This is a video example showing how to calculate the cent of gravity and the center of mass for a simple collection of objects in a uniform gravitational field. That is to say, "g" is the same for every object.
Пікірлер: 29
@megasupercrazybob9 жыл бұрын
Great video. Clear narration and explanation. No extraneous filler, just giving me the information I came for. Keep it up!
@dylicious9 жыл бұрын
Perfect video. Simple, quick, and to the point. 10/10
@NoThrottle3 жыл бұрын
Perfect video. Simple, quick, and to the point. 10/10 (1)
@anaaya31316 жыл бұрын
Thank-you Sir, this helped a lot! ;)
@lluhu8 жыл бұрын
Ok, understood. Now, where would the center of mass of the system be applied IF there would be now an additional weight on the same vertical line as the center of mass found?
@mcrekkr3 жыл бұрын
I've been given a question that is almost exactly like this one only difference is that there diagram only shows the distance from the left edge of the beam (Point A/where to calculate from) to one side of the object then the length of the object and then from the end of the object to the end of the rest of the beam and not the center of the object. Is this only meant to calculate from the left edge of the beam to the center of each object? The way the question was given to me was unfortunately confusing to me.
@V.Z.695 жыл бұрын
Say I take the diagram and state, there is a nail balancing the beam. The nail is in the center of the beam and the beam balances perfectly. Were to put the two buckets to keep the beam steady. How would you set up the equation? X_cm = (mx1+mx2+mx3)/(m1+m2+m3) = 0?
@Jamesisawesome244 ай бұрын
Work out the centre of gravity for each of the two components. Using the distances from 'A' to the centre of the beam then multiply by the weight of the beam. Then from 'A' to the centre of the spacing collar then multiply by the weight of the collar. Now add them together (w1 x d1) + (w2 x d2) =? Once you have added these together, divide by the overall weight of the beam and spacing collar.
@calmmilkshake9041 Жыл бұрын
How did we find the giometrical thingy for the beam?? Is the formula or did we just guess
@Smalls12 жыл бұрын
great video
@Piplip2010bat7 жыл бұрын
Any videos about chemistry? As how you calculate the pH-worth of a substance. :)
@ajnishkumarmehta5667 жыл бұрын
centroid is the geometric center of the body or line (mass less body ) , than how you find Geometric center of Beam because it beam have mass 15kg . ????
@ladybluebusiness84375 жыл бұрын
God Bless you
@warrickjames75276 жыл бұрын
how did you get 4m instead of 5 when its 5m from the 1m on the leftside?
@dirkvanzuijlen19623 жыл бұрын
what if a mass is totally on the left side of th beam at x=0
@majimadavis3602 Жыл бұрын
thankas
@aswitrishu44655 жыл бұрын
Please explain more
@kaila_jenner2 ай бұрын
what if the x1 is not given?
@rajeshdeotare88697 жыл бұрын
thnx sir
@drahcirombina734 жыл бұрын
Where did you get the 1m,3m, and 4m?
@drahcirombina734 жыл бұрын
Please reply please
@IJN_Guy Жыл бұрын
@@drahcirombina73 I know this is two years way too late, but the distances "1m, 3m, and 4m" are in correlation to the beginning/far left-side of the board. In this example, the first weight is 1m from the edge, the center of the board is 3m, and the final weight is 4m from the left-most edge. Hope that makes it easier, if you were still wondering, lol.
@anaadipriyadarshi53172 жыл бұрын
I just looked this to confirm my ans...😏
@leonardolopez-manteca44938 ай бұрын
So center of mass is the same as center of gravity
@aminakai74289 жыл бұрын
guys!! if you want to have fun increase the speed to 2 haha have fun
@niabrown40163 жыл бұрын
everyone saying perfect video, this shit was not clear. How tf did he get 3.0 and 4 meters
@Smalls12 жыл бұрын
in the problem it shows the 4 meter distance from the left edge for the 15kg weight. The 5kg is the weight of the 'uniform' beam (uniform being the key word), so we can infer that the centre of the mass would be in the middle which is half of 6 meters = (3m).
@Smalls12 жыл бұрын
hope that helps
@alexz40062 жыл бұрын
4 meters is given, the distance from the left edge of the beam to the 15 kg object thats why those multiply together in the numerator. This applies for the other objects so you multiply the mass times their distance from the left of the edge in this example. The 3 meters is because the 5 kg beam is uniform and its center is at 3 m since the beam is 6 m long . So you multiply 5kg(3 m) because of the same thing i explained earlier. Everything was well explained you have to work on your analysis