Center of mass / Center of gravity Example Calculation

  Рет қаралды 145,360

mrwaynesclass

mrwaynesclass

10 жыл бұрын

This is a video example showing how to calculate the cent of gravity and the center of mass for a simple collection of objects in a uniform gravitational field. That is to say, "g" is the same for every object.

Пікірлер: 29
@megasupercrazybob
@megasupercrazybob 9 жыл бұрын
Great video. Clear narration and explanation. No extraneous filler, just giving me the information I came for. Keep it up!
@dylicious
@dylicious 9 жыл бұрын
Perfect video. Simple, quick, and to the point. 10/10
@NoThrottle
@NoThrottle 3 жыл бұрын
Perfect video. Simple, quick, and to the point. 10/10 (1)
@anaaya3131
@anaaya3131 6 жыл бұрын
Thank-you Sir, this helped a lot! ;)
@lluhu
@lluhu 8 жыл бұрын
Ok, understood. Now, where would the center of mass of the system be applied IF there would be now an additional weight on the same vertical line as the center of mass found?
@mcrekkr
@mcrekkr 3 жыл бұрын
I've been given a question that is almost exactly like this one only difference is that there diagram only shows the distance from the left edge of the beam (Point A/where to calculate from) to one side of the object then the length of the object and then from the end of the object to the end of the rest of the beam and not the center of the object. Is this only meant to calculate from the left edge of the beam to the center of each object? The way the question was given to me was unfortunately confusing to me.
@V.Z.69
@V.Z.69 5 жыл бұрын
Say I take the diagram and state, there is a nail balancing the beam. The nail is in the center of the beam and the beam balances perfectly. Were to put the two buckets to keep the beam steady. How would you set up the equation? X_cm = (mx1+mx2+mx3)/(m1+m2+m3) = 0?
@Jamesisawesome24
@Jamesisawesome24 4 ай бұрын
Work out the centre of gravity for each of the two components. Using the distances from 'A' to the centre of the beam then multiply by the weight of the beam. Then from 'A' to the centre of the spacing collar then multiply by the weight of the collar. Now add them together (w1 x d1) + (w2 x d2) =? Once you have added these together, divide by the overall weight of the beam and spacing collar.
@calmmilkshake9041
@calmmilkshake9041 Жыл бұрын
How did we find the giometrical thingy for the beam?? Is the formula or did we just guess
@Smalls1
@Smalls1 2 жыл бұрын
great video
@Piplip2010bat
@Piplip2010bat 7 жыл бұрын
Any videos about chemistry? As how you calculate the pH-worth of a substance. :)
@ajnishkumarmehta566
@ajnishkumarmehta566 7 жыл бұрын
centroid is the geometric center of the body or line (mass less body ) , than how you find Geometric center of Beam because it beam have mass 15kg . ????
@ladybluebusiness8437
@ladybluebusiness8437 5 жыл бұрын
God Bless you
@warrickjames7527
@warrickjames7527 6 жыл бұрын
how did you get 4m instead of 5 when its 5m from the 1m on the leftside?
@dirkvanzuijlen1962
@dirkvanzuijlen1962 3 жыл бұрын
what if a mass is totally on the left side of th beam at x=0
@majimadavis3602
@majimadavis3602 Жыл бұрын
thankas
@aswitrishu4465
@aswitrishu4465 5 жыл бұрын
Please explain more
@kaila_jenner
@kaila_jenner 2 ай бұрын
what if the x1 is not given?
@rajeshdeotare8869
@rajeshdeotare8869 7 жыл бұрын
thnx sir
@drahcirombina73
@drahcirombina73 4 жыл бұрын
Where did you get the 1m,3m, and 4m?
@drahcirombina73
@drahcirombina73 4 жыл бұрын
Please reply please
@IJN_Guy
@IJN_Guy Жыл бұрын
@@drahcirombina73 I know this is two years way too late, but the distances "1m, 3m, and 4m" are in correlation to the beginning/far left-side of the board. In this example, the first weight is 1m from the edge, the center of the board is 3m, and the final weight is 4m from the left-most edge. Hope that makes it easier, if you were still wondering, lol.
@anaadipriyadarshi5317
@anaadipriyadarshi5317 2 жыл бұрын
I just looked this to confirm my ans...😏
@leonardolopez-manteca4493
@leonardolopez-manteca4493 8 ай бұрын
So center of mass is the same as center of gravity
@aminakai7428
@aminakai7428 9 жыл бұрын
guys!! if you want to have fun increase the speed to 2 haha have fun
@niabrown4016
@niabrown4016 3 жыл бұрын
everyone saying perfect video, this shit was not clear. How tf did he get 3.0 and 4 meters
@Smalls1
@Smalls1 2 жыл бұрын
in the problem it shows the 4 meter distance from the left edge for the 15kg weight. The 5kg is the weight of the 'uniform' beam (uniform being the key word), so we can infer that the centre of the mass would be in the middle which is half of 6 meters = (3m).
@Smalls1
@Smalls1 2 жыл бұрын
hope that helps
@alexz4006
@alexz4006 2 жыл бұрын
4 meters is given, the distance from the left edge of the beam to the 15 kg object thats why those multiply together in the numerator. This applies for the other objects so you multiply the mass times their distance from the left of the edge in this example. The 3 meters is because the 5 kg beam is uniform and its center is at 3 m since the beam is 6 m long . So you multiply 5kg(3 m) because of the same thing i explained earlier. Everything was well explained you have to work on your analysis
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