesla bifilar (series) coil rings at the fundamental frequency (80k) even if I sweep down or up. On the oscilloscope the waveform shape clearly stays 80khz but made up from the input frequency, just like a carrier wave in radio transmission. I used a hair thin wire coil with only 10 or so turns with the function generator as input. If I put higher and higher capacitors in parellel the lower the output voltage goes. But with 1uF I could pull it down to around 3.0 - 3.5kHz! Even ferrite transformers can work at this range. I'm thinking about completely doing away with the resonant primary and feeding the bifilar as the extra coil from a normal ferrite transformer like this guy did: highvoltageforum.net/index.php?topic=218.0 This way I can have higher coupling just as Tesla in his later experiments used an inductor to raise voltage that is not inductively coupled to raise voltage (like modern boost converters using inductive kickback. The downside is that a bifilar's insulation cannot withstand very high voltages as the potential across turns is half the overall voltage. Sorry for the long text, I had to explain everything.

Almost there

I think your right. but this is only an (important) detail in the whole system. what would happen, if the resonant sine was loaded down, and the parallel capacitor was less charged. then the series capacitor would have a larger voltage than the parallel capacitor. Think about what this discharge would do.

Self capacity, can you explain more? When the coils are stacked, they can act as capacitor plates.

Maybe "self capacity" was not enough exact. What I mean is when both wire of the bifilar coil are disconnected, you get more capacity side by side than one on top of the other one (even if in the last case you had more than twice the surface. We say that picture worth million words so here is some pictures that I just took: 1) one wire over the other other wire: preview.ibb.co/kUwTic/one_on_the_top_of_the_other.jpg 2) Wires side by side (with half the surface area compare to #1): image.ibb.co/hEZQUH/side_by_side.jpg Does it make sense what I mean now?

Yes I understand now, thanks for the pictures. the capacitance has increased, but at the cost of inductance? (less windings). The coil with the lowest resonant frequency would be the winner in my opinion. And if you measure inductance and the resonant frequency, you can calculate the capacitance without disconnecting the windings.

@@MasterIvo Hi Ivo, thank you very much for your valuable work! I don't know how you measure the high frequency currents? I only measure all currents indirectly via a low-resistance ohmic resistor using a differential probe and go to a digital oscilloscope with the signal. This is the only way to get correct values. Other measuring methods often showed an overunity that was not there.

old video, can't remember

Many have aaked this. But I didn't measure and moved on. I do intend to do a proper power measurement in a future video. Since I work so high in frequency I want to rectify it to dc. But even that seems problematic. So first some innovation needed. I do remember this test being unloaded. It's a resonant energy gain, not a power gain.

@@MasterIvo : Thanks for the reply Ivo, if it's the voltage gain you are after the resonance path is the way. However be careful with the idea of "energy gain and not power gain" as you may be aware from basics Energy = Power / Time equation and that the only time the "Voltage squared" term comes into play is when there is a resisive load involved, ie you have a voltage across a resistor which sets the power according to: P = V^2/R. Now if you combine this with the energy equation above you get: E = P/t = (V^2/R)/t Which basically says that the Power and Energy in the circuit are related and not independent of each other.

Also since my background is in electronics, I would be interested in a more detailed circuit of your test set up - that is assuming you are interested in others replicating your experiment. Been going over your schematic in the video but found it a bit difficult with section involving the 10nF cap in parallel with the coil, mainly the fact that there is no DC applied to the MOSFET, i.e. the Drain Terminal is tied to ground for DC vie the coil. The results you show suggest that there is more to it than what I see in the schematic, i.e. the timing of everything may have to be taken into account. For myself, I prefer pure schematics, eg actual MOSFET symbols and no blocks unless it is supposed to be a "system" or a block diagram. These methods are usually easier to follow and understand - for me anyway. Hope I'm not being too picky about this.

@@markg1051 I am interested in replication, but have moved on beyond this circuit. This was part of a learning process. Now working with series resonance. The resonant energy can be calculated by calculating the energy stored in the capacitance of the coil/capacitor when its max voltage. That's why I refer to the voltage squared. It's hard to keep it clear and simple at the same time. But I do my best. I hope the circuit I'm working on now will be replicated. And I will do my best to make that circuit very clear.

You can couple them magnetically when placing them parallel, indeed. iron is to slow you need MnZn ferrite to increase inductance. but to find a disk that fits...

Master Ivo yeah finding appropriate material can be rough. What happened when they are inducing to each other in series? Throws off the resonance ?

in series you only have magnetic coupling, the dielectric field isn't used properly

Master Ivo what if the coils run opposite of each other?

Use aluminum. You will be amazed at what happens. ;)

You might be right, it's an older experiment, and I left this behind. It is part of my research, but I went another direction (Tesla's Radiant energy).

Phew! I was almost confused there one moment. Thanks. I've seen this before, focusing on voltage without considering amps and their relation to total wattage.

Good thanks for asking, how are you? Radiant Circuit is working and published on my channel. now progressing it to the next level.

Study the capacitor properties on the pancake.

I first need to create an output to be able to calculate COP.

It will be 1.

thanks! that's good to hear :D

I really don't know, you'll have to try it yourself. this is an old circuit, I moved on into another setup

I'll take a look

No, I have another solution to the spark gap, instead of disruptive discharging a capacitor, like Tesla did, I discharge a coil, this produces a inductive spike, that is the same energy. the benefit is the coil discharges (magnetic field energy) when the switch opens (instead of the spark gap closing the switch of a capacitor)

ehhhh what?

yep ben ik. PWS? wat is dat? Ik heb er nog nooit een gemaakt, maar heb wel nog een vaag plan om er 1 te bouwen.

A space/time antenna = a spark gap

For charging the phone?

Yes please

full brigde rectifier with uf4007 diodes, capacitor and voltage regulator should do the trick.

Thank you!

the uf4007 are ultrafast diodes, these are needed for the bridge rectifier, because the frequency is higher.

At this time I won't, but in the future I might. I first need to make something worth building. thay works, and helps. For now I do recommend you build the radiant power circuit of my april 2019 video. This is a great learning. tool. I am advancing it into a dual setup, which I will publish in the near future

@@MasterIvo silly question thinking if there is a way to stack these like battery cells with no acid🤔

I tried little bit but failed seems to me it should be possible because people also stack capacitor banks?

@@MasterIvo gees I've been having some wierd set backs the board I used for one of my tests warped for no reason a lot in no time🙄and I learned how to completely demagnatise a magnet by accident when looking at v gate set up😂🤣🤦‍♂️did you know that was a thing now I do it burned out like adding to much power to a light bulb magnets aren't cheap 🙄

I was experimenting on some ways to remove the magnetic bump which worked and than the magnet burned out so now I look silly. Whatever. Full speed forward.

I read he used stroboscopes with his sparks

I don't exactly understand what you are referring to.

As you showed in previous videos, the form of energy itself changes between dielectric and magnetic fields yes? When dielectric filed is greatest amplitude (=max volts) at this time usually the magnetic field is at it's lowest (min ampere). When we divide max volts by min current we get high z value no? In opposite case when dielectric field is lowest and magnetic field is highest, we have situation where min volts divided by max ampere value gives low z value. So in your video here the z value is not constant. So it's very likely not correct to claim the 10V increase corresponds to 100 times more energy. To measure this parameter it needs a slightly different approach. Using scope and your frequency increments 1st measure the upper & lower bandwidth points at the -3dB point or 0.707 of max volts. Then divide the centre frequency at max volts point by the bandwidth (the difference between the upper and lower 0.707 frequencies). The answer will give you the "Q" factor of your circuit. This Q factor is the direct ratio between 'free' energy circulating and energy dissipated in your high Q coils. Then take a non inductive resistor and place it in parallel with your tank circuit, when this resistor loads down the scope voltage to 0.707 of its maximum peak to peak value, then that resistor is dissipating 50% of the energy available in your circuit. From the scope (0.3535 of the peak to peak value) for sine wave, across the resistor gives ability to calculate the energy present from V rms x V rms /R . hope this helps mate.

I was referring to the electric energy stored in the dielectric field. Q=1/2C (V*V) since V(voltage) is squared, 10x10=100. When resonant if the voltage(dielectric field strength) is maximum the current (magnetic field strength) is zero. Dividing by zero gives zero. But Impedance isn't calculated that way. your method only applies when current and voltage are in phase (DC).